anonymous
  • anonymous
Explain Pascal's Law
Physics
  • Stacey Warren - Expert brainly.com
Hey! We 've verified this expert answer for you, click below to unlock the details :)
SOLVED
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.
schrodinger
  • schrodinger
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
anonymous
  • anonymous
@calculusfunctions sir, please help
anonymous
  • anonymous
@Algebraic!
anonymous
  • anonymous
@ganeshie8

Looking for something else?

Not the answer you are looking for? Search for more explanations.

More answers

anonymous
  • anonymous
what's your question?
anonymous
  • anonymous
What is Pascal's Law?
anonymous
  • anonymous
weight = mg
anonymous
  • anonymous
I am preparing a model for "hydraulic crane" and hence I need to know about Pascal's Law, Can you tell me that how it applies in hydraulic crane or any hydraulic system
anonymous
  • anonymous
|dw:1351506202510:dw| Just a very rough diagram of hydraulic crane :)
anonymous
  • anonymous
consider a cylinder of water area of ends =A height = d if it's open to the atmosphere at the top, what's the pressure at a depth d? weight of water = A*d*density*g = F pressure = F/A = d*density*g
anonymous
  • anonymous
Can you explain with diagram ?
anonymous
  • anonymous
btw, this is how my "hydraulic crane" works: http://www.youtube.com/watch?v=Dcmbdczw3CA
anonymous
  • anonymous
|dw:1351506384411:dw|
anonymous
  • anonymous
so you're maybe concerned about this aspect of it...
anonymous
  • anonymous
Yes ...
anonymous
  • anonymous
|dw:1351506734001:dw|
anonymous
  • anonymous
|dw:1351507069349:dw|
anonymous
  • anonymous
F2 = (A2/A1)*F1
anonymous
  • anonymous
|dw:1351507242257:dw|

Looking for something else?

Not the answer you are looking for? Search for more explanations.