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Increasing and decreasing intervals of 4x^2+4x-1

Mathematics
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do you know derivatives?
we have to complete the square
would it be \[\huge 4x^2+4x-4+4-1 \] for the first step of completing the square ?

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Other answers:

yes
then \[\huge 4 (x-1)^2 -1\] ? :S
when you multiply that out it doesnt give you 4x^2+4x-4+4-1
try this one 4(x+(1/2))^2 -2
i dont get where the 1/2 comes from :S
i found the error: the leading coefficient must be 1 to complete the square try setting it equal to 0, moving the -1 over, and dividing by 4 then complete the square
why does it have to be 1 ?
because thats what the formula says
oh so it applies at all equations ?
it applies to quadratics with a leading coefficient of 1
|dw:1351571054966:dw|
that works move the -1/4 over divide the middle term by 2 and square it add that answer to both sides factor
*by middle term, i meant the coefficient with the x^1
what do you mean by move the -1/4 over ? like why
because thats what the formula says to do you'll end up with x^2+x=(1/4) the term with x is 1 (1/2)^2 = 1/4 add (1/4) to both sides end up with x^2+x+(1/4) = (1/2) factor into (x+(1/2))^2 = (1/2) solve for x
|dw:1351571511476:dw|
yes now factor the left side

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