Given a geometric sequence whose sum of the first 10 terms is 4 and whose sum from the 11th to the 30th term is 48, find the sum from the 31st to the 60th term.

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Sum of 10 = a * (r^4 - 1)
-------- = 4
r- 1

@cwrw238 why is it r^4? I thought it's r^10.

n is 10 not 4

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