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mathew0135
 2 years ago
Check whether the series defined below is convergent and if so, find its sum.
mathew0135
 2 years ago
Check whether the series defined below is convergent and if so, find its sum.

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mathew0135
 2 years ago
Best ResponseYou've already chosen the best response.0\[\sum_{n=1}^{\infty} \frac{ 2^n }{ (12)^{n1} }\] and the equation.

zordoloom
 2 years ago
Best ResponseYou've already chosen the best response.0What math class is this for?

etemplin
 2 years ago
Best ResponseYou've already chosen the best response.0likely calc 2, because i just had a test on this

zordoloom
 2 years ago
Best ResponseYou've already chosen the best response.0BTW, this series converges.

mathew0135
 2 years ago
Best ResponseYou've already chosen the best response.0Math 1B in Australia (presumably similar to calc 2 from what i've seen).

zordoloom
 2 years ago
Best ResponseYou've already chosen the best response.0ok, the sum will also be 12/5

mathew0135
 2 years ago
Best ResponseYou've already chosen the best response.0thanks, good to know but how do you work that out?

zordoloom
 2 years ago
Best ResponseYou've already chosen the best response.0Take the limit as n goes to infinity.

mathew0135
 2 years ago
Best ResponseYou've already chosen the best response.0thus far i've found the absolute value, then tried to find the limit as it approaches infinity. That's what i believe you do.

zordoloom
 2 years ago
Best ResponseYou've already chosen the best response.0Ya. That would be correct. So, the form is an+1/an

zordoloom
 2 years ago
Best ResponseYou've already chosen the best response.0And you plug in the formula that you have into this equation.

zordoloom
 2 years ago
Best ResponseYou've already chosen the best response.0(2^n+1)/(12^(n+1)(1)) all over (2^n)/(12^(n1))

mathew0135
 2 years ago
Best ResponseYou've already chosen the best response.0okay so because the is to a higher power the limit is equal to 0 and thus converges. Hate to ask but how do you find the sum. Think you tried to explain it there but i'm still a bit confused. does: ((2^n+1)/(12^(n+1)(1)))/((2^n)/(12^(n1))) find me the sum when n=1?
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