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feldy90
 3 years ago
Is the cotan(theta) function the same as tan^1(theta)?
feldy90
 3 years ago
Is the cotan(theta) function the same as tan^1(theta)?

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uzumakhi
 3 years ago
Best ResponseYou've already chosen the best response.2\[\cot \theta = \frac{ 1 }{ \tan \theta }\]

feldy90
 3 years ago
Best ResponseYou've already chosen the best response.0So that's a yes? If I'm entering it into my calculator (there is no cot function), I enter\[\cot(\theta) = \tan^{1}(\theta)\]

uzumakhi
 3 years ago
Best ResponseYou've already chosen the best response.2you can't write it as \[\tan ^{1} \theta \]

feldy90
 3 years ago
Best ResponseYou've already chosen the best response.0Isn't that the same thing...? Doesn't: \[\frac{ 1 }{ \tan(\theta) } = \tan ^{1}(\theta)\]

irene22988
 3 years ago
Best ResponseYou've already chosen the best response.0nope. to find cot(theta), do this: 1/(tan(theta))

uzumakhi
 3 years ago
Best ResponseYou've already chosen the best response.2when we take tan function from one side of equality to other then we write tan^1

feldy90
 3 years ago
Best ResponseYou've already chosen the best response.0So you use tan^1 in something like... To solve for x if tan(x)=a, then x=tan^1(a)

feldy90
 3 years ago
Best ResponseYou've already chosen the best response.0Can you say\[\csc ^{4}(\theta) = \frac{ 1 }{ \sin ^{4}(\theta) }\]

irene22988
 3 years ago
Best ResponseYou've already chosen the best response.0yep. in calculator, that would be: 1/(sin(theta))^4

shubhamsrg
 3 years ago
Best ResponseYou've already chosen the best response.01 is a special case in trigonometric functions.. 1 corresponds to inverse function.. thus for 1/sin, we use cosec and likewise..
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