anonymous
  • anonymous
combine {sqrt -8} + {sqrt -32}
Mathematics
chestercat
  • chestercat
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anonymous
  • anonymous
The answer in my book is \[6i - 2i \sqrt{10}\] I dont know how they got that answer.
anonymous
  • anonymous
You can't take the square root of a negative number
anonymous
  • anonymous
@ksaimouli is incorrect

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anonymous
  • anonymous
thats why you multiply it by i which is equal to -1
anonymous
  • anonymous
@ksaimouli That's totally wrong. sqrt(a)+sqrt(b) is NOT sqrt(a+b). @ilikephysics2 Yes, You can. That's what imaginary numbers are there for. @karinewoods17 Notice that \[ \Large {\sqrt {8} = 2\sqrt{2}} \]and \[ \Large {\sqrt {32} = 4\sqrt{2}}, \]so \[ \Large {\sqrt {-8} = 2i\sqrt{2}} \]and \[ \Large {\sqrt {-32} = 4i\sqrt{2}} \]Do you see how that works? Now, just add to get 6isqrt(2).
anonymous
  • anonymous
wouldnt it be \[6i \sqrt{2}\] ??
anonymous
  • anonymous
\[\sqrt{-8}+\sqrt{-32}=\sqrt{-8}+\sqrt{-8\times4}= \sqrt{-8} + 2\sqrt{-8}\]
anonymous
  • anonymous
\[3\sqrt{-8}=3i \sqrt{8}=3i \sqrt{2\times4}=6i \sqrt{2}\]
anonymous
  • anonymous
Yes you are correct
anonymous
  • anonymous
Yep. That's exactly what I said, except I explained everything. =P
anonymous
  • anonymous
but... the answer in my book says the answer is \[6i - 2i \sqrt{10}\] How did they get that?
anonymous
  • anonymous
Im sorry:/ Im making coffee and waiting for you:)
anonymous
  • anonymous
im not! sorry!
anonymous
  • anonymous
I was making breakfast for my boyfriend.
anonymous
  • anonymous
umm. \[\sqrt{-32}\] breaks into \[\sqrt{-32} = \sqrt{4} * \sqrt{-8}\] which simplifies to \[4i \sqrt{2}\] ?
anonymous
  • anonymous
And yes I try:)
anonymous
  • anonymous
now what. lol
anonymous
  • anonymous
@nincompoop please do not ignore me;)

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