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12/2= 6 6/2=3
n is 2
i didnt get u
when u divide n by 12 you get a remainder of 6 right. so what number do you divide from 12 to get 6
what ur not understanding you need to find what n is
n/12 = 6 n = 72 therefore; 72/6 = 12
take an integer K...then we can write n as n=12*K+6....K can be changed depending on n...so now we divide n by 6 thats (12*K+6)/6=2K+1...remainder is 0
If the quotient is a whole number, then the remainder is obviously 0... I was showing how to find that out
note that 12K+6...always leaves a remainder 6 when divided by 12..this is the genaral form of the integer n
what if the quotient is not a whole no.?
then u have a remainder not equal to 0
So n = 78
n=12*k+6..as i mentioned...k is any integer...so put k=1,2,3.....and u 'll get diff values of n
did u make up the ques..?...the ques is wrong..
i just want to know that if the quotient is not a whole no.then what wud be the solution of that question?
look...if the quetiont is not a whole number.. then u have a remainder...thats all...example..114/12...12*9=108..u have remainder 6..so the quo. is..9+(6/12)...thats 9.5 not awhole num...but 8/4....we have 4*2=8..rem=0...so quo=2+(0/4)=2..whole number
Examples: 12/5 leaves a remainder of 2. (12+4)/5 leaves a remainder of 1.
(x^3 - 2x^2 + 4x - 2)/(x-3) leaves a remainder of 19.
i got it thanku