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sweett2639
 3 years ago
You're filling a water balloon with a spherical shape. If the water is coming in at 4 cubic inches per second, how fast is the radius changing when the volume is 200 cubic inches? (answer: 0.0241 in/sec)
sweett2639
 3 years ago
You're filling a water balloon with a spherical shape. If the water is coming in at 4 cubic inches per second, how fast is the radius changing when the volume is 200 cubic inches? (answer: 0.0241 in/sec)

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baldymcgee6
 3 years ago
Best ResponseYou've already chosen the best response.1dw:1351471895315:dw

baldymcgee6
 3 years ago
Best ResponseYou've already chosen the best response.1@sweett2639 do you follow?

sweett2639
 3 years ago
Best ResponseYou've already chosen the best response.0\[v= \frac{ 4 }{ 3 } \pi r ^{3}\]i understand that the volume of a sphere is and that\[\frac{ dv }{ dt } = 4 inches ^{3}/\sec\] but not much more than that

baldymcgee6
 3 years ago
Best ResponseYou've already chosen the best response.1dw:1351472335325:dw

sweett2639
 3 years ago
Best ResponseYou've already chosen the best response.0so you set 200 equal to v and moved the equasion around so that r is 3.628

baldymcgee6
 3 years ago
Best ResponseYou've already chosen the best response.1dw:1351472455417:dw

baldymcgee6
 3 years ago
Best ResponseYou've already chosen the best response.1Right, we know that the volume is 200 in^3 at the moment of interest, therefore we can find what the radius of the sphere is at that moment

baldymcgee6
 3 years ago
Best ResponseYou've already chosen the best response.1dw:1351472567598:dw

sweett2639
 3 years ago
Best ResponseYou've already chosen the best response.0everytime i try to calculate r, i get the wrong number

baldymcgee6
 3 years ago
Best ResponseYou've already chosen the best response.1http://www.wolframalpha.com/input/?i=4%2F%284*pi*%283.628%29%5E2%29 just make sure you type it into the calc correctly.
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