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morganalana17
Group Title
hey i need help solving...
4a2b+c=24
ab+c=13
9a+3b+c=9
can anyone help me with this
 2 years ago
 2 years ago
morganalana17 Group Title
hey i need help solving... 4a2b+c=24 ab+c=13 9a+3b+c=9 can anyone help me with this
 2 years ago
 2 years ago

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Kaji Group TitleBest ResponseYou've already chosen the best response.0
Is this factoring?
 2 years ago

morganalana17 Group TitleBest ResponseYou've already chosen the best response.0
no it wants me to solve it and turn it into a quadratic
 2 years ago

BurrDaBoss Group TitleBest ResponseYou've already chosen the best response.0
so you need the amount of the variables ?
 2 years ago

ajprincess Group TitleBest ResponseYou've already chosen the best response.0
4a2b+c=24(1) ab+c=13(2) 9a+3b+c=9(3) Let us eliminate c from equations (1) and (2). To do that subtract equation (2) from equation (1). (1)(2)=> 4a2b+c(ab+c)=2413 4a2b+ca+bc=11 3ab=11(4) Similarly let us eliminate c from equations (2) and (3). To do that subtract equation (2) from equation (3). (3)(2)=> 9a+3b+c(ab+c)=913 9a+3b+ca+bc=4 8a+4b=4(5) Nw take the equations (4) and (5). 3ab=11(4) 8a+4b=4(5) Let us eliminate b from both the equations. To do that we need to multiply equation (4) by 4. Then we will get (4)*4=> 4(3ab)=4*11 12a4b=44(6) Nw add both equations (5) and (6) (5)+(6)=> 8a+4b+12a4b=4+44 20a=40 Solve for a. Then plug in that value of a in 3ab=11 to find b. Then plug in the values of a and b in ab+c=13 to find c. Can u find them @morganalana17?
 2 years ago
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