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\[\sum_{n=1}^{\infty} \frac{ 2^n }{ (-12)^{n-1} }\]
and the equation.

What math class is this for?

likely calc 2, because i just had a test on this

BTW, this series converges.

Math 1B in Australia (presumably similar to calc 2 from what i've seen).

ok, the sum will also be -12/5

thanks, good to know but how do you work that out?

Take the limit as n goes to infinity.

Ya. That would be correct. So, the form is an+1/an

And you plug in the formula that you have into this equation.

-(2^n+1)/(12^(n+1)(-1)) all over (2^n)/(-12^(n-1))