anonymous
  • anonymous
Isaac is looking through binoculars on a whale watching trip when he notices a sea otter in the distance. If he is 20 feet above sea level in the boat, and the angle of depression is 30 degrees, how far away from the boat is the otter (to the nearest foot)?
Mathematics
chestercat
  • chestercat
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anonymous
  • anonymous
hello are you there? do u think you can draw this first before you can solve?
anonymous
  • anonymous
@ janessia
anonymous
  • anonymous
hmm idk

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anonymous
  • anonymous
how would i draw it?
anonymous
  • anonymous
do you know the angle of depression?
anonymous
  • anonymous
|dw:1351530728427:dw|
anonymous
  • anonymous
the height y=20 , the x= distance angle theta = angle of depression
anonymous
  • anonymous
so how do i solve this?
anonymous
  • anonymous
|dw:1351530990457:dw|
anonymous
  • anonymous
you can try tangent
anonymous
  • anonymous
opposite hypotenuse?
anonymous
  • anonymous
opposite adjacent
anonymous
  • anonymous
?
anonymous
  • anonymous
sorry my pc got frozen,,, yes try that tangent
anonymous
  • anonymous
let me know what you getting
anonymous
  • anonymous
\[\tan \theta =\frac{ 20 }{ x } ,......\] then what is x=?
anonymous
  • anonymous
memorized sin A= opposite/ hypotenuse cos A= adjacent/hypotenuse tan A= opposite/adjacent
anonymous
  • anonymous
ohk but hmmmm??? im so confused
anonymous
  • anonymous
just forget it its fine
anonymous
  • anonymous
\[\tan \theta =\frac{ 20 }{ x }\] so here we want x, therefore multiply both sides by x, to get \[xtan \theta =\frac{ 20 }{ x }.x\] \[x \tan \theta =20\] divide both sides by tan o gives \[\frac{ x \tan \theta }{ \tan \theta }=\frac{ 20 }{ \tan \theta } \] w/c gives \[x=\frac{ 20 }{ \tan \theta }....\] x=?
anonymous
  • anonymous
did you get it? angle of depression \[\theta =30\]
anonymous
  • anonymous
so x= 20/ tan 30 what did you get?

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