Ace school

with brainly

  • Get help from millions of students
  • Learn from experts with step-by-step explanations
  • Level-up by helping others

A community for students.

About Session 9, Clip 3 on product rule. At about 6 min. 8 sec into the video, the professor says that he introduced u(v(x+∆x) which he didn't like. However, the formula until then reads (u(x+∆x)-u(x))v(x+∆x), so the u in u(v(x+∆x) doesn't concern v(x+∆x) but belongs to (u(x+∆x)-u(x)) as is indicated by the brackets. He later introduced +u(x)v(x+∆x) to cancel for something that actually was not there in the first place. Although it ends up as it should, I cannot follow the explantion provided. The explanation in the lecture notes seems more logical. Did I miss something?

OCW Scholar - Single Variable Calculus
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

Join Brainly to access

this expert answer

SIGN UP FOR FREE
Can you give a website address?
Dear Stacey, Sorry it took a few days. The address is http://ocw.mit.edu/courses/mathematics/18-01sc-single-variable-calculus-fall-2010/part-a-definition-and-basic-rules/session-9-product-rule/ from the course 18-01sc single variable calculus with kind regards Frank

Not the answer you are looking for?

Search for more explanations.

Ask your own question

Other answers:

Not the answer you are looking for?

Search for more explanations.

Ask your own question