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ConDawg
 2 years ago
(2x^2tan(x))/sec(x)
find f ' (x)
and f ' (3)
ConDawg
 2 years ago
(2x^2tan(x))/sec(x) find f ' (x) and f ' (3)

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ConDawg
 2 years ago
Best ResponseYou've already chosen the best response.0Answer is 2 x (x cos(x)+2 sin(x)), I just don't know how to do it

ConDawg
 2 years ago
Best ResponseYou've already chosen the best response.0What do you do after you get the numerator?

3psilon
 2 years ago
Best ResponseYou've already chosen the best response.0Actually forget what I said. Just use the quotient rule

ConDawg
 2 years ago
Best ResponseYou've already chosen the best response.0(4x)(tan(x))(2x^2)(sec(x^2)) derivative of tan(x) = sec(x)^2

ConDawg
 2 years ago
Best ResponseYou've already chosen the best response.0is that right for the numerator?

3psilon
 2 years ago
Best ResponseYou've already chosen the best response.0\[\frac{ \sec(x)(2x^{2}\sec^{2}x+4xtanx) 2x^{2} \tan(x)\tan(x)\sec(x) }{ \sec^{2}x }\]

3psilon
 2 years ago
Best ResponseYou've already chosen the best response.0That's when it is in quotient rule form. As I said . it does get messy :/

ConDawg
 2 years ago
Best ResponseYou've already chosen the best response.0Wow... sorry it took long to reply, the website isn't working well for me.

ConDawg
 2 years ago
Best ResponseYou've already chosen the best response.0m trying to follow what you got and how you got it with the formula, i'm just learning the quotient rule

3psilon
 2 years ago
Best ResponseYou've already chosen the best response.0The quotient rule is low d(high)  high d(low) all over Low low or low^2

3psilon
 2 years ago
Best ResponseYou've already chosen the best response.0high is the numerator and low is the denominator when there is a d next to it that means the derivative

3psilon
 2 years ago
Best ResponseYou've already chosen the best response.0In this case the d(high) involved the product rule that's why it got so messy

ConDawg
 2 years ago
Best ResponseYou've already chosen the best response.0okay im following now. Goodness this hard on the head... so first we found out what the numerator is from the product rule, and then we use the quotient rule

3psilon
 2 years ago
Best ResponseYou've already chosen the best response.0Just take it one step at a time :) Use the quotient rule for the whole thing. But you'll come across product rule inside it
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