## feldy90 3 years ago Is the cotan(theta) function the same as tan^-1(theta)?

1. uzumakhi

$\cot \theta = \frac{ 1 }{ \tan \theta }$

2. feldy90

So that's a yes? If I'm entering it into my calculator (there is no cot function), I enter$\cot(\theta) = \tan^{-1}(\theta)$

3. uzumakhi

you can't write it as $\tan ^{-1} \theta$

4. feldy90

Isn't that the same thing...? Doesn't: $\frac{ 1 }{ \tan(\theta) } = \tan ^{-1}(\theta)$

5. uzumakhi

no my friend

6. feldy90

:( okay. Thanks

7. irene22988

nope. to find cot(theta), do this: 1/(tan(theta))

8. uzumakhi

when we take tan function from one side of equality to other then we write tan^-1

9. feldy90

So you use tan^-1 in something like... To solve for x if tan(x)=a, then x=tan^-1(a)

10. uzumakhi

yes you are right

11. feldy90

Thank you :)

12. uzumakhi

welcome

13. feldy90

Can you say$\csc ^{4}(\theta) = \frac{ 1 }{ \sin ^{4}(\theta) }$

14. irene22988

yep. in calculator, that would be: 1/(sin(theta))^4

15. shubhamsrg

-1 is a special case in trigonometric functions.. -1 corresponds to inverse function.. thus for 1/sin, we use cosec and likewise..

16. feldy90

Thanks I get it now :)

17. shubhamsrg