anonymous
  • anonymous
Find dy/dx if y= tan9x/x^2
Mathematics
katieb
  • katieb
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anonymous
  • anonymous
All you have to do is derivative tan9x/x². Do you know how to? No?
anonymous
  • anonymous
I thought I did.. and then I did it wrong on the test. I use the product rule but I didnt follow through correctly.
anonymous
  • anonymous
Do you know quotient rule?

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anonymous
  • anonymous
Yes, that's what I meant, I tried to do that and I didn't know what to do with the tan9x? I can't use it as a constant or I tried to put it outside like 9tanx and it came out wrong
anonymous
  • anonymous
Well, actually, to derivative the numeration, you have to use chain rule, you know what it is and how to apply it, right?
anonymous
  • anonymous
I know what it is just no how to use it here. Would it be 1 times 9?
anonymous
  • anonymous
For chain rule, we know that \[\frac{d}{dx}f(g(x)) = f'(g(x)) \cdot g'(x)\]Derivative first function and left second function untouched then derivative second function. Let f(x) be tanx and g(x) be 9x. Do you know what to do next?
anonymous
  • anonymous
No. I don't
anonymous
  • anonymous
First, we derivative tan(9x). We only need to derivative tan and left 9x untouched. Is this clear?
anonymous
  • anonymous
Okay, yes.so then I have that - tan9xtimes 2x
anonymous
  • anonymous
Thank you for your help but at this point I just can't do this.
anonymous
  • anonymous
Don't say you can't, you can do it! Just derivative the numerator first. Now, what is derivative of tanx?
anonymous
  • anonymous
sec^2x
anonymous
  • anonymous
|dw:1351472593435:dw|

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