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yes

is E[x} the exponential function

i tought that Var(x)=E[X^2]-E[X]^2 , so for Var(X)=0 E[X^2]=E[X]^2

no E[X] is the expectation of x

oh im sorry

so based on my reasing then I have to find a random variable for which the Var(x)=0, i think