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anonymous
 4 years ago
Solving quadratics by factoring, solve equaton
20x^2+14=27x
anonymous
 4 years ago
Solving quadratics by factoring, solve equaton 20x^2+14=27x

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anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0first add 27x to each side 20x^2 +27x + 14 = 0

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0oh no, you can't subtract 20x^2 and 27x one is x to the second power

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0it's 20x^2 + 27x + 14 = 0 the 27 has a variable of x which we don't know what is so we can't add or subtract with it unless another number has the same variable

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0this algbra is confusing

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0ok, so if your adding or subtracting with a variable you need to have the same variable, but if your multiply or dividing it doesn't matter.

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0ok well we have 20x^2 +27x + 14 = 0 and ima pass it to @JakeV8 mainly because i forget this part, and i need sleep lol

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0ok Jake from here i need to find the smaller value & the larger value

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Sorry, I got kicked off the site and lost everything I had typed. This doesn't factor into something easy with integer values... 20x^2 +27x + 14 = 0 you can divide it all through by 20 to get: x^2  (27/20)x + (14/20) = 0 But in my opinion, that's not much better. The solutions are x = 8/20 and x = 35/20 which both reduce to x = 2/5 and x = 7/4 that means you could have factored it as: (x + 2/5)(x  7/4) = 0 If you can see how to easily get from the original quadratic equation to this factored form, then great. Personally, it doesn't seem easy or obvious to me, and if the problem hadn't stated to solve by factoring, I would have used the quadratic formula to get the solutions for x.
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