Got Homework?
Connect with other students for help. It's a free community.
Here's the question you clicked on:
 0 viewing
Solve Triangle FGH. Round to the nearest degree.
Picture attached!
 one year ago
 one year ago
Solve Triangle FGH. Round to the nearest degree. Picture attached!
 one year ago
 one year ago

This Question is Closed

janessiaBest ResponseYou've already chosen the best response.0
@jim_thompson5910 can you help me please?
 one year ago

jim_thompson5910Best ResponseYou've already chosen the best response.0
sorry for getting to you so late, you can use the law of cosines to solve for each angle
 one year ago

jim_thompson5910Best ResponseYou've already chosen the best response.0
so for instance, let's say we're solving for angle F (ie finding the measure of angle F) The law of cosines is a^2=b^2+c^22bc*cos(A) where 'a', b and c are the sides of the triangle and angle A is opposite side 'a'. To find angle F, we do this... a^2=b^2+c^22bc*cos(A) (6.3)^2=(5.6)^2+(5.8)^22(5.6)(5.8)*cos(F) 39.69=(5.6)^2+(5.8)^22(5.6)(5.8)*cos(F) 39.69=31.36+(5.8)^22(5.6)(5.8)*cos(F) 39.69=31.36+33.642(5.6)(5.8)*cos(F) 39.69=31.36+33.6411.2(5.8)*cos(F) 39.69=31.36+33.6464.96*cos(F) 39.69=6564.96*cos(F) 39.6965=64.96*cos(F) 25.31=64.96*cos(F) (25.31)/(64.96)=cos(F) 0.389624384236453=cos(F) cos(F)=0.389624384236453 F=arccos(0.389624384236453) F=67.0688704863168 So the angle F is roughly 67.0688704863168 degrees
 one year ago

jim_thompson5910Best ResponseYou've already chosen the best response.0
It's a lot I know, but hopefully you can go through it step by step without too much trouble and make sense of it all You can then use this idea to find angles G and H.
 one year ago
See more questions >>>
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.