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etemplin Group TitleBest ResponseYou've already chosen the best response.0
do you know derivatives?
 one year ago

burhan101 Group TitleBest ResponseYou've already chosen the best response.0
we have to complete the square
 one year ago

burhan101 Group TitleBest ResponseYou've already chosen the best response.0
would it be \[\huge 4x^2+4x4+41 \] for the first step of completing the square ?
 one year ago

burhan101 Group TitleBest ResponseYou've already chosen the best response.0
then \[\huge 4 (x1)^2 1\] ? :S
 one year ago

etemplin Group TitleBest ResponseYou've already chosen the best response.0
when you multiply that out it doesnt give you 4x^2+4x4+41
 one year ago

etemplin Group TitleBest ResponseYou've already chosen the best response.0
try this one 4(x+(1/2))^2 2
 one year ago

burhan101 Group TitleBest ResponseYou've already chosen the best response.0
i dont get where the 1/2 comes from :S
 one year ago

etemplin Group TitleBest ResponseYou've already chosen the best response.0
i found the error: the leading coefficient must be 1 to complete the square try setting it equal to 0, moving the 1 over, and dividing by 4 then complete the square
 one year ago

burhan101 Group TitleBest ResponseYou've already chosen the best response.0
why does it have to be 1 ?
 one year ago

etemplin Group TitleBest ResponseYou've already chosen the best response.0
because thats what the formula says
 one year ago

burhan101 Group TitleBest ResponseYou've already chosen the best response.0
oh so it applies at all equations ?
 one year ago

etemplin Group TitleBest ResponseYou've already chosen the best response.0
it applies to quadratics with a leading coefficient of 1
 one year ago

burhan101 Group TitleBest ResponseYou've already chosen the best response.0
dw:1351571054966:dw
 one year ago

etemplin Group TitleBest ResponseYou've already chosen the best response.0
that works move the 1/4 over divide the middle term by 2 and square it add that answer to both sides factor
 one year ago

etemplin Group TitleBest ResponseYou've already chosen the best response.0
*by middle term, i meant the coefficient with the x^1
 one year ago

burhan101 Group TitleBest ResponseYou've already chosen the best response.0
what do you mean by move the 1/4 over ? like why
 one year ago

etemplin Group TitleBest ResponseYou've already chosen the best response.0
because thats what the formula says to do you'll end up with x^2+x=(1/4) the term with x is 1 (1/2)^2 = 1/4 add (1/4) to both sides end up with x^2+x+(1/4) = (1/2) factor into (x+(1/2))^2 = (1/2) solve for x
 one year ago

burhan101 Group TitleBest ResponseYou've already chosen the best response.0
dw:1351571511476:dw
 one year ago

etemplin Group TitleBest ResponseYou've already chosen the best response.0
yes now factor the left side
 one year ago
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