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ERoseM

  • 2 years ago

Find dy/dx if y= tan9x/x^2

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  1. micahwood50
    • 2 years ago
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    All you have to do is derivative tan9x/x². Do you know how to? No?

  2. ERoseM
    • 2 years ago
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    I thought I did.. and then I did it wrong on the test. I use the product rule but I didnt follow through correctly.

  3. micahwood50
    • 2 years ago
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    Do you know quotient rule?

  4. ERoseM
    • 2 years ago
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    Yes, that's what I meant, I tried to do that and I didn't know what to do with the tan9x? I can't use it as a constant or I tried to put it outside like 9tanx and it came out wrong

  5. micahwood50
    • 2 years ago
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    Well, actually, to derivative the numeration, you have to use chain rule, you know what it is and how to apply it, right?

  6. ERoseM
    • 2 years ago
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    I know what it is just no how to use it here. Would it be 1 times 9?

  7. micahwood50
    • 2 years ago
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    For chain rule, we know that \[\frac{d}{dx}f(g(x)) = f'(g(x)) \cdot g'(x)\]Derivative first function and left second function untouched then derivative second function. Let f(x) be tanx and g(x) be 9x. Do you know what to do next?

  8. ERoseM
    • 2 years ago
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    No. I don't

  9. micahwood50
    • 2 years ago
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    First, we derivative tan(9x). We only need to derivative tan and left 9x untouched. Is this clear?

  10. ERoseM
    • 2 years ago
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    Okay, yes.so then I have that - tan9xtimes 2x

  11. ERoseM
    • 2 years ago
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    Thank you for your help but at this point I just can't do this.

  12. micahwood50
    • 2 years ago
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    Don't say you can't, you can do it! Just derivative the numerator first. Now, what is derivative of tanx?

  13. ERoseM
    • 2 years ago
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    sec^2x

  14. ERoseM
    • 2 years ago
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    |dw:1351472593435:dw|

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