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mark_o.
 2 years ago
Best ResponseYou've already chosen the best response.0derivative of u=5x+(1/2) sqrt of x sometimes its easier to use the power rule, and rewriting it as u=5x+(1/2 )( x)^1/2 use power rule of the derivative

mark_o.
 2 years ago
Best ResponseYou've already chosen the best response.0d(kx)/dx=k.,,dx^n/dx= nx^n1

roselin
 2 years ago
Best ResponseYou've already chosen the best response.0the problem is actually: dw:1351567010524:dw

roselin
 2 years ago
Best ResponseYou've already chosen the best response.0\[u= 5x+1\div 2\sqrt{x}\]

mark_o.
 2 years ago
Best ResponseYou've already chosen the best response.0it will be the same idea by using the power rule u=5x + 1/(2sqrtx) u=5x + (1/2)(x)^1/2 now find the derivative

roselin
 2 years ago
Best ResponseYou've already chosen the best response.0what if i use the quotient rule?

mark_o.
 2 years ago
Best ResponseYou've already chosen the best response.0u=5x + (1/2)(x)^1/2 is it du/dt=5+(1/2)(1/2)x^1/2  2/2) du/dt=5+(1/2)(1/2)x^3/2 ) ?

roselin
 2 years ago
Best ResponseYou've already chosen the best response.0its find the derivative of the function \[u= 5x+1 \div \sqrt{2}\]

mark_o.
 2 years ago
Best ResponseYou've already chosen the best response.0ok the quotient rule says \[\frac{ d(\frac{ U }{ V }) }{ dx }=\frac{ V \frac{ du }{ dx }U \frac{ dV }{ dx } }{ v ^{2} }\]

roselin
 2 years ago
Best ResponseYou've already chosen the best response.0\[u= 5x+1\div 2\sqrt{x}\]

roselin
 2 years ago
Best ResponseYou've already chosen the best response.0so i must use the power rule?

mark_o.
 2 years ago
Best ResponseYou've already chosen the best response.0arrange them like \[u=5x +(\frac{ 1 }{ 2 })(\frac{ 1 }{ x ^{\frac{ 1 }{ 2 }} })\]

mark_o.
 2 years ago
Best ResponseYou've already chosen the best response.0lets try to work only on 1/x^1/2

roselin
 2 years ago
Best ResponseYou've already chosen the best response.0where did u get the v from?

mark_o.
 2 years ago
Best ResponseYou've already chosen the best response.0if you are using the quotient rule Dx(U/V)

roselin
 2 years ago
Best ResponseYou've already chosen the best response.0wait the quotient rule is dw:1351568697070:dw

roselin
 2 years ago
Best ResponseYou've already chosen the best response.0that is the quotient rule right?

mark_o.
 2 years ago
Best ResponseYou've already chosen the best response.0lets try to work only on 1/x^1/2 therefore Dx(U/V)=Dx( 1/x^1/2) so here u=1 and v=x^1/2

mark_o.
 2 years ago
Best ResponseYou've already chosen the best response.0yes on youR formula g=V..,f=u , its the same..you guys have taught f and g but variables such u,v, w are used also locally and internationally

mark_o.
 2 years ago
Best ResponseYou've already chosen the best response.0ok try to use your formula and you will arrive with the same answer anyway

roselin
 2 years ago
Best ResponseYou've already chosen the best response.0i am solving it here, give me a minute i will post what i have

mark_o.
 2 years ago
Best ResponseYou've already chosen the best response.0ok take your time..lol.. :D

mark_o.
 2 years ago
Best ResponseYou've already chosen the best response.0hm try to study this one let u=1 and v= x^1/2 Dx(1/(x)^1/2) x^1/2(Dx(1)  1 Dx(x^1/2) =  ( x^1/2)^2 0  (1/2)x^1/2 =  x (1/2) =  x x^1/2 (1/2) = x^3/2 1 =  2 x^3/2

mark_o.
 2 years ago
Best ResponseYou've already chosen the best response.0now lets go back to the prob derivative of u=5x+(1/2)( x)^1/2 1 du/dx= 5   2( 2x^3/2) 1 = 5  4x^3/2 w/c is the same as doing it w/ power rule
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