A community for students. Sign up today!
Here's the question you clicked on:
 0 viewing
Tresag
 2 years ago
simplify to the lowest terms
16a^2/4a+11b121b^2/4a+11b
Tresag
 2 years ago
simplify to the lowest terms 16a^2/4a+11b121b^2/4a+11b

This Question is Closed

gaara438125
 2 years ago
Best ResponseYou've already chosen the best response.1\[\frac{ 16a^2 }{ 4a + 11 }  \frac{ 121b^2 }{ 4a + 11b }\] i'm guessing you meant that?

gaara438125
 2 years ago
Best ResponseYou've already chosen the best response.1find an LCD which in this case is?

Tresag
 2 years ago
Best ResponseYou've already chosen the best response.0i don't know...nothing goes into 121

gaara438125
 2 years ago
Best ResponseYou've already chosen the best response.1the LCD is least common denominator, so the left fraction's denominator is the same as the right 4a + 11b is the LCD

Tresag
 2 years ago
Best ResponseYou've already chosen the best response.0so how do I find the lowest term ?

Tresag
 2 years ago
Best ResponseYou've already chosen the best response.0is the answer 105/4a+11b ?

gaara438125
 2 years ago
Best ResponseYou've already chosen the best response.1since the right side's denominator is already 4a + 11b we have to multiply the left sides to look like that as well we're missing a B so we multiply the numerator and denominator by B/B so it now looks like \[\frac{ 16a^2b }{ 4a + 11b }  \frac{ 121b^2 }{ 4a + 11b }\]

gaara438125
 2 years ago
Best ResponseYou've already chosen the best response.1\[\frac{ 16a^2  121b^2 }{ 4a + 11b }\]
Ask your own question
Ask a QuestionFind more explanations on OpenStudy
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.