A community for students.
Here's the question you clicked on:
 0 viewing
burhan101
 2 years ago
Increasing and decreasing intervals of 4x^2+4x1
burhan101
 2 years ago
Increasing and decreasing intervals of 4x^2+4x1

This Question is Closed

etemplin
 2 years ago
Best ResponseYou've already chosen the best response.0do you know derivatives?

burhan101
 2 years ago
Best ResponseYou've already chosen the best response.0we have to complete the square

burhan101
 2 years ago
Best ResponseYou've already chosen the best response.0would it be \[\huge 4x^2+4x4+41 \] for the first step of completing the square ?

burhan101
 2 years ago
Best ResponseYou've already chosen the best response.0then \[\huge 4 (x1)^2 1\] ? :S

etemplin
 2 years ago
Best ResponseYou've already chosen the best response.0when you multiply that out it doesnt give you 4x^2+4x4+41

etemplin
 2 years ago
Best ResponseYou've already chosen the best response.0try this one 4(x+(1/2))^2 2

burhan101
 2 years ago
Best ResponseYou've already chosen the best response.0i dont get where the 1/2 comes from :S

etemplin
 2 years ago
Best ResponseYou've already chosen the best response.0i found the error: the leading coefficient must be 1 to complete the square try setting it equal to 0, moving the 1 over, and dividing by 4 then complete the square

burhan101
 2 years ago
Best ResponseYou've already chosen the best response.0why does it have to be 1 ?

etemplin
 2 years ago
Best ResponseYou've already chosen the best response.0because thats what the formula says

burhan101
 2 years ago
Best ResponseYou've already chosen the best response.0oh so it applies at all equations ?

etemplin
 2 years ago
Best ResponseYou've already chosen the best response.0it applies to quadratics with a leading coefficient of 1

burhan101
 2 years ago
Best ResponseYou've already chosen the best response.0dw:1351571054966:dw

etemplin
 2 years ago
Best ResponseYou've already chosen the best response.0that works move the 1/4 over divide the middle term by 2 and square it add that answer to both sides factor

etemplin
 2 years ago
Best ResponseYou've already chosen the best response.0*by middle term, i meant the coefficient with the x^1

burhan101
 2 years ago
Best ResponseYou've already chosen the best response.0what do you mean by move the 1/4 over ? like why

etemplin
 2 years ago
Best ResponseYou've already chosen the best response.0because thats what the formula says to do you'll end up with x^2+x=(1/4) the term with x is 1 (1/2)^2 = 1/4 add (1/4) to both sides end up with x^2+x+(1/4) = (1/2) factor into (x+(1/2))^2 = (1/2) solve for x

burhan101
 2 years ago
Best ResponseYou've already chosen the best response.0dw:1351571511476:dw

etemplin
 2 years ago
Best ResponseYou've already chosen the best response.0yes now factor the left side
Ask your own question
Sign UpFind more explanations on OpenStudy
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.