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morganalana17
Group Title
hey i need help solving...
4a2b+c=24
ab+c=13
9a+3b+c=9
can anyone help me with this
 one year ago
 one year ago
morganalana17 Group Title
hey i need help solving... 4a2b+c=24 ab+c=13 9a+3b+c=9 can anyone help me with this
 one year ago
 one year ago

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Kaji Group TitleBest ResponseYou've already chosen the best response.0
Is this factoring?
 one year ago

morganalana17 Group TitleBest ResponseYou've already chosen the best response.0
no it wants me to solve it and turn it into a quadratic
 one year ago

BurrDaBoss Group TitleBest ResponseYou've already chosen the best response.0
so you need the amount of the variables ?
 one year ago

ajprincess Group TitleBest ResponseYou've already chosen the best response.0
4a2b+c=24(1) ab+c=13(2) 9a+3b+c=9(3) Let us eliminate c from equations (1) and (2). To do that subtract equation (2) from equation (1). (1)(2)=> 4a2b+c(ab+c)=2413 4a2b+ca+bc=11 3ab=11(4) Similarly let us eliminate c from equations (2) and (3). To do that subtract equation (2) from equation (3). (3)(2)=> 9a+3b+c(ab+c)=913 9a+3b+ca+bc=4 8a+4b=4(5) Nw take the equations (4) and (5). 3ab=11(4) 8a+4b=4(5) Let us eliminate b from both the equations. To do that we need to multiply equation (4) by 4. Then we will get (4)*4=> 4(3ab)=4*11 12a4b=44(6) Nw add both equations (5) and (6) (5)+(6)=> 8a+4b+12a4b=4+44 20a=40 Solve for a. Then plug in that value of a in 3ab=11 to find b. Then plug in the values of a and b in ab+c=13 to find c. Can u find them @morganalana17?
 one year ago
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