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Qaisersatti
Group Title
Homework 9
Pt 1 (ii,iii & v)
Pt 2 (iv,v,vii) any help please
 one year ago
 one year ago
Qaisersatti Group Title
Homework 9 Pt 1 (ii,iii & v) Pt 2 (iv,v,vii) any help please
 one year ago
 one year ago

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Nurali Group TitleBest ResponseYou've already chosen the best response.0
Question 1 2. 70 3. 70 5. 219.9 Question 2 didn't Complete please tell me answer of question 2 i,ii,iii,vi
 one year ago

Nurali Group TitleBest ResponseYou've already chosen the best response.0
if correct please click best response
 one year ago

Jose.oliveira2 Group TitleBest ResponseYou've already chosen the best response.3
H9P1 0.250122093132 7.5 7.5 0 23.5619449019 0 0 0 H9P2 L*C L/R 1 HELP Help (1/R)*sqrt(L/C) HELP H9P3 b/(2*m) 1/(sqrt(m*1/k)) 1/(2*pi*sqrt(m*1/k)) (2*m)/(sqrt(m*(1/k)))
 one year ago

Jose.oliveira2 Group TitleBest ResponseYou've already chosen the best response.3
Reviwe H9P1 a) 0.250122093132 b) 7.5 c) 7.5 d) 0 e) 23.5619449019 f) 0 g) 0 h) 0 H9P2 a) L*C b) L/R c) 1 d) sqrt(1/(L*C))/(2*pi) e) 1/(2*R*C) f) (1/R)*sqrt(L/C) g) 2*sqrt(L/C) H9P3 a) b/(2*m) b) 1/(sqrt(m*1/k)) c) 1/(2*pi*sqrt(m*1/k)) d) (2*m)/(sqrt(m*(1/k)))
 one year ago

olimpiacaj Group TitleBest ResponseYou've already chosen the best response.0
At the time just before the impulse happens what is the current iL(5.0−), in Amperes, through the inductor? Equation???
 one year ago

Jose.oliveira2 Group TitleBest ResponseYou've already chosen the best response.3
iL(t) = A*cos(2*pi*f*t) + B*sin(2*pi*f*t) vC(t) = L*diL/dt = L*2*pi*f*(A*sin(2*pi*f*t) + B * cos(2*pi*f*t)) The initial conditions mean that A = 1, and B = 0, (in my case) So, iL (t) = cos(2*pi*f*t), vC (t) = L*2*pi*f*sin(2*pi*f*t) iL(5) = cos(2*pi*0.25*5) = cos(2.5*pi) = 0. If you have another values, change only.
 one year ago

Qaisersatti Group TitleBest ResponseYou've already chosen the best response.0
My Q No 1 (ii,iii & v) is not coming correct can anyone comment. The current source puts out an impulse of area A=2/π=0.64 Coulombs at time t=5.0s. At t=0 the state is: vC(0)=0.0 and iL(0)=1.0. The equation governing the evolution of the inductor current in this circuit is d2iL(t)dt2+1LCiL(t)=ALCδ(t−5.0) (ii) At the initial time what is the total energy, in Joules, stored in the circuit? (iii) At the time just before the impulse happens t=5.0− what is the total energy, in Joules, stored in the circuit? (v) At the time just before the impulse happens what is the voltage vC(5.0−), in Volts, across the capacitor? please comment...
 one year ago

Jose.oliveira2 Group TitleBest ResponseYou've already chosen the best response.3
Thats the same values and questions in my, i don´t know what happens.
 one year ago

Jose.oliveira2 Group TitleBest ResponseYou've already chosen the best response.3
try this energy stored=½*L*iL^2 (b and c) vC(t) = L*2*pi*f*sin(2*pi*f*t) for (e)
 one year ago

Qaisersatti Group TitleBest ResponseYou've already chosen the best response.0
@Jose.oliveira2 thanks brother its already done...thanks
 one year ago
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