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alchimista
 2 years ago
Is there a random variable X such that
E[X^2]=E[X]^2?
if yes, is it selfindependent ?
alchimista
 2 years ago
Is there a random variable X such that E[X^2]=E[X]^2? if yes, is it selfindependent ?

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piscez.in
 2 years ago
Best ResponseYou've already chosen the best response.0this really seems like an interesting question, but maybe you can make it clearer, are you sure this is the right question?

piscez.in
 2 years ago
Best ResponseYou've already chosen the best response.0is E[x} the exponential function

alchimista
 2 years ago
Best ResponseYou've already chosen the best response.0i tought that Var(x)=E[X^2]E[X]^2 , so for Var(X)=0 E[X^2]=E[X]^2

alchimista
 2 years ago
Best ResponseYou've already chosen the best response.0no E[X] is the expectation of x

alchimista
 2 years ago
Best ResponseYou've already chosen the best response.0so based on my reasing then I have to find a random variable for which the Var(x)=0, i think

paulstephen214
 2 years ago
Best ResponseYou've already chosen the best response.1if X is Cauchy Distributed then this will be true..., you can have the standardized Cauchy dist. 1/(pi*(1+(x^2)))

Valpey
 2 years ago
Best ResponseYou've already chosen the best response.0Hard to call a variable "random" if it doesn't vary. It is also hard to show that this is true for the standardized Cauchy Distribution (basically a distribution with significant probability weight at (+/)1/0).
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