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ConDawg

  • 2 years ago

(2x^2tan(x))/sec(x) find f ' (x) and f ' (3)

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  1. ConDawg
    • 2 years ago
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    Answer is 2 x (x cos(x)+2 sin(x)), I just don't know how to do it

  2. ConDawg
    • 2 years ago
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    okay I got cha

  3. 3psilon
    • 2 years ago
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    it gets a little messy

  4. ConDawg
    • 2 years ago
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    What do you do after you get the numerator?

  5. 3psilon
    • 2 years ago
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    Actually forget what I said. Just use the quotient rule

  6. ConDawg
    • 2 years ago
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    (4x)(tan(x))-(2x^2)(sec(x^2)) derivative of tan(x) = sec(x)^2

  7. ConDawg
    • 2 years ago
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    is that right for the numerator?

  8. 3psilon
    • 2 years ago
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    \[\frac{ \sec(x)(2x^{2}\sec^{2}x+4xtanx)- 2x^{2} \tan(x)\tan(x)\sec(x) }{ \sec^{2}x }\]

  9. 3psilon
    • 2 years ago
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    That's when it is in quotient rule form. As I said . it does get messy :/

  10. ConDawg
    • 2 years ago
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    Wow... sorry it took long to reply, the website isn't working well for me.

  11. ConDawg
    • 2 years ago
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    m trying to follow what you got and how you got it with the formula, i'm just learning the quotient rule

  12. 3psilon
    • 2 years ago
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    The quotient rule is low d(high) - high d(low) all over Low low or low^2

  13. 3psilon
    • 2 years ago
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    high is the numerator and low is the denominator when there is a d next to it that means the derivative

  14. 3psilon
    • 2 years ago
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    In this case the d(high) involved the product rule that's why it got so messy

  15. ConDawg
    • 2 years ago
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    okay im following now. Goodness this hard on the head... so first we found out what the numerator is from the product rule, and then we use the quotient rule

  16. 3psilon
    • 2 years ago
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    Just take it one step at a time :) Use the quotient rule for the whole thing. But you'll come across product rule inside it

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