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Tresag

  • 3 years ago

simplify to the lowest terms 16a^2/4a+11b-121b^2/4a+11b

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  1. gaara438125
    • 3 years ago
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    \[\frac{ 16a^2 }{ 4a + 11 } - \frac{ 121b^2 }{ 4a + 11b }\] i'm guessing you meant that?

  2. Tresag
    • 3 years ago
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    yes

  3. gaara438125
    • 3 years ago
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    find an LCD which in this case is?

  4. Tresag
    • 3 years ago
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    i don't know...nothing goes into 121

  5. gaara438125
    • 3 years ago
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    the LCD is least common denominator, so the left fraction's denominator is the same as the right 4a + 11b is the LCD

  6. Tresag
    • 3 years ago
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    ok

  7. Tresag
    • 3 years ago
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    so how do I find the lowest term ?

  8. Tresag
    • 3 years ago
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    is the answer 105/4a+11b ?

  9. gaara438125
    • 3 years ago
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    since the right side's denominator is already 4a + 11b we have to multiply the left sides to look like that as well we're missing a B so we multiply the numerator and denominator by B/B so it now looks like \[\frac{ 16a^2b }{ 4a + 11b } - \frac{ 121b^2 }{ 4a + 11b }\]

  10. gaara438125
    • 3 years ago
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    \[\frac{ 16a^2 - 121b^2 }{ 4a + 11b }\]

  11. Tresag
    • 3 years ago
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    ok

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