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\[f(z)=\frac{ z }{ (z-1)(2-z) }\]

oh kay i think i know where i went wrong.

start with partial fractions i think

you get
\[\frac{1}{z-1}-\frac{2}{z-2}\]

yep

oops now i got stuck, i am not getting the right thing

ouh substitution after the partial fraction works.

second part is \(\frac{2}{1+(1-z)}\) right?

yea

yes, i believe so

oh kay thx alot =)

oh wait i am confusing myself. it is \(|z-1|>1\) not less than
that is why you need to flip it