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Stuck! *sighs* (-2x^2)(x^-5)^2

Mathematics
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you might want to re-write this problem...
\[(-2x^2)(x^-5)^2\]
\[(x - 5)^2 = (x - 5)(x - 5)\] so \[(x - 5)(x - 5)\] FOIL that to get what?

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Other answers:

\[x^2-10x+25?\]
yeah then we do \[2x^2(x^2 - 10x + 25)\]
Which is \[x^4-20x^3+50x^2?\]
yeah, but idk if your teacher or whoever wants the simplified version or not lol \[-2x^4-20x^3+50x^2?\] ^^^^^ i think that's what you meant, but you missed the -2
Lol! Thank you so much!
hit that best response if you would :P
May you please help with this one:\[(4/3)^{-6}\]
ok so, since it's to the negative sixth power, we take the reciprocal of the number and then the power becomes positive and we put it in the denominator.

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