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karinewoods17
 3 years ago
combine {sqrt 8} + {sqrt 32}
karinewoods17
 3 years ago
combine {sqrt 8} + {sqrt 32}

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karinewoods17
 3 years ago
Best ResponseYou've already chosen the best response.1The answer in my book is \[6i  2i \sqrt{10}\] I dont know how they got that answer.

ilikephysics2
 3 years ago
Best ResponseYou've already chosen the best response.0You can't take the square root of a negative number

karinewoods17
 3 years ago
Best ResponseYou've already chosen the best response.1thats why you multiply it by i which is equal to 1

Ahaanomegas
 3 years ago
Best ResponseYou've already chosen the best response.0@ksaimouli That's totally wrong. sqrt(a)+sqrt(b) is NOT sqrt(a+b). @ilikephysics2 Yes, You can. That's what imaginary numbers are there for. @karinewoods17 Notice that \[ \Large {\sqrt {8} = 2\sqrt{2}} \]and \[ \Large {\sqrt {32} = 4\sqrt{2}}, \]so \[ \Large {\sqrt {8} = 2i\sqrt{2}} \]and \[ \Large {\sqrt {32} = 4i\sqrt{2}} \]Do you see how that works? Now, just add to get 6isqrt(2).

karinewoods17
 3 years ago
Best ResponseYou've already chosen the best response.1wouldnt it be \[6i \sqrt{2}\] ??

ChmE
 3 years ago
Best ResponseYou've already chosen the best response.0\[\sqrt{8}+\sqrt{32}=\sqrt{8}+\sqrt{8\times4}= \sqrt{8} + 2\sqrt{8}\]

ChmE
 3 years ago
Best ResponseYou've already chosen the best response.0\[3\sqrt{8}=3i \sqrt{8}=3i \sqrt{2\times4}=6i \sqrt{2}\]

Ahaanomegas
 3 years ago
Best ResponseYou've already chosen the best response.0Yep. That's exactly what I said, except I explained everything. =P

karinewoods17
 3 years ago
Best ResponseYou've already chosen the best response.1but... the answer in my book says the answer is \[6i  2i \sqrt{10}\] How did they get that?

karinewoods17
 3 years ago
Best ResponseYou've already chosen the best response.1Im sorry:/ Im making coffee and waiting for you:)

karinewoods17
 3 years ago
Best ResponseYou've already chosen the best response.1I was making breakfast for my boyfriend.

karinewoods17
 3 years ago
Best ResponseYou've already chosen the best response.1umm. \[\sqrt{32}\] breaks into \[\sqrt{32} = \sqrt{4} * \sqrt{8}\] which simplifies to \[4i \sqrt{2}\] ?

karinewoods17
 3 years ago
Best ResponseYou've already chosen the best response.1@nincompoop please do not ignore me;)
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