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anonymous
 3 years ago
Please help!
A rocket of mass 1.0x10^3kg is being fired to a height of 5.0 x 10^3 m. The rocket engine shuts off when the rocket reaches a height of 1.0x10^3m, and the rocket coasts up to 5.0 x 10^3 m.
A) What velocity must the rocket have at the 1.0x10^3 m point to enable it to reach 5.0 x 10^3m
B) What acceleration did the rocket experience while the engine was on? off?
C) What force did the rocket engine exert on the rocket?
anonymous
 3 years ago
Please help! A rocket of mass 1.0x10^3kg is being fired to a height of 5.0 x 10^3 m. The rocket engine shuts off when the rocket reaches a height of 1.0x10^3m, and the rocket coasts up to 5.0 x 10^3 m. A) What velocity must the rocket have at the 1.0x10^3 m point to enable it to reach 5.0 x 10^3m B) What acceleration did the rocket experience while the engine was on? off? C) What force did the rocket engine exert on the rocket?

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anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0Strategy: Part A) Assuming rocket stops at 5.0x10^3m, use \(v^2=v_0^22gy\) where y is the rest of travelling distance, (5.01.0)x10^3m. Part B) While on: The rocket must reach velocity in a from rest at a distance 1.0x10^3m. Again, use \(v^2=v_0^22gy\). While off: Simply \(g\). Part C) Newtons famous \(\Sigma F=ma\) where a is the one you found in Part B).

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0Thank you very much! Fanned and medaled!

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0I got a question what is that v in the equation after the equals? is that 2/0?

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0Tell me if im right and please fill in that variable i dont know: 1)V^2=?  2(9.8)(4.0x10^3) 2)V^2=?  2(9.8)(1.0x10^3) B) 9.8m/s^2 3) (1.0x10^3) x whatever i get from 2a?

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.01 V=0; ?= v you're looking for 2 v = the one found in 1; ? = 0
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