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karinewoods17 Group TitleBest ResponseYou've already chosen the best response.1
The answer in my book is \[6i  2i \sqrt{10}\] I dont know how they got that answer.
 2 years ago

ilikephysics2 Group TitleBest ResponseYou've already chosen the best response.0
You can't take the square root of a negative number
 2 years ago

ChmE Group TitleBest ResponseYou've already chosen the best response.0
@ksaimouli is incorrect
 2 years ago

karinewoods17 Group TitleBest ResponseYou've already chosen the best response.1
thats why you multiply it by i which is equal to 1
 2 years ago

Ahaanomegas Group TitleBest ResponseYou've already chosen the best response.0
@ksaimouli That's totally wrong. sqrt(a)+sqrt(b) is NOT sqrt(a+b). @ilikephysics2 Yes, You can. That's what imaginary numbers are there for. @karinewoods17 Notice that \[ \Large {\sqrt {8} = 2\sqrt{2}} \]and \[ \Large {\sqrt {32} = 4\sqrt{2}}, \]so \[ \Large {\sqrt {8} = 2i\sqrt{2}} \]and \[ \Large {\sqrt {32} = 4i\sqrt{2}} \]Do you see how that works? Now, just add to get 6isqrt(2).
 2 years ago

karinewoods17 Group TitleBest ResponseYou've already chosen the best response.1
wouldnt it be \[6i \sqrt{2}\] ??
 2 years ago

ChmE Group TitleBest ResponseYou've already chosen the best response.0
\[\sqrt{8}+\sqrt{32}=\sqrt{8}+\sqrt{8\times4}= \sqrt{8} + 2\sqrt{8}\]
 2 years ago

ChmE Group TitleBest ResponseYou've already chosen the best response.0
\[3\sqrt{8}=3i \sqrt{8}=3i \sqrt{2\times4}=6i \sqrt{2}\]
 2 years ago

ChmE Group TitleBest ResponseYou've already chosen the best response.0
Yes you are correct
 2 years ago

Ahaanomegas Group TitleBest ResponseYou've already chosen the best response.0
Yep. That's exactly what I said, except I explained everything. =P
 2 years ago

karinewoods17 Group TitleBest ResponseYou've already chosen the best response.1
but... the answer in my book says the answer is \[6i  2i \sqrt{10}\] How did they get that?
 2 years ago

karinewoods17 Group TitleBest ResponseYou've already chosen the best response.1
Im sorry:/ Im making coffee and waiting for you:)
 2 years ago

karinewoods17 Group TitleBest ResponseYou've already chosen the best response.1
im not! sorry!
 2 years ago

karinewoods17 Group TitleBest ResponseYou've already chosen the best response.1
I was making breakfast for my boyfriend.
 2 years ago

karinewoods17 Group TitleBest ResponseYou've already chosen the best response.1
umm. \[\sqrt{32}\] breaks into \[\sqrt{32} = \sqrt{4} * \sqrt{8}\] which simplifies to \[4i \sqrt{2}\] ?
 2 years ago

karinewoods17 Group TitleBest ResponseYou've already chosen the best response.1
And yes I try:)
 2 years ago

karinewoods17 Group TitleBest ResponseYou've already chosen the best response.1
now what. lol
 2 years ago

karinewoods17 Group TitleBest ResponseYou've already chosen the best response.1
@nincompoop please do not ignore me;)
 2 years ago
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