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alchimista
Group Title
Is there a random variable X such that
E[X^2]=E[X]^2?
if yes, is it selfindependent ?
 2 years ago
 2 years ago
alchimista Group Title
Is there a random variable X such that E[X^2]=E[X]^2? if yes, is it selfindependent ?
 2 years ago
 2 years ago

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piscez.in Group TitleBest ResponseYou've already chosen the best response.0
this really seems like an interesting question, but maybe you can make it clearer, are you sure this is the right question?
 2 years ago

piscez.in Group TitleBest ResponseYou've already chosen the best response.0
is E[x} the exponential function
 2 years ago

alchimista Group TitleBest ResponseYou've already chosen the best response.0
i tought that Var(x)=E[X^2]E[X]^2 , so for Var(X)=0 E[X^2]=E[X]^2
 2 years ago

alchimista Group TitleBest ResponseYou've already chosen the best response.0
no E[X] is the expectation of x
 2 years ago

piscez.in Group TitleBest ResponseYou've already chosen the best response.0
oh im sorry
 2 years ago

alchimista Group TitleBest ResponseYou've already chosen the best response.0
so based on my reasing then I have to find a random variable for which the Var(x)=0, i think
 2 years ago

paulstephen214 Group TitleBest ResponseYou've already chosen the best response.1
if X is Cauchy Distributed then this will be true..., you can have the standardized Cauchy dist. 1/(pi*(1+(x^2)))
 2 years ago

Valpey Group TitleBest ResponseYou've already chosen the best response.0
Hard to call a variable "random" if it doesn't vary. It is also hard to show that this is true for the standardized Cauchy Distribution (basically a distribution with significant probability weight at (+/)1/0).
 2 years ago
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