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kmcneill2020

  • 2 years ago

Stuck! *sighs* (-2x^2)(x^-5)^2

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  1. gaara438125
    • 2 years ago
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    you might want to re-write this problem...

  2. kmcneill2020
    • 2 years ago
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    \[(-2x^2)(x^-5)^2\]

  3. gaara438125
    • 2 years ago
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    \[(x - 5)^2 = (x - 5)(x - 5)\] so \[(x - 5)(x - 5)\] FOIL that to get what?

  4. kmcneill2020
    • 2 years ago
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    \[x^2-10x+25?\]

  5. gaara438125
    • 2 years ago
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    yeah then we do \[2x^2(x^2 - 10x + 25)\]

  6. kmcneill2020
    • 2 years ago
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    Which is \[x^4-20x^3+50x^2?\]

  7. gaara438125
    • 2 years ago
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    yeah, but idk if your teacher or whoever wants the simplified version or not lol \[-2x^4-20x^3+50x^2?\] ^^^^^ i think that's what you meant, but you missed the -2

  8. kmcneill2020
    • 2 years ago
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    Lol! Thank you so much!

  9. gaara438125
    • 2 years ago
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    hit that best response if you would :P

  10. kmcneill2020
    • 2 years ago
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    May you please help with this one:\[(4/3)^{-6}\]

  11. gaara438125
    • 2 years ago
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    ok so, since it's to the negative sixth power, we take the reciprocal of the number and then the power becomes positive and we put it in the denominator.

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