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Is there a random variable X such that
E[X^2]=E[X]^2?
if yes, is it selfindependent ?
 one year ago
 one year ago
Is there a random variable X such that E[X^2]=E[X]^2? if yes, is it selfindependent ?
 one year ago
 one year ago

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piscez.inBest ResponseYou've already chosen the best response.0
this really seems like an interesting question, but maybe you can make it clearer, are you sure this is the right question?
 one year ago

piscez.inBest ResponseYou've already chosen the best response.0
is E[x} the exponential function
 one year ago

alchimistaBest ResponseYou've already chosen the best response.0
i tought that Var(x)=E[X^2]E[X]^2 , so for Var(X)=0 E[X^2]=E[X]^2
 one year ago

alchimistaBest ResponseYou've already chosen the best response.0
no E[X] is the expectation of x
 one year ago

alchimistaBest ResponseYou've already chosen the best response.0
so based on my reasing then I have to find a random variable for which the Var(x)=0, i think
 one year ago

paulstephen214Best ResponseYou've already chosen the best response.1
if X is Cauchy Distributed then this will be true..., you can have the standardized Cauchy dist. 1/(pi*(1+(x^2)))
 one year ago

ValpeyBest ResponseYou've already chosen the best response.0
Hard to call a variable "random" if it doesn't vary. It is also hard to show that this is true for the standardized Cauchy Distribution (basically a distribution with significant probability weight at (+/)1/0).
 one year ago
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