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mark_o.Best ResponseYou've already chosen the best response.0
derivative of u=5x+(1/2) sqrt of x sometimes its easier to use the power rule, and rewriting it as u=5x+(1/2 )( x)^1/2 use power rule of the derivative
 one year ago

mark_o.Best ResponseYou've already chosen the best response.0
d(kx)/dx=k.,,dx^n/dx= nx^n1
 one year ago

roselinBest ResponseYou've already chosen the best response.0
the problem is actually: dw:1351567010524:dw
 one year ago

roselinBest ResponseYou've already chosen the best response.0
\[u= 5x+1\div 2\sqrt{x}\]
 one year ago

mark_o.Best ResponseYou've already chosen the best response.0
it will be the same idea by using the power rule u=5x + 1/(2sqrtx) u=5x + (1/2)(x)^1/2 now find the derivative
 one year ago

roselinBest ResponseYou've already chosen the best response.0
what if i use the quotient rule?
 one year ago

mark_o.Best ResponseYou've already chosen the best response.0
u=5x + (1/2)(x)^1/2 is it du/dt=5+(1/2)(1/2)x^1/2  2/2) du/dt=5+(1/2)(1/2)x^3/2 ) ?
 one year ago

roselinBest ResponseYou've already chosen the best response.0
its find the derivative of the function \[u= 5x+1 \div \sqrt{2}\]
 one year ago

mark_o.Best ResponseYou've already chosen the best response.0
ok the quotient rule says \[\frac{ d(\frac{ U }{ V }) }{ dx }=\frac{ V \frac{ du }{ dx }U \frac{ dV }{ dx } }{ v ^{2} }\]
 one year ago

roselinBest ResponseYou've already chosen the best response.0
\[u= 5x+1\div 2\sqrt{x}\]
 one year ago

roselinBest ResponseYou've already chosen the best response.0
so i must use the power rule?
 one year ago

mark_o.Best ResponseYou've already chosen the best response.0
arrange them like \[u=5x +(\frac{ 1 }{ 2 })(\frac{ 1 }{ x ^{\frac{ 1 }{ 2 }} })\]
 one year ago

mark_o.Best ResponseYou've already chosen the best response.0
lets try to work only on 1/x^1/2
 one year ago

roselinBest ResponseYou've already chosen the best response.0
where did u get the v from?
 one year ago

mark_o.Best ResponseYou've already chosen the best response.0
if you are using the quotient rule Dx(U/V)
 one year ago

roselinBest ResponseYou've already chosen the best response.0
wait the quotient rule is dw:1351568697070:dw
 one year ago

roselinBest ResponseYou've already chosen the best response.0
that is the quotient rule right?
 one year ago

mark_o.Best ResponseYou've already chosen the best response.0
lets try to work only on 1/x^1/2 therefore Dx(U/V)=Dx( 1/x^1/2) so here u=1 and v=x^1/2
 one year ago

mark_o.Best ResponseYou've already chosen the best response.0
yes on youR formula g=V..,f=u , its the same..you guys have taught f and g but variables such u,v, w are used also locally and internationally
 one year ago

mark_o.Best ResponseYou've already chosen the best response.0
ok try to use your formula and you will arrive with the same answer anyway
 one year ago

roselinBest ResponseYou've already chosen the best response.0
i am solving it here, give me a minute i will post what i have
 one year ago

mark_o.Best ResponseYou've already chosen the best response.0
ok take your time..lol.. :D
 one year ago

mark_o.Best ResponseYou've already chosen the best response.0
hm try to study this one let u=1 and v= x^1/2 Dx(1/(x)^1/2) x^1/2(Dx(1)  1 Dx(x^1/2) =  ( x^1/2)^2 0  (1/2)x^1/2 =  x (1/2) =  x x^1/2 (1/2) = x^3/2 1 =  2 x^3/2
 one year ago

mark_o.Best ResponseYou've already chosen the best response.0
now lets go back to the prob derivative of u=5x+(1/2)( x)^1/2 1 du/dx= 5   2( 2x^3/2) 1 = 5  4x^3/2 w/c is the same as doing it w/ power rule
 one year ago
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