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swin2013
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\[\ln(\cos(w-1))\]
calculusfunctions
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To take the derivative of the natural logarithm function, divide the derivative of the argument function by the argument function. Thus\[\frac{ d(\ln f(x)) }{ x }=\frac{ f \prime(x) }{ f(x) }\]Do you understand?
swin2013
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so it's 1/cos(w-1) * -sin(w-1) *1?
calculusfunctions
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Sorry, that should be dx in the first denominator.
calculusfunctions
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\[\frac{ d(\ln (\cos (w -1)) }{ dx }=\frac{ -\sin (w -1) }{ \cos (w -1) }=-\tan (w -1)\]Understand?
calculusfunctions
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@swin2013 I asked if you understood.
swin2013
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yes i do sorry, i was working on another problem :)
calculusfunctions
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No worries!