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mathew0135
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Check whether the series defined below is convergent and if so, find its sum.
 2 years ago
 2 years ago
mathew0135 Group Title
Check whether the series defined below is convergent and if so, find its sum.
 2 years ago
 2 years ago

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mathew0135 Group TitleBest ResponseYou've already chosen the best response.0
\[\sum_{n=1}^{\infty} \frac{ 2^n }{ (12)^{n1} }\] and the equation.
 2 years ago

zordoloom Group TitleBest ResponseYou've already chosen the best response.0
What math class is this for?
 2 years ago

etemplin Group TitleBest ResponseYou've already chosen the best response.0
likely calc 2, because i just had a test on this
 2 years ago

zordoloom Group TitleBest ResponseYou've already chosen the best response.0
BTW, this series converges.
 2 years ago

mathew0135 Group TitleBest ResponseYou've already chosen the best response.0
Math 1B in Australia (presumably similar to calc 2 from what i've seen).
 2 years ago

zordoloom Group TitleBest ResponseYou've already chosen the best response.0
ok, the sum will also be 12/5
 2 years ago

mathew0135 Group TitleBest ResponseYou've already chosen the best response.0
thanks, good to know but how do you work that out?
 2 years ago

zordoloom Group TitleBest ResponseYou've already chosen the best response.0
Take the limit as n goes to infinity.
 2 years ago

mathew0135 Group TitleBest ResponseYou've already chosen the best response.0
thus far i've found the absolute value, then tried to find the limit as it approaches infinity. That's what i believe you do.
 2 years ago

zordoloom Group TitleBest ResponseYou've already chosen the best response.0
Ya. That would be correct. So, the form is an+1/an
 2 years ago

zordoloom Group TitleBest ResponseYou've already chosen the best response.0
And you plug in the formula that you have into this equation.
 2 years ago

zordoloom Group TitleBest ResponseYou've already chosen the best response.0
(2^n+1)/(12^(n+1)(1)) all over (2^n)/(12^(n1))
 2 years ago

mathew0135 Group TitleBest ResponseYou've already chosen the best response.0
okay so because the is to a higher power the limit is equal to 0 and thus converges. Hate to ask but how do you find the sum. Think you tried to explain it there but i'm still a bit confused. does: ((2^n+1)/(12^(n+1)(1)))/((2^n)/(12^(n1))) find me the sum when n=1?
 2 years ago
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