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ConDawg Group Title

(2x^2tan(x))/sec(x) find f ' (x) and f ' (3)

  • 2 years ago
  • 2 years ago

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  1. ConDawg Group Title
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    Answer is 2 x (x cos(x)+2 sin(x)), I just don't know how to do it

    • 2 years ago
  2. ConDawg Group Title
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    okay I got cha

    • 2 years ago
  3. 3psilon Group Title
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    it gets a little messy

    • 2 years ago
  4. ConDawg Group Title
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    What do you do after you get the numerator?

    • 2 years ago
  5. 3psilon Group Title
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    Actually forget what I said. Just use the quotient rule

    • 2 years ago
  6. ConDawg Group Title
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    (4x)(tan(x))-(2x^2)(sec(x^2)) derivative of tan(x) = sec(x)^2

    • 2 years ago
  7. ConDawg Group Title
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    is that right for the numerator?

    • 2 years ago
  8. 3psilon Group Title
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    \[\frac{ \sec(x)(2x^{2}\sec^{2}x+4xtanx)- 2x^{2} \tan(x)\tan(x)\sec(x) }{ \sec^{2}x }\]

    • 2 years ago
  9. 3psilon Group Title
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    That's when it is in quotient rule form. As I said . it does get messy :/

    • 2 years ago
  10. ConDawg Group Title
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    Wow... sorry it took long to reply, the website isn't working well for me.

    • 2 years ago
  11. ConDawg Group Title
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    m trying to follow what you got and how you got it with the formula, i'm just learning the quotient rule

    • 2 years ago
  12. 3psilon Group Title
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    The quotient rule is low d(high) - high d(low) all over Low low or low^2

    • 2 years ago
  13. 3psilon Group Title
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    high is the numerator and low is the denominator when there is a d next to it that means the derivative

    • 2 years ago
  14. 3psilon Group Title
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    In this case the d(high) involved the product rule that's why it got so messy

    • 2 years ago
  15. ConDawg Group Title
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    okay im following now. Goodness this hard on the head... so first we found out what the numerator is from the product rule, and then we use the quotient rule

    • 2 years ago
  16. 3psilon Group Title
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    Just take it one step at a time :) Use the quotient rule for the whole thing. But you'll come across product rule inside it

    • 2 years ago
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