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mskyeg
Group Title
The equation h=16t^2 + 32t +9 gives the height of a ball, h, in feet above the ground, at t seconds after the ball is thrown upward. How many seconds after the ball is thrown will it reach maximum height? What is its maximum height?
 2 years ago
 2 years ago
mskyeg Group Title
The equation h=16t^2 + 32t +9 gives the height of a ball, h, in feet above the ground, at t seconds after the ball is thrown upward. How many seconds after the ball is thrown will it reach maximum height? What is its maximum height?
 2 years ago
 2 years ago

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etemplin Group TitleBest ResponseYou've already chosen the best response.1
the vertex of any parabola is given by (b/(2a)) the value of this is how many seconds plug this value into the equation to get the max height
 2 years ago

etemplin Group TitleBest ResponseYou've already chosen the best response.1
yes h=25 t=1
 2 years ago

mskyeg Group TitleBest ResponseYou've already chosen the best response.1
cool thanks:)
 2 years ago

mskyeg Group TitleBest ResponseYou've already chosen the best response.1
I figured out i wanted to check cause it is important thank you very much
 2 years ago
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