A community for students.
Here's the question you clicked on:
 0 viewing
anonymous
 4 years ago
Help Please!!! *** Fan and medal rewarded***
***Attachment below***
anonymous
 4 years ago
Help Please!!! *** Fan and medal rewarded*** ***Attachment below***

This Question is Closed

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Im trying to figure out how to make use of the 'equation' functionality of this site

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.02x/(y^2x^2) = 2x/ (y+x) *(yx) therefore the equation becomes 2x/ (y+x)(yx)  x/(yx) = ( 2x x(y+x) )/ ( (y+x)(yx) ) =( 2x xy x^2) / (y^2 x^2) I hope that makes sense. It was pretty simple, i am not sure if this was what you were looking for. Really sorry for making it exorbitantly late . I was trying to figure out how to use the 'equation' functionality and it was so frustrating
Ask your own question
Sign UpFind more explanations on OpenStudy
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.