A community for students.
Here's the question you clicked on:
 0 viewing
 2 years ago
A system of two block with one frictionless pulley is release. Block one mass 3.00kg sitting on ground, block 2 mass 5.00 kg with a height of 4.00 meter. What is the velocity (speed) of the 5.0kg block in m/s when it strikes the ground. We have been using the conservation of momentum and Kinetic Energy (KE) and Potential Energy (PEg) formulas. ow do I set this up to solve?
 2 years ago
A system of two block with one frictionless pulley is release. Block one mass 3.00kg sitting on ground, block 2 mass 5.00 kg with a height of 4.00 meter. What is the velocity (speed) of the 5.0kg block in m/s when it strikes the ground. We have been using the conservation of momentum and Kinetic Energy (KE) and Potential Energy (PEg) formulas. ow do I set this up to solve?

This Question is Open

imron07
 2 years ago
Best ResponseYou've already chosen the best response.2Since there's no energy lost in the system: PE+KE before = PE + KE after dw:1351478956312:dw

DonReynolds
 2 years ago
Best ResponseYou've already chosen the best response.0Thanks for that reply, I understand that, but how do I set up the equation to calculate the velocity?

imron07
 2 years ago
Best ResponseYou've already chosen the best response.2Before: m1gh1+m2gh2+1/2 mv1^2+1/2 mv2^2=0+5g*4+0+0 After: m1gh'1+m2gh'2+1/2 mv'1^2+1/2 mv'2^2=3g*4+0+1/2x3xv'^2+1/2x5xv'^2 (v'1=v'=v')
Ask your own question
Sign UpFind more explanations on OpenStudy
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.