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minnie123
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Help Please!!! *** Fan and medal rewarded***
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 2 years ago
 2 years ago
minnie123 Group Title
Help Please!!! *** Fan and medal rewarded*** ***Attachment below***
 2 years ago
 2 years ago

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minnie123 Group TitleBest ResponseYou've already chosen the best response.0
Somebody Help Me!!!!
 2 years ago

piscez.in Group TitleBest ResponseYou've already chosen the best response.1
Im trying to figure out how to make use of the 'equation' functionality of this site
 2 years ago

piscez.in Group TitleBest ResponseYou've already chosen the best response.1
2x/(y^2x^2) = 2x/ (y+x) *(yx) therefore the equation becomes 2x/ (y+x)(yx)  x/(yx) = ( 2x x(y+x) )/ ( (y+x)(yx) ) =( 2x xy x^2) / (y^2 x^2) I hope that makes sense. It was pretty simple, i am not sure if this was what you were looking for. Really sorry for making it exorbitantly late . I was trying to figure out how to use the 'equation' functionality and it was so frustrating
 2 years ago

minnie123 Group TitleBest ResponseYou've already chosen the best response.0
thanks...
 2 years ago
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