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Find the center and radius of a circle that has a diameter with endpoints (-9, -6) and (-1,0). Show work. a) center (4,3); radius 5 b) center (8,6); radius 10 c) center (-5,-3); radius 5 d) center (-10,-6); radius 10

Algebra
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Center would be the midpoint between those two points, and the radius would be the distance between them divided by 2
So I do the midpoint formula using the two points to find the center?
Graph paper would work great for this problem

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Yep, use the midpoint formula
What do you get?
(-5,-3)
Yep, what about for the radius?
I know its suppose to be 5, but I didn't get it.
Do you know the distance formula?
Wait, I think I know why..
I still didn't get it. Isn't it d=\[\sqrt{(x2-x1)^{2}+(y2-y1)^{2}}\]
Yeah thats it. Plug in your coordinates \[D=\sqrt{(-1+9)^2+(0+6)^2}\]
youll get d=sqrt{100} d=10 but remember thats the diameter, radius is diameter divided by 2. 10/2=5
Oh, I got it now. I just added wrong. Thanks!
You're welcome

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