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Isaac is looking through binoculars on a whale watching trip when he notices a sea otter in the distance. If he is 20 feet above sea level in the boat, and the angle of depression is 30 degrees, how far away from the boat is the otter (to the nearest foot)?

Mathematics
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hello are you there? do u think you can draw this first before you can solve?
@ janessia
hmm idk

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Other answers:

how would i draw it?
do you know the angle of depression?
|dw:1351530728427:dw|
the height y=20 , the x= distance angle theta = angle of depression
so how do i solve this?
|dw:1351530990457:dw|
you can try tangent
opposite hypotenuse?
opposite adjacent
?
sorry my pc got frozen,,, yes try that tangent
let me know what you getting
\[\tan \theta =\frac{ 20 }{ x } ,......\] then what is x=?
memorized sin A= opposite/ hypotenuse cos A= adjacent/hypotenuse tan A= opposite/adjacent
ohk but hmmmm??? im so confused
just forget it its fine
\[\tan \theta =\frac{ 20 }{ x }\] so here we want x, therefore multiply both sides by x, to get \[xtan \theta =\frac{ 20 }{ x }.x\] \[x \tan \theta =20\] divide both sides by tan o gives \[\frac{ x \tan \theta }{ \tan \theta }=\frac{ 20 }{ \tan \theta } \] w/c gives \[x=\frac{ 20 }{ \tan \theta }....\] x=?
did you get it? angle of depression \[\theta =30\]
so x= 20/ tan 30 what did you get?

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