A rocket of mass 1.0x10^3kg is being fired to a height of 5.0 x 10^3 m. The rocket engine shuts off when the rocket reaches a height of 1.0x10^3m, and the rocket coasts up to 5.0 x 10^3 m.
A) What velocity must the rocket have at the 1.0x10^3 m point to enable it to reach 5.0 x 10^3m
B) What acceleration did the rocket experience while the engine was on? off?
C) What force did the rocket engine exert on the rocket?
Stacey Warren - Expert brainly.com
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Assuming rocket stops at 5.0x10^3m, use \(v^2=v_0^2-2gy\) where y is the rest of travelling distance, (5.0-1.0)x10^3m.
While on: The rocket must reach velocity in a from rest at a distance 1.0x10^3m. Again, use \(v^2=v_0^2-2gy\).
While off: Simply \(g\).
Newtons famous \(\Sigma F=ma\) where a is the one you found in Part B).
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I got a question what is that v in the equation after the equals? is that 2/0?