Got Homework?
Connect with other students for help. It's a free community.
Here's the question you clicked on:
 0 viewing
Locust_Grub
Group Title
PLS HELP BEEN STUCK FOR HOURS ON THIS.
Starting from 1.5 miles away, a car drives toward a speed checkpoint and then passes it. The car travels at a constant rate of 53 miles per hour. The distance of the car from the checkpoint is given by d = 1.5 – 53t. At what times is the car 0.1 miles from the checkpoint? Calculate your answer in seconds. (1 point)95.1s and 108.7s
10.2s and 101.9s108.7s and 10.2s95.1s and 10.2s
 one year ago
 one year ago
Locust_Grub Group Title
PLS HELP BEEN STUCK FOR HOURS ON THIS. Starting from 1.5 miles away, a car drives toward a speed checkpoint and then passes it. The car travels at a constant rate of 53 miles per hour. The distance of the car from the checkpoint is given by d = 1.5 – 53t. At what times is the car 0.1 miles from the checkpoint? Calculate your answer in seconds. (1 point)95.1s and 108.7s 10.2s and 101.9s108.7s and 10.2s95.1s and 10.2s
 one year ago
 one year ago

This Question is Closed

Girly17 Group TitleBest ResponseYou've already chosen the best response.0
AHhhh i have been too): i did steps and i still dont get it. Im from connexus
 one year ago

03225186213 Group TitleBest ResponseYou've already chosen the best response.0
dw:1351580898467:dw
 one year ago

Locust_Grub Group TitleBest ResponseYou've already chosen the best response.0
WRONG ALL OF YOU
 one year ago

Girly17 Group TitleBest ResponseYou've already chosen the best response.0
ok check this out bruh. this is what i first did. I subtracted 1.5 from both sides of this equation. 1.553t=0.1 and i got 1.4 then i divided 1.4/5.3 and i got 0.026415(etc) NEED HELP
 one year ago

Locust_Grub Group TitleBest ResponseYou've already chosen the best response.0
:P ANSWER THE TOPIC QUESTION MY BRAINS ABOUT TO BLOW
 one year ago

Girly17 Group TitleBest ResponseYou've already chosen the best response.0
LMAO I AGREE IVE BEEN SITTIN ON MY retriceFOR 4 HOURS MAN
 one year ago

Fellowroot Group TitleBest ResponseYou've already chosen the best response.0
I have t=0.026 and t=0.030 Does anyone else agree?
 one year ago

Hero Group TitleBest ResponseYou've already chosen the best response.0
d = 1.5 – 53t 0.1 = (1.5  53t) 0.1 = 1.5  53t 0.1 =53t  1.5 1.5 + 0.1 = 53t 1.6/53 = t t = 108.67 secs 53t = 1.5  0.1 53t = 1.4 t = 1.4/53 t = 95.09 secs
 one year ago

Girly17 Group TitleBest ResponseYou've already chosen the best response.0
fellow i got the same on these two equations i just did
 one year ago

Girly17 Group TitleBest ResponseYou've already chosen the best response.0
so 0.026 and 0.030 is correct? hero
 one year ago

Hero Group TitleBest ResponseYou've already chosen the best response.0
I don't know where you get that from. It wants in seconds
 one year ago

Hero Group TitleBest ResponseYou've already chosen the best response.0
In hours, yes, that is correct
 one year ago

Girly17 Group TitleBest ResponseYou've already chosen the best response.0
wait nvm. gotcha. thanks!;)
 one year ago

Hero Group TitleBest ResponseYou've already chosen the best response.0
I don't know why it took you four hours
 one year ago

Hero Group TitleBest ResponseYou've already chosen the best response.0
@Girly17, I help you with a question and you block me and call me a weirdo? Thanks
 one year ago

Fellowroot Group TitleBest ResponseYou've already chosen the best response.0
Yeah, double checked I got it. You can solve this problem in 2 ways. 1st way by pure math abs( anything ) = something means anything =+something and/or anything =something and solve for t also you can think of this as a physics problem with zero acceleration, deduce your position function and find the times at the desired distances.
 one year ago

Hero Group TitleBest ResponseYou've already chosen the best response.0
I solved it the "easiest" way
 one year ago

Girly17 Group TitleBest ResponseYou've already chosen the best response.0
calm down calm down you were rude and said post it like everyone else. well look here yo i woulda done that but i couldnt find how to do that so i seen send a message thing and it was easier for me.
 one year ago

Girly17 Group TitleBest ResponseYou've already chosen the best response.0
took me 4 hours cuz im awesome like that
 one year ago

Hero Group TitleBest ResponseYou've already chosen the best response.0
I wasn't being rude. I was trying to explain to you that it is inconvenient to help you in the messages.
 one year ago

Hero Group TitleBest ResponseYou've already chosen the best response.0
Messages are not for posting questions.
 one year ago

Hero Group TitleBest ResponseYou've already chosen the best response.0
Anyone else would tell you the same thing
 one year ago

Girly17 Group TitleBest ResponseYou've already chosen the best response.0
which means you took it the wrong way, how are the inconvenient? lets see.
 one year ago

Girly17 Group TitleBest ResponseYou've already chosen the best response.0
and how was i suppose to know?!?!?!?!?!?!?!?!
 one year ago

Hero Group TitleBest ResponseYou've already chosen the best response.0
You didn't know, but I was explaining to you. That's all I can try to do is communicate with you and explain to you. All you have to do is not overreact.
 one year ago

Girly17 Group TitleBest ResponseYou've already chosen the best response.0
i am not overreacting. you're just giving me bs. but wtvr goodnight and thanks
 one year ago
See more questions >>>
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.