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swin2013
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\[\sin(xy) = 2x+5\]

baldymcgee6
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dw:1351479398654:dw

baldymcgee6
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differentiate implicitly.

swin2013
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yea... i think i did it wrong. i know when there's a y present you multiply by dy/dx

baldymcgee6
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Well, you see, we're taking the derivative with respect to x, so when we come upon a y, we just write "the derivative of y" which is dy//dx or y'

baldymcgee6
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So what is the derivative of sin(xy)

swin2013
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cos(xy)

baldymcgee6
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But beacause of the chaine rule we have to multiply by the derivative of the inside.

baldymcgee6
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dw:1351479776831:dw

swin2013
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oookk i was stuck on that part, i wasn't sure if i multiplied dy/dx correctly