anonymous
  • anonymous
Please help! A rocket of mass 1.0x10^3kg is being fired to a height of 5.0 x 10^3 m. The rocket engine shuts off when the rocket reaches a height of 1.0x10^3m, and the rocket coasts up to 5.0 x 10^3 m. A) What velocity must the rocket have at the 1.0x10^3 m point to enable it to reach 5.0 x 10^3m B) What acceleration did the rocket experience while the engine was on? off? C) What force did the rocket engine exert on the rocket?
Physics
  • Stacey Warren - Expert brainly.com
Hey! We 've verified this expert answer for you, click below to unlock the details :)
SOLVED
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.
jamiebookeater
  • jamiebookeater
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
anonymous
  • anonymous
Strategy: Part A) Assuming rocket stops at 5.0x10^3m, use \(v^2=v_0^2-2gy\) where y is the rest of travelling distance, (5.0-1.0)x10^3m. Part B) While on: The rocket must reach velocity in a from rest at a distance 1.0x10^3m. Again, use \(v^2=v_0^2-2gy\). While off: Simply \(g\). Part C) Newtons famous \(\Sigma F=ma\) where a is the one you found in Part B).
anonymous
  • anonymous
Thank you very much! Fanned and medaled!
anonymous
  • anonymous
I got a question what is that v in the equation after the equals? is that 2/0?

Looking for something else?

Not the answer you are looking for? Search for more explanations.

More answers

anonymous
  • anonymous
Tell me if im right and please fill in that variable i dont know: 1)V^2=? - 2(-9.8)(4.0x10^3) 2)V^2=? - 2(-9.8)(1.0x10^3) B) 9.8m/s^2 3) (1.0x10^3) x whatever i get from 2a?
anonymous
  • anonymous
1 V=0; ?= v you're looking for 2 v = the one found in 1; ? = 0

Looking for something else?

Not the answer you are looking for? Search for more explanations.