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precal Group TitleBest ResponseYou've already chosen the best response.0
dw:1351476871325:dw
 2 years ago

precal Group TitleBest ResponseYou've already chosen the best response.0
don't I need to use some formula?
 2 years ago

zepdrix Group TitleBest ResponseYou've already chosen the best response.0
So is the question, "Does the series converge?" ? :o
 2 years ago

precal Group TitleBest ResponseYou've already chosen the best response.0
yes, I know it converges to 9/4
 2 years ago

precal Group TitleBest ResponseYou've already chosen the best response.0
doesn't help that I don't know why?
 2 years ago

precal Group TitleBest ResponseYou've already chosen the best response.0
dw:1351477345222:dw
 2 years ago

precal Group TitleBest ResponseYou've already chosen the best response.0
dw:1351477381056:dw
 2 years ago

zepdrix Group TitleBest ResponseYou've already chosen the best response.0
dw:1351477186152:dw Hmm can't you do some type of comparison test? Sorry I'm a little rusty with these :D We know that the pseries 1/n^2 converses, and our series is smaller than that one :O something like that..
 2 years ago

precal Group TitleBest ResponseYou've already chosen the best response.0
dw:1351477424396:dw
 2 years ago

precal Group TitleBest ResponseYou've already chosen the best response.0
I am as rusty as you
 2 years ago

precal Group TitleBest ResponseYou've already chosen the best response.0
how about if I do this as a telescoping series? as if I know what I am talking about
 2 years ago

zepdrix Group TitleBest ResponseYou've already chosen the best response.0
Yah that's prolly the way to approach it c: try to recognize a pattern coming out of it.
 2 years ago

precal Group TitleBest ResponseYou've already chosen the best response.0
I know if I factor out the 9 and then I just need to create the (1/4)
 2 years ago

zepdrix Group TitleBest ResponseYou've already chosen the best response.0
Oh oh oh i think it's coming back to me a little bit... I think in order to write it as a telescoping series, we need to rewrite it as partial fractions, then we'll get terms being subtracted in each n, allowing for some cancellations probably.
 2 years ago

zepdrix Group TitleBest ResponseYou've already chosen the best response.0
dw:1351478870156:dw
 2 years ago

zepdrix Group TitleBest ResponseYou've already chosen the best response.0
dw:1351479010862:dw
 2 years ago

colorful Group TitleBest ResponseYou've already chosen the best response.0
dw:1351479486392:dw
 2 years ago

zepdrix Group TitleBest ResponseYou've already chosen the best response.0
oh sorry XD hehe
 2 years ago

precal Group TitleBest ResponseYou've already chosen the best response.0
sorry, I ran off to watch some youtube videos on this
 2 years ago

zepdrix Group TitleBest ResponseYou've already chosen the best response.0
Mmmm that's prolly a good idea :) I don't think I'm getting anywhere with this one lol
 2 years ago

precal Group TitleBest ResponseYou've already chosen the best response.0
dw:1351479960238:dwgot this as well
 2 years ago

precal Group TitleBest ResponseYou've already chosen the best response.0
dw:1351480090695:dw
 2 years ago

colorful Group TitleBest ResponseYou've already chosen the best response.0
the next few terms are something like (1/81/5+1/12)+(1/101/6+1/14)
 2 years ago

precal Group TitleBest ResponseYou've already chosen the best response.0
I thought somehow we would be left with 1/4 as the first term then it would make sense that they solution is 9/4
 2 years ago

precal Group TitleBest ResponseYou've already chosen the best response.0
wonder if we messed up on the partial fraction
 2 years ago

colorful Group TitleBest ResponseYou've already chosen the best response.0
I don't think so
 2 years ago

zepdrix Group TitleBest ResponseYou've already chosen the best response.0
Ummm I doubt it, it's likely that the terms just cancel out in a strange way :D
 2 years ago

precal Group TitleBest ResponseYou've already chosen the best response.0
well that is good to know
 2 years ago

precal Group TitleBest ResponseYou've already chosen the best response.0
yes, wonder if we have to do more than the first three terms to see it
 2 years ago

zepdrix Group TitleBest ResponseYou've already chosen the best response.0
dw:1351480321431:dw
 2 years ago

precal Group TitleBest ResponseYou've already chosen the best response.0
dw:1351480632232:dw
 2 years ago

precal Group TitleBest ResponseYou've already chosen the best response.0
ok that is all I see right now
 2 years ago

zepdrix Group TitleBest ResponseYou've already chosen the best response.0
nasty little problem :3
 2 years ago

precal Group TitleBest ResponseYou've already chosen the best response.0
yes, well I think I will sleep on it, would not be the first time I went to bed with an unsolved problem....thanks..........
 2 years ago

precal Group TitleBest ResponseYou've already chosen the best response.0
dw:1351531637965:dwok I think I solved it @zepdrix
 2 years ago

zepdrix Group TitleBest ResponseYou've already chosen the best response.0
Hmmmmmm that doesn't quite look right <:o you can't split up the base of a fraction. \[\frac{ 1 }{ 2n+4 }=\frac{ 1 }{ \infty+4 }=0\]
 2 years ago

zepdrix Group TitleBest ResponseYou've already chosen the best response.0
dw:1351531992905:dw
 2 years ago