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precal Group TitleBest ResponseYou've already chosen the best response.0
dw:1351476871325:dw
 one year ago

precal Group TitleBest ResponseYou've already chosen the best response.0
don't I need to use some formula?
 one year ago

zepdrix Group TitleBest ResponseYou've already chosen the best response.0
So is the question, "Does the series converge?" ? :o
 one year ago

precal Group TitleBest ResponseYou've already chosen the best response.0
yes, I know it converges to 9/4
 one year ago

precal Group TitleBest ResponseYou've already chosen the best response.0
doesn't help that I don't know why?
 one year ago

precal Group TitleBest ResponseYou've already chosen the best response.0
dw:1351477345222:dw
 one year ago

precal Group TitleBest ResponseYou've already chosen the best response.0
dw:1351477381056:dw
 one year ago

zepdrix Group TitleBest ResponseYou've already chosen the best response.0
dw:1351477186152:dw Hmm can't you do some type of comparison test? Sorry I'm a little rusty with these :D We know that the pseries 1/n^2 converses, and our series is smaller than that one :O something like that..
 one year ago

precal Group TitleBest ResponseYou've already chosen the best response.0
dw:1351477424396:dw
 one year ago

precal Group TitleBest ResponseYou've already chosen the best response.0
I am as rusty as you
 one year ago

precal Group TitleBest ResponseYou've already chosen the best response.0
how about if I do this as a telescoping series? as if I know what I am talking about
 one year ago

zepdrix Group TitleBest ResponseYou've already chosen the best response.0
Yah that's prolly the way to approach it c: try to recognize a pattern coming out of it.
 one year ago

precal Group TitleBest ResponseYou've already chosen the best response.0
I know if I factor out the 9 and then I just need to create the (1/4)
 one year ago

zepdrix Group TitleBest ResponseYou've already chosen the best response.0
Oh oh oh i think it's coming back to me a little bit... I think in order to write it as a telescoping series, we need to rewrite it as partial fractions, then we'll get terms being subtracted in each n, allowing for some cancellations probably.
 one year ago

zepdrix Group TitleBest ResponseYou've already chosen the best response.0
dw:1351478870156:dw
 one year ago

zepdrix Group TitleBest ResponseYou've already chosen the best response.0
dw:1351479010862:dw
 one year ago

colorful Group TitleBest ResponseYou've already chosen the best response.0
dw:1351479486392:dw
 one year ago

zepdrix Group TitleBest ResponseYou've already chosen the best response.0
oh sorry XD hehe
 one year ago

precal Group TitleBest ResponseYou've already chosen the best response.0
sorry, I ran off to watch some youtube videos on this
 one year ago

zepdrix Group TitleBest ResponseYou've already chosen the best response.0
Mmmm that's prolly a good idea :) I don't think I'm getting anywhere with this one lol
 one year ago

precal Group TitleBest ResponseYou've already chosen the best response.0
dw:1351479960238:dwgot this as well
 one year ago

precal Group TitleBest ResponseYou've already chosen the best response.0
dw:1351480090695:dw
 one year ago

colorful Group TitleBest ResponseYou've already chosen the best response.0
the next few terms are something like (1/81/5+1/12)+(1/101/6+1/14)
 one year ago

precal Group TitleBest ResponseYou've already chosen the best response.0
I thought somehow we would be left with 1/4 as the first term then it would make sense that they solution is 9/4
 one year ago

precal Group TitleBest ResponseYou've already chosen the best response.0
wonder if we messed up on the partial fraction
 one year ago

colorful Group TitleBest ResponseYou've already chosen the best response.0
I don't think so
 one year ago

zepdrix Group TitleBest ResponseYou've already chosen the best response.0
Ummm I doubt it, it's likely that the terms just cancel out in a strange way :D
 one year ago

precal Group TitleBest ResponseYou've already chosen the best response.0
well that is good to know
 one year ago

precal Group TitleBest ResponseYou've already chosen the best response.0
yes, wonder if we have to do more than the first three terms to see it
 one year ago

zepdrix Group TitleBest ResponseYou've already chosen the best response.0
dw:1351480321431:dw
 one year ago

precal Group TitleBest ResponseYou've already chosen the best response.0
dw:1351480632232:dw
 one year ago

precal Group TitleBest ResponseYou've already chosen the best response.0
ok that is all I see right now
 one year ago

zepdrix Group TitleBest ResponseYou've already chosen the best response.0
nasty little problem :3
 one year ago

precal Group TitleBest ResponseYou've already chosen the best response.0
yes, well I think I will sleep on it, would not be the first time I went to bed with an unsolved problem....thanks..........
 one year ago

precal Group TitleBest ResponseYou've already chosen the best response.0
dw:1351531637965:dwok I think I solved it @zepdrix
 one year ago

zepdrix Group TitleBest ResponseYou've already chosen the best response.0
Hmmmmmm that doesn't quite look right <:o you can't split up the base of a fraction. \[\frac{ 1 }{ 2n+4 }=\frac{ 1 }{ \infty+4 }=0\]
 one year ago

zepdrix Group TitleBest ResponseYou've already chosen the best response.0
dw:1351531992905:dw
 one year ago