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anonymous
 3 years ago
Increasing and decreasing intervals of 4x^2+4x1
anonymous
 3 years ago
Increasing and decreasing intervals of 4x^2+4x1

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anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0do you know derivatives?

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0we have to complete the square

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0would it be \[\huge 4x^2+4x4+41 \] for the first step of completing the square ?

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0then \[\huge 4 (x1)^2 1\] ? :S

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0when you multiply that out it doesnt give you 4x^2+4x4+41

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0try this one 4(x+(1/2))^2 2

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0i dont get where the 1/2 comes from :S

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0i found the error: the leading coefficient must be 1 to complete the square try setting it equal to 0, moving the 1 over, and dividing by 4 then complete the square

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0why does it have to be 1 ?

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0because thats what the formula says

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0oh so it applies at all equations ?

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0it applies to quadratics with a leading coefficient of 1

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0dw:1351571054966:dw

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0that works move the 1/4 over divide the middle term by 2 and square it add that answer to both sides factor

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0*by middle term, i meant the coefficient with the x^1

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0what do you mean by move the 1/4 over ? like why

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0because thats what the formula says to do you'll end up with x^2+x=(1/4) the term with x is 1 (1/2)^2 = 1/4 add (1/4) to both sides end up with x^2+x+(1/4) = (1/2) factor into (x+(1/2))^2 = (1/2) solve for x

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0dw:1351571511476:dw

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0yes now factor the left side
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