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minnie123

  • 2 years ago

Help Please!!! *** Fan and medal rewarded*** ***Attachment below***

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  1. minnie123
    • 2 years ago
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  2. minnie123
    • 2 years ago
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    Somebody Help Me!!!!

  3. piscez.in
    • 2 years ago
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    Im trying to figure out how to make use of the 'equation' functionality of this site

  4. minnie123
    • 2 years ago
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    ok?

  5. piscez.in
    • 2 years ago
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    2x/(y^2-x^2) = 2x/ (y+x) *(y-x) therefore the equation becomes 2x/ (y+x)(y-x) - x/(y-x) = ( 2x- x(y+x) )/ ( (y+x)(y-x) ) =( 2x- xy- x^2) / (y^2- x^2) I hope that makes sense. It was pretty simple, i am not sure if this was what you were looking for. Really sorry for making it exorbitantly late . I was trying to figure out how to use the 'equation' functionality and it was so frustrating

  6. minnie123
    • 2 years ago
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    thanks...

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spraguer (Moderator)
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is replying to Can someone tell me what button the professor is hitting...

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