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parking in a student lot cost $1 for the first hour and 1.75 for each hour there after a partial hour is changed the same as a full hour what is the longest time that a student can park in this lot for $7 ? the longest time is ? have to show my work.
 one year ago
 one year ago
parking in a student lot cost $1 for the first hour and 1.75 for each hour there after a partial hour is changed the same as a full hour what is the longest time that a student can park in this lot for $7 ? the longest time is ? have to show my work.
 one year ago
 one year ago

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etemplinBest ResponseYou've already chosen the best response.1
the expression for how much money it costs is 1+1.75t where t is time in hours. If the cost has to be less than or equal to 7, set the expression less than or equal to 7 1+1.75t<=7 subtract 1 from both sides and divide by 1.75 this will tell you how many hours you can have remember to round down to the nearest integer
 one year ago

hitten101Best ResponseYou've already chosen the best response.0
1+1.75t<=7 1.75t<=6 calculate t now..
 one year ago

etemplinBest ResponseYou've already chosen the best response.1
@hitten101 i think we both made a mistake...shouldnt it be 1+1.75(t1)<=7 because if you plug in 1 hour into the original, you get charged 2.75 not 1.00
 one year ago

hitten101Best ResponseYou've already chosen the best response.0
oh yes you are right @etemplin
 one year ago

EmilyggarzaBest ResponseYou've already chosen the best response.0
the answer is 6 then?
 one year ago

EmilyggarzaBest ResponseYou've already chosen the best response.0
no offends you a very intelligent handsome guy.
 one year ago

etemplinBest ResponseYou've already chosen the best response.1
no. using the new equation (the old one was wrong...sorry about that) you get t<=4.42 so it should be 4. ill check by taking 1 for the first hour, adding 1.75 for the second hour (total = 2.75) add 1.75 for the third hour (total = 4.5) and 1.75 for the 4th hour (total = 6.25) since you cant go over 7, the hours = 4
 one year ago

hitten101Best ResponseYou've already chosen the best response.0
No @etemplin the time can go in fractions also. it does not need to be a natural number. it can be a fraction.
 one year ago

etemplinBest ResponseYou've already chosen the best response.1
it says if you only use a partial hour it counts for a whole one
 one year ago

hitten101Best ResponseYou've already chosen the best response.0
@Emilyggarza whom u referring to?
 one year ago

hitten101Best ResponseYou've already chosen the best response.0
hmmm... ur right @etemplin i ignored that part of the question
 one year ago

hitten101Best ResponseYou've already chosen the best response.0
and thank you @Emilyggarza
 one year ago

robtobeyBest ResponseYou've already chosen the best response.0
\[1+\text{Floor}\left[\frac{71}{1.75}\right]=4 \text{ hours}\]Floor[x] gives the greatest integer less than or equal to x.
 one year ago
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