A community for students.
Here's the question you clicked on:
 0 viewing
anonymous
 4 years ago
Find the directional derivatives of the following functions at the given points P in the direction of the vectors v.
f(x,y,z) =√xyz , P (3,2,6) , v =<1,2,2>
anonymous
 4 years ago
Find the directional derivatives of the following functions at the given points P in the direction of the vectors v. f(x,y,z) =√xyz , P (3,2,6) , v =<1,2,2>

This Question is Closed

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0find the derivatives of the function x, y and z seperately, by keeping the other 2 variables constant in each case. Think of a smart way to keep the other 2 variables constant!

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0ok, i tried to work out. is the ans 1?

TuringTest
 4 years ago
Best ResponseYou've already chosen the best response.1what is you function?\[f(x,y,z)=\sqrt{xyz}\]or\[f(x,y,z)=\sqrt xyz\]?

TuringTest
 4 years ago
Best ResponseYou've already chosen the best response.1\[D_{\vec v}=\nabla f(3,2,6)\cdot\frac{\vec v}{\\vec v\}\]I don't think the answer is one but I haven't done it yet...

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0is there an advanced equation editor available to super users that has cool features like gradient?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0@mathstina @TuringTest is right

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0@mathstina first fing the derivative of the function with respect to x, by substituting the y and x values

TuringTest
 4 years ago
Best ResponseYou've already chosen the best response.1oh yeah, I do get 1 :)

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0@TuringTest @mathstina no its not 1, atleast as per my calculations

TuringTest
 4 years ago
Best ResponseYou've already chosen the best response.1I will show my work and you can spot a mistake if you see one...

TuringTest
 4 years ago
Best ResponseYou've already chosen the best response.1\[\nabla f=\frac12\langle\sqrt{\frac{yz}x},\sqrt{\frac{xz}y},\sqrt{\frac{xy}z}\rangle\implies\nabla f(3,2,6)=\frac12\langle2,3,1\rangle\]\[\frac{\vec v}{\\vec v\}=\frac13\langle1,2,2\rangle\]\[\nabla f(3,2,6)\cdot\frac{\vec v}{\\vec v\}=\frac16(26+2)=1\]

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0@TuringTest @mathstina im sorry, your right, i made a mistake by putting all ves as +ves and vice versa. Bravo you two

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Its ok. u too got the same ans

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0i got it as 1 previously, now i have 1 :)
Ask your own question
Sign UpFind more explanations on OpenStudy
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.