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anonymous
 3 years ago
PLS HELP BEEN STUCK FOR HOURS ON THIS.
Starting from 1.5 miles away, a car drives toward a speed checkpoint and then passes it. The car travels at a constant rate of 53 miles per hour. The distance of the car from the checkpoint is given by d = 1.5 – 53t. At what times is the car 0.1 miles from the checkpoint? Calculate your answer in seconds. (1 point)95.1s and 108.7s
10.2s and 101.9s108.7s and 10.2s95.1s and 10.2s
anonymous
 3 years ago
PLS HELP BEEN STUCK FOR HOURS ON THIS. Starting from 1.5 miles away, a car drives toward a speed checkpoint and then passes it. The car travels at a constant rate of 53 miles per hour. The distance of the car from the checkpoint is given by d = 1.5 – 53t. At what times is the car 0.1 miles from the checkpoint? Calculate your answer in seconds. (1 point)95.1s and 108.7s 10.2s and 101.9s108.7s and 10.2s95.1s and 10.2s

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anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0AHhhh i have been too): i did steps and i still dont get it. Im from connexus

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0dw:1351580898467:dw

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0ok check this out bruh. this is what i first did. I subtracted 1.5 from both sides of this equation. 1.553t=0.1 and i got 1.4 then i divided 1.4/5.3 and i got 0.026415(etc) NEED HELP

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0:P ANSWER THE TOPIC QUESTION MY BRAINS ABOUT TO BLOW

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0LMAO I AGREE IVE BEEN SITTIN ON MY retriceFOR 4 HOURS MAN

Fellowroot
 3 years ago
Best ResponseYou've already chosen the best response.0I have t=0.026 and t=0.030 Does anyone else agree?

Hero
 3 years ago
Best ResponseYou've already chosen the best response.0d = 1.5 – 53t 0.1 = (1.5  53t) 0.1 = 1.5  53t 0.1 =53t  1.5 1.5 + 0.1 = 53t 1.6/53 = t t = 108.67 secs 53t = 1.5  0.1 53t = 1.4 t = 1.4/53 t = 95.09 secs

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0fellow i got the same on these two equations i just did

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0so 0.026 and 0.030 is correct? hero

Hero
 3 years ago
Best ResponseYou've already chosen the best response.0I don't know where you get that from. It wants in seconds

Hero
 3 years ago
Best ResponseYou've already chosen the best response.0In hours, yes, that is correct

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0wait nvm. gotcha. thanks!;)

Hero
 3 years ago
Best ResponseYou've already chosen the best response.0I don't know why it took you four hours

Hero
 3 years ago
Best ResponseYou've already chosen the best response.0@Girly17, I help you with a question and you block me and call me a weirdo? Thanks

Fellowroot
 3 years ago
Best ResponseYou've already chosen the best response.0Yeah, double checked I got it. You can solve this problem in 2 ways. 1st way by pure math abs( anything ) = something means anything =+something and/or anything =something and solve for t also you can think of this as a physics problem with zero acceleration, deduce your position function and find the times at the desired distances.

Hero
 3 years ago
Best ResponseYou've already chosen the best response.0I solved it the "easiest" way

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0calm down calm down you were rude and said post it like everyone else. well look here yo i woulda done that but i couldnt find how to do that so i seen send a message thing and it was easier for me.

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0took me 4 hours cuz im awesome like that

Hero
 3 years ago
Best ResponseYou've already chosen the best response.0I wasn't being rude. I was trying to explain to you that it is inconvenient to help you in the messages.

Hero
 3 years ago
Best ResponseYou've already chosen the best response.0Messages are not for posting questions.

Hero
 3 years ago
Best ResponseYou've already chosen the best response.0Anyone else would tell you the same thing

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0which means you took it the wrong way, how are the inconvenient? lets see.

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0and how was i suppose to know?!?!?!?!?!?!?!?!

Hero
 3 years ago
Best ResponseYou've already chosen the best response.0You didn't know, but I was explaining to you. That's all I can try to do is communicate with you and explain to you. All you have to do is not overreact.

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0i am not overreacting. you're just giving me bs. but wtvr goodnight and thanks
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