Open study

is now brainly

With Brainly you can:

  • Get homework help from millions of students and moderators
  • Learn how to solve problems with step-by-step explanations
  • Share your knowledge and earn points by helping other students
  • Learn anywhere, anytime with the Brainly app!

A community for students.

Help Please!!! *** Fan and medal rewarded*** ***Attachment below***

Mathematics
See more answers at brainly.com
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

Get this expert

answer on brainly

SEE EXPERT ANSWER

Get your free account and access expert answers to this and thousands of other questions

1 Attachment
Somebody Help Me!!!!
Im trying to figure out how to make use of the 'equation' functionality of this site

Not the answer you are looking for?

Search for more explanations.

Ask your own question

Other answers:

ok?
2x/(y^2-x^2) = 2x/ (y+x) *(y-x) therefore the equation becomes 2x/ (y+x)(y-x) - x/(y-x) = ( 2x- x(y+x) )/ ( (y+x)(y-x) ) =( 2x- xy- x^2) / (y^2- x^2) I hope that makes sense. It was pretty simple, i am not sure if this was what you were looking for. Really sorry for making it exorbitantly late . I was trying to figure out how to use the 'equation' functionality and it was so frustrating
thanks...

Not the answer you are looking for?

Search for more explanations.

Ask your own question