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etemplin Group TitleBest ResponseYou've already chosen the best response.0
do you know derivatives?
 2 years ago

burhan101 Group TitleBest ResponseYou've already chosen the best response.0
we have to complete the square
 2 years ago

burhan101 Group TitleBest ResponseYou've already chosen the best response.0
would it be \[\huge 4x^2+4x4+41 \] for the first step of completing the square ?
 2 years ago

burhan101 Group TitleBest ResponseYou've already chosen the best response.0
then \[\huge 4 (x1)^2 1\] ? :S
 2 years ago

etemplin Group TitleBest ResponseYou've already chosen the best response.0
when you multiply that out it doesnt give you 4x^2+4x4+41
 2 years ago

etemplin Group TitleBest ResponseYou've already chosen the best response.0
try this one 4(x+(1/2))^2 2
 2 years ago

burhan101 Group TitleBest ResponseYou've already chosen the best response.0
i dont get where the 1/2 comes from :S
 2 years ago

etemplin Group TitleBest ResponseYou've already chosen the best response.0
i found the error: the leading coefficient must be 1 to complete the square try setting it equal to 0, moving the 1 over, and dividing by 4 then complete the square
 2 years ago

burhan101 Group TitleBest ResponseYou've already chosen the best response.0
why does it have to be 1 ?
 2 years ago

etemplin Group TitleBest ResponseYou've already chosen the best response.0
because thats what the formula says
 2 years ago

burhan101 Group TitleBest ResponseYou've already chosen the best response.0
oh so it applies at all equations ?
 2 years ago

etemplin Group TitleBest ResponseYou've already chosen the best response.0
it applies to quadratics with a leading coefficient of 1
 2 years ago

burhan101 Group TitleBest ResponseYou've already chosen the best response.0
dw:1351571054966:dw
 2 years ago

etemplin Group TitleBest ResponseYou've already chosen the best response.0
that works move the 1/4 over divide the middle term by 2 and square it add that answer to both sides factor
 2 years ago

etemplin Group TitleBest ResponseYou've already chosen the best response.0
*by middle term, i meant the coefficient with the x^1
 2 years ago

burhan101 Group TitleBest ResponseYou've already chosen the best response.0
what do you mean by move the 1/4 over ? like why
 2 years ago

etemplin Group TitleBest ResponseYou've already chosen the best response.0
because thats what the formula says to do you'll end up with x^2+x=(1/4) the term with x is 1 (1/2)^2 = 1/4 add (1/4) to both sides end up with x^2+x+(1/4) = (1/2) factor into (x+(1/2))^2 = (1/2) solve for x
 2 years ago

burhan101 Group TitleBest ResponseYou've already chosen the best response.0
dw:1351571511476:dw
 2 years ago

etemplin Group TitleBest ResponseYou've already chosen the best response.0
yes now factor the left side
 2 years ago
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