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\[\cot \theta = \frac{ 1 }{ \tan \theta }\]

you can't write it as
\[\tan ^{-1} \theta \]

Isn't that the same thing...? Doesn't:
\[\frac{ 1 }{ \tan(\theta) } = \tan ^{-1}(\theta)\]

no my friend

:( okay. Thanks

nope. to find cot(theta), do this: 1/(tan(theta))

when we take tan function from one side of equality to other then we write tan^-1

So you use tan^-1 in something like... To solve for x if tan(x)=a, then x=tan^-1(a)

yes you are right

Thank you :)

welcome

Can you say\[\csc ^{4}(\theta) = \frac{ 1 }{ \sin ^{4}(\theta) }\]

yep. in calculator, that would be: 1/(sin(theta))^4

Thanks I get it now :)

hmm,,glad you do!