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alchimista
Group Title
Is there a random variable X such that
E[X^2]=E[X]^2?
if yes, is it selfindependent ?
 one year ago
 one year ago
alchimista Group Title
Is there a random variable X such that E[X^2]=E[X]^2? if yes, is it selfindependent ?
 one year ago
 one year ago

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piscez.in Group TitleBest ResponseYou've already chosen the best response.0
this really seems like an interesting question, but maybe you can make it clearer, are you sure this is the right question?
 one year ago

piscez.in Group TitleBest ResponseYou've already chosen the best response.0
is E[x} the exponential function
 one year ago

alchimista Group TitleBest ResponseYou've already chosen the best response.0
i tought that Var(x)=E[X^2]E[X]^2 , so for Var(X)=0 E[X^2]=E[X]^2
 one year ago

alchimista Group TitleBest ResponseYou've already chosen the best response.0
no E[X] is the expectation of x
 one year ago

piscez.in Group TitleBest ResponseYou've already chosen the best response.0
oh im sorry
 one year ago

alchimista Group TitleBest ResponseYou've already chosen the best response.0
so based on my reasing then I have to find a random variable for which the Var(x)=0, i think
 one year ago

paulstephen214 Group TitleBest ResponseYou've already chosen the best response.1
if X is Cauchy Distributed then this will be true..., you can have the standardized Cauchy dist. 1/(pi*(1+(x^2)))
 one year ago

Valpey Group TitleBest ResponseYou've already chosen the best response.0
Hard to call a variable "random" if it doesn't vary. It is also hard to show that this is true for the standardized Cauchy Distribution (basically a distribution with significant probability weight at (+/)1/0).
 one year ago
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