Can someone help me with this please? I don't know how to do this.
Write the equation for the horizontal line that contains point G(-8, 8).

- anonymous

- schrodinger

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- anonymous

Horizontal lines are of the form y=n where you may have been given a point in the form (m, n). You have such a point G.

- anonymous

keep in mind that a horizontal line is parallel to x axis, and slope is the value of tan of the angle between the x axis and the line

- anonymous

@piscez.in: What do you mean by the slope is the value of tan of the angle between the x-axis and the line? Specifically, what do you mean by the value of tan?
@tcarroll010: Okay, just a moment please.

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- anonymous

So it would be something like y = 8 - (-8)?

- anonymous

@fang02 tan value as in tangent value, like sine cosine, tan etc.

- anonymous

Hmm..I do not believe I have learned about the tan value then.

- anonymous

He means that the equation of a line in slope-intercept form, in general is y = mx + b and that here we have "0" slope, so the mx term disappears. So, we have y=b, or in my notation, y=n. You have point (-8, 8) which is the same distance away from the x-axis as the "b" intercept, (0, 8), so you can simplify and use the "n".

- anonymous

@Fang02 oh im sorry hun, well then forget it. But try to roughly draw the line on a paper. Find the y intercept. And you must already be knowing that the slope of horizontal lines( lines parallel to x axis) is always 1

- anonymous

Not y = 8 - (-8). Instead, y=n where n = 8

- anonymous

So, the answer is pretty much y = 8 then?
No need to be sorry pisez.in.

- anonymous

Yes! You got it. Good job! It's just y=8.

- anonymous

Okay, thanks a lot! :) Would you mind helping me with another problem real quick?

- anonymous

sure!

- anonymous

Write an equation in point-slope form of the line through point J(4, 1) with slope -4.

- anonymous

Point-slope form is y2 - y1 over x2 over x1
So, I think it would be:
1 - 4 over something

- anonymous

point-slope form is going to be:\[y - y _{1} = m(x - x _{1})\] Here, y is y and x is x as variables. x1 and y1 are a SPECIFIC point in the form (x1, y1)

- anonymous

(x1, y1) is the point you are given that is (4, 1), so x1 is 4 and y1 is 1.

- anonymous

I think that (x1, y1) would be (-4, 1) right?

- anonymous

Why does the 4 turn positive?

- anonymous

(x1, y1) is the point you are given that is (4, 1), so x1 is 4 and y1 is 1. It's the slope that is -4.

- anonymous

I understand.

- anonymous

So now, just substitute.

- anonymous

y - y1 = m(x - x1)
y - 1 = -4 (4 - 4) ?

- anonymous

Not quite there yet. What happened to "x"? "x" stays as "x" just like "y" stays as "y". You only substitute for y1, x1, and m.

- anonymous

Oh okay. So, y = 1 = -4(x - 4)

- anonymous

You still have a small typo, but you are extremely close now.

- anonymous

Would I put x1 in parenthesis to show that it is positive and is just being subtracted?
y = 1 = -4(x - (4))

- anonymous

You don't have to do that, you can just leave it as y - 1 = -4(x - 4). Notice how after the "y" I changed that from "=" to "-"

- anonymous

Oh okay, I understand now.

- anonymous

Very nice working with you and you will get there. Just keep up the good work!

- anonymous

Thanks! You too! :)

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