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edr1c
 3 years ago
laurent series expansion?
edr1c
 3 years ago
laurent series expansion?

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edr1c
 3 years ago
Best ResponseYou've already chosen the best response.0\[f(z)=\frac{ 1 }{ z(z1)^{2} }\]

edr1c
 3 years ago
Best ResponseYou've already chosen the best response.0expanding about the point z=1, let u=z1 then z=u+1 \[f(z)=\frac{ 1 }{ (u+1)u ^{2} }=\frac{ 1 }{ u ^{2} }\frac{ 1 }{ 1(u) }\]\[f(z)=\frac{ 1 }{ u ^{2} }\sum_{n=0}^{\infty}(1)^{n}(u)^{n}\]\[f(z)=\frac{ 1 }{ (z1) ^{2} }\sum_{n=0}^{\infty}(1)^{n}(z1)^{n}\]\[f(z)=\sum_{n=0}^{\infty}\frac{ (1)^{n} }{ (z1)^{n1} }\]my steps correct for z=1?

edr1c
 3 years ago
Best ResponseYou've already chosen the best response.0(z1)^n2 for the denominator*
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