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bmelykBest ResponseYou've already chosen the best response.1
Use the appropriate rule or combination of rules to find the derivative of the function defined below. y=\[(16x4)\sqrt{8x2}\]
 one year ago

bmelykBest ResponseYou've already chosen the best response.1
i know i have to use my product rule, when i do that i get: (16x4)(1/2)(8x2)^1/2 + (8x2)^1/2 *16
 one year ago

hartnnBest ResponseYou've already chosen the best response.0
u forgot chain rule for (8x2)
 one year ago

bmelykBest ResponseYou've already chosen the best response.1
oh times 8 in there lol. i had that wrote down, lol just forgot to type it.
 one year ago

bmelykBest ResponseYou've already chosen the best response.1
okay so that i got: \[\frac{ 4(16x4) }{ \sqrt{8x2} }+16\sqrt{8x2}\]
 one year ago

bmelykBest ResponseYou've already chosen the best response.1
would i take my 4 out of the numerator so i got 16(4x1) ?
 one year ago

hartnnBest ResponseYou've already chosen the best response.0
thats not much of a simplification, but u can !
 one year ago

bmelykBest ResponseYou've already chosen the best response.1
is tehre a way to further simplify this> my answer isn't matching any of the answers on my assingment (this one is a multiple choice)
 one year ago

hartnnBest ResponseYou've already chosen the best response.0
what are the options ? u can factor out 16 from both the terms..
 one year ago

bmelykBest ResponseYou've already chosen the best response.1
a) 16 4/squrt8x2 B)16(squrt8x2)+32 times 16x4/squrt8x2 c)1616/squrt8x2 d)64/squrt8x2 e)32*2^1/2*x^1/2 16*2^1/2+(164x)/squrt8x2 f)8*csgn(4x1)*2^1/2 g)16*squrt8x2+4(16x4/squrt8x2) h)8(16x4)(squrt8x2)
 one year ago

hartnnBest ResponseYou've already chosen the best response.0
ohh, u can crossmultiply to get the common denominator as \(\sqrt{}8x2\)
 one year ago

bmelykBest ResponseYou've already chosen the best response.1
so then i have\[4(16x4)+16\sqrt{8x2}(\sqrt{8x2})\]
 one year ago

hartnnBest ResponseYou've already chosen the best response.0
which is? \(\sqrt{8x2}\sqrt{8x2}=8x2\)
 one year ago

bmelykBest ResponseYou've already chosen the best response.1
i had 320x16 as my numerator but that's not there as an answer either.
 one year ago

hartnnBest ResponseYou've already chosen the best response.0
checking, wait..your c option is weird...1616=0
 one year ago

bmelykBest ResponseYou've already chosen the best response.1
\[16\frac{ 16 }{ \sqrt{8x2} }\]
 one year ago

bmelykBest ResponseYou've already chosen the best response.1
that's what it actually is, it's a little weird when i wrote it the other way lol..
 one year ago

ChlorophyllBest ResponseYou've already chosen the best response.0
My answer's the denom. cancel out! However the way your post the option too complicated to read !!!
 one year ago

bmelykBest ResponseYou've already chosen the best response.1
how did your answer look? i can rewrite them out.
 one year ago

bmelykBest ResponseYou've already chosen the best response.1
\[a) 16\frac{ 4 }{ \sqrt{8x2} }\]
 one year ago

bmelykBest ResponseYou've already chosen the best response.1
\[b) 16\sqrt{8x2}+32*\frac{ 16x4 }{ \sqrt{8x2} }\]
 one year ago

bmelykBest ResponseYou've already chosen the best response.1
\[c)16\frac{ 16 }{ 8x2 }\]
 one year ago

bmelykBest ResponseYou've already chosen the best response.1
\[d)\frac{ 64 }{ \sqrt{8x2} }\]
 one year ago

bmelykBest ResponseYou've already chosen the best response.1
\[e) 32*2^{\frac{ 1 }{ 2 }}*x^\frac{ 1 }{ 2 }16*2^\frac{ 1 }{ 2 }+(16x4)*\frac{ 2^\frac{ 1 }{ 2 } }{ x \frac{ 1 }{ 2 } }\]
 one year ago

bmelykBest ResponseYou've already chosen the best response.1
\[f)8*csgn(4x1)*2^\frac{ 1 }{ 2 }\]
 one year ago

bmelykBest ResponseYou've already chosen the best response.1
\[g)16\sqrt{8x2}+4\frac{ 164x }{ \sqrt{8x2}}\]
 one year ago

bmelykBest ResponseYou've already chosen the best response.1
\[h)8(164x)(\sqrt{8x2}\]
 one year ago

hartnnBest ResponseYou've already chosen the best response.0
isn't g) option the same thing what we got ?
 one year ago

bmelykBest ResponseYou've already chosen the best response.1
if you wanna check out my lastest/last question that would be great!
 one year ago

ChlorophyllBest ResponseYou've already chosen the best response.0
So it turns out that there's no need to simplified =)
 one year ago

bmelykBest ResponseYou've already chosen the best response.1
i had the right answer all along haha.
 one year ago

bmelykBest ResponseYou've already chosen the best response.1
http://openstudy.com/study#/updates/50902c28e4b043900ad9134d please : )
 one year ago
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