anonymous
  • anonymous
How would you transform the graph of y= f (x ) to obtain the graph of y= -3f (x- 2) +5 ? If (7, -3) is a point on the graph of y= f (x ) , what would be the corresponding point on the graph of y=-3f (x- 2)+ 5 ?
Mathematics
chestercat
  • chestercat
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anonymous
  • anonymous
anonymous
  • anonymous
anonymous
  • anonymous
There are three aspects to the transformation. Think first about that "-3" in front of the f(x-2)... and just think for a minute as if was just -3f(x). So if that was the only transformation, it would take the original function f(x), and it would make it 3 times larger for every x input, but it would also flip it... so any negative values in f(x) would become positive (and 3 times larger) in -3f(x).

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anonymous
  • anonymous
Next, think about what the (x-2) does as the function input in comparison to the original function, f(x). f(x) gives some value for any input x. f(x-2) will take values for x that are 2 larger and then return the same f. In other words, say f(x) = 10 when x=0... f(0) = 10 Then in the transformed function f(x-2), it will also be equal 10, but it will shift over to be equal 10 when x = 2. So f(x-2) is a transformation that shifts the function right by 2 units compared with f(x)
anonymous
  • anonymous
So, with those two parts of the transformation, you can say that -3f(x-2) transforms f(x) by making it 3 times larger, flipping it across the x-axis, and shifting it all right by 2 units. The last transformation adds 5 to everything else. Can you see what shift will occur as a result?
anonymous
  • anonymous
to be honest i didn't get it.
anonymous
  • anonymous
1)shift the function to the right by 2 points, 2) flip the graph down, around x axis. 3) Re- calibrate y axis in such a way that 3 units in the previous graph is 1 unit in the present graph 4) Shift the resulting graph up by 5 points
anonymous
  • anonymous
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