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You're filling a water balloon with a spherical shape. If the water is coming in at 4 cubic inches per second, how fast is the radius changing when the volume is 200 cubic inches? (answer: 0.0241 in/sec)
 one year ago
 one year ago
You're filling a water balloon with a spherical shape. If the water is coming in at 4 cubic inches per second, how fast is the radius changing when the volume is 200 cubic inches? (answer: 0.0241 in/sec)
 one year ago
 one year ago

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baldymcgee6Best ResponseYou've already chosen the best response.1
dw:1351471895315:dw
 one year ago

baldymcgee6Best ResponseYou've already chosen the best response.1
@sweett2639 do you follow?
 one year ago

sweett2639Best ResponseYou've already chosen the best response.0
\[v= \frac{ 4 }{ 3 } \pi r ^{3}\]i understand that the volume of a sphere is and that\[\frac{ dv }{ dt } = 4 inches ^{3}/\sec\] but not much more than that
 one year ago

baldymcgee6Best ResponseYou've already chosen the best response.1
dw:1351472335325:dw
 one year ago

sweett2639Best ResponseYou've already chosen the best response.0
so you set 200 equal to v and moved the equasion around so that r is 3.628
 one year ago

baldymcgee6Best ResponseYou've already chosen the best response.1
dw:1351472455417:dw
 one year ago

baldymcgee6Best ResponseYou've already chosen the best response.1
Right, we know that the volume is 200 in^3 at the moment of interest, therefore we can find what the radius of the sphere is at that moment
 one year ago

baldymcgee6Best ResponseYou've already chosen the best response.1
dw:1351472567598:dw
 one year ago

sweett2639Best ResponseYou've already chosen the best response.0
everytime i try to calculate r, i get the wrong number
 one year ago

baldymcgee6Best ResponseYou've already chosen the best response.1
http://www.wolframalpha.com/input/?i=4%2F%284*pi*%283.628%29%5E2%29 just make sure you type it into the calc correctly.
 one year ago
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