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bmelykBest ResponseYou've already chosen the best response.1
Use the appropriate rule or combination of rules to find the derivative of the function defined below. \[y=\sec^2(t^21)\]
 one year ago

hartnnBest ResponseYou've already chosen the best response.2
first can u find the derivative of sec^2 x ?
 one year ago

bmelykBest ResponseYou've already chosen the best response.1
well to the power of 2x i guess.
 one year ago

hartnnBest ResponseYou've already chosen the best response.2
to the power of 2x ? u know chain rule, right ? what is derivative of x^2 first ?
 one year ago

hartnnBest ResponseYou've already chosen the best response.2
its 2x, right, so derivative of sec^2 x = ?
 one year ago

bmelykBest ResponseYou've already chosen the best response.1
2x(sec)*(sec2xtan2x) ??
 one year ago

hartnnBest ResponseYou've already chosen the best response.2
applying chain rule, u get \((sec^2x)' = 2sec\: x(sec\: x)'=2sec \:x(sec\:xtan\:x)\) got this ?
 one year ago

hartnnBest ResponseYou've already chosen the best response.2
so now can u apply chain rule again and find it for your question ?
 one year ago

bmelykBest ResponseYou've already chosen the best response.1
i was just confused how you just had sec^2x wrote down is all, i thought you meant to the power of 2x, not sec^2(x)
 one year ago

hartnnBest ResponseYou've already chosen the best response.2
oh, sorry for confusion again....
 one year ago

bmelykBest ResponseYou've already chosen the best response.1
haha its okay, theres just no x's present in the question is all.
 one year ago

bmelykBest ResponseYou've already chosen the best response.1
so now i have: \[\sec^2(2t)+(t^21)(2)(\sec^2)(sectan)\]
 one year ago

hartnnBest ResponseYou've already chosen the best response.2
how sec^2 2t? the angle doesn't change...
 one year ago

bmelykBest ResponseYou've already chosen the best response.1
im using the product rule.
 one year ago

hartnnBest ResponseYou've already chosen the best response.2
\([sec^2(t^21)]'= 2sec (t^21)[sec(t^21)]'\) got this step ?
 one year ago

hartnnBest ResponseYou've already chosen the best response.2
now next step would be ?
 one year ago

bmelykBest ResponseYou've already chosen the best response.1
to use thechain rule on [sec(t2−1)
 one year ago

hartnnBest ResponseYou've already chosen the best response.2
yes! precisely it would be sec(t^21)tan(t^21)(2t)
 one year ago

hartnnBest ResponseYou've already chosen the best response.2
so final answe would be ?
 one year ago

bmelykBest ResponseYou've already chosen the best response.1
so now i have: \[2\sec(t^21)*\sec(t^21)\tan(t^21)(2t)\]
 one year ago

hartnnBest ResponseYou've already chosen the best response.2
correct! than can be simplified to \(2\sec^2(t^21)*\tan(t^21)(2t)\)
 one year ago

hartnnBest ResponseYou've already chosen the best response.2
\(4t\sec^2(t^21)*\tan(t^21)\)
 one year ago

bmelykBest ResponseYou've already chosen the best response.1
so that's my final answer? : )
 one year ago

hartnnBest ResponseYou've already chosen the best response.2
but, did u get all steps ?
 one year ago

bmelykBest ResponseYou've already chosen the best response.1
can i write that as: \[4t*\sec(t^21)^2*\tan(t^21)\]
 one year ago

bmelykBest ResponseYou've already chosen the best response.1
i wrote them all down : ) i get them now, it's not as hard when i got someone explaining it to me hah.
 one year ago

bmelykBest ResponseYou've already chosen the best response.1
can i write it like that though???
 one year ago

bmelykBest ResponseYou've already chosen the best response.1
should there be a *t at the end of the equation?
 one year ago
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