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anonymous
 4 years ago
wondering if someone will walk me through how to do this problem:
anonymous
 4 years ago
wondering if someone will walk me through how to do this problem:

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anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Use the appropriate rule or combination of rules to find the derivative of the function defined below. \[y=\sec^2(t^21)\]

hartnn
 4 years ago
Best ResponseYou've already chosen the best response.2first can u find the derivative of sec^2 x ?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0well to the power of 2x i guess.

hartnn
 4 years ago
Best ResponseYou've already chosen the best response.2to the power of 2x ? u know chain rule, right ? what is derivative of x^2 first ?

hartnn
 4 years ago
Best ResponseYou've already chosen the best response.2its 2x, right, so derivative of sec^2 x = ?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.02x(sec)*(sec2xtan2x) ??

hartnn
 4 years ago
Best ResponseYou've already chosen the best response.2applying chain rule, u get \((sec^2x)' = 2sec\: x(sec\: x)'=2sec \:x(sec\:xtan\:x)\) got this ?

hartnn
 4 years ago
Best ResponseYou've already chosen the best response.2so now can u apply chain rule again and find it for your question ?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0i was just confused how you just had sec^2x wrote down is all, i thought you meant to the power of 2x, not sec^2(x)

hartnn
 4 years ago
Best ResponseYou've already chosen the best response.2oh, sorry for confusion again....

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0haha its okay, theres just no x's present in the question is all.

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0so now i have: \[\sec^2(2t)+(t^21)(2)(\sec^2)(sectan)\]

hartnn
 4 years ago
Best ResponseYou've already chosen the best response.2how sec^2 2t? the angle doesn't change...

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0im using the product rule.

hartnn
 4 years ago
Best ResponseYou've already chosen the best response.2\([sec^2(t^21)]'= 2sec (t^21)[sec(t^21)]'\) got this step ?

hartnn
 4 years ago
Best ResponseYou've already chosen the best response.2now next step would be ?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0to use thechain rule on [sec(t2−1)

hartnn
 4 years ago
Best ResponseYou've already chosen the best response.2yes! precisely it would be sec(t^21)tan(t^21)(2t)

hartnn
 4 years ago
Best ResponseYou've already chosen the best response.2so final answe would be ?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0so now i have: \[2\sec(t^21)*\sec(t^21)\tan(t^21)(2t)\]

hartnn
 4 years ago
Best ResponseYou've already chosen the best response.2correct! than can be simplified to \(2\sec^2(t^21)*\tan(t^21)(2t)\)

hartnn
 4 years ago
Best ResponseYou've already chosen the best response.2\(4t\sec^2(t^21)*\tan(t^21)\)

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0so that's my final answer? : )

hartnn
 4 years ago
Best ResponseYou've already chosen the best response.2but, did u get all steps ?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0can i write that as: \[4t*\sec(t^21)^2*\tan(t^21)\]

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0i wrote them all down : ) i get them now, it's not as hard when i got someone explaining it to me hah.

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0can i write it like that though???

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0should there be a *t at the end of the equation?
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