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minnie123
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Help Please!!! *** Fan and medal rewarded***
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 one year ago
 one year ago
minnie123 Group Title
Help Please!!! *** Fan and medal rewarded*** ***Attachment below***
 one year ago
 one year ago

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minnie123 Group TitleBest ResponseYou've already chosen the best response.0
Somebody Help Me!!!!
 one year ago

piscez.in Group TitleBest ResponseYou've already chosen the best response.1
Im trying to figure out how to make use of the 'equation' functionality of this site
 one year ago

piscez.in Group TitleBest ResponseYou've already chosen the best response.1
2x/(y^2x^2) = 2x/ (y+x) *(yx) therefore the equation becomes 2x/ (y+x)(yx)  x/(yx) = ( 2x x(y+x) )/ ( (y+x)(yx) ) =( 2x xy x^2) / (y^2 x^2) I hope that makes sense. It was pretty simple, i am not sure if this was what you were looking for. Really sorry for making it exorbitantly late . I was trying to figure out how to use the 'equation' functionality and it was so frustrating
 one year ago

minnie123 Group TitleBest ResponseYou've already chosen the best response.0
thanks...
 one year ago
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