anonymous
  • anonymous
just wondering how to proceed with this problem.
Calculus1
  • Stacey Warren - Expert brainly.com
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SOLVED
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jamiebookeater
  • jamiebookeater
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anonymous
  • anonymous
Use the appropriate rule or combination of rules to find the derivative of the function defined below. y=\[(16x-4)\sqrt{8x-2}\]
anonymous
  • anonymous
i know i have to use my product rule, when i do that i get: (16x-4)(1/2)(8x-2)^-1/2 + (8x-2)^1/2 *16
hartnn
  • hartnn
u forgot chain rule for (8x-2)

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anonymous
  • anonymous
oh times 8 in there lol. i had that wrote down, lol just forgot to type it.
hartnn
  • hartnn
then u are correct
anonymous
  • anonymous
okay so that i got: \[\frac{ 4(16x-4) }{ \sqrt{8x-2} }+16\sqrt{8x-2}\]
hartnn
  • hartnn
absolutely correct!
anonymous
  • anonymous
would i take my 4 out of the numerator so i got 16(4x-1) ?
hartnn
  • hartnn
thats not much of a simplification, but u can !
anonymous
  • anonymous
is tehre a way to further simplify this> my answer isn't matching any of the answers on my assingment (this one is a multiple choice)
hartnn
  • hartnn
what are the options ? u can factor out 16 from both the terms..
anonymous
  • anonymous
a) 16- 4/squrt8x-2 B)16(squrt8x-2)+32 times 16x-4/squrt8x-2 c)16-16/squrt8x-2 d)64/squrt8x-2 e)32*2^1/2*x^1/2 -16*2^1/2+(16-4x)/squrt8x-2 f)8*csgn(4x-1)*2^1/2 g)16*squrt8x-2+4(16x-4/squrt8x-2) h)8(16x-4)(squrt8x-2)
hartnn
  • hartnn
ohh, u can cross-multiply to get the common denominator as \(\sqrt{}8x-2\)
anonymous
  • anonymous
so then i have\[4(16x-4)+16\sqrt{8x-2}(\sqrt{8x-2})\]
anonymous
  • anonymous
??
hartnn
  • hartnn
which is? \(\sqrt{8x-2}\sqrt{8x-2}=8x-2\)
anonymous
  • anonymous
i had 320x-16 as my numerator but that's not there as an answer either.
anonymous
  • anonymous
is the answer c?
hartnn
  • hartnn
checking, wait..your c option is weird...16-16=0
anonymous
  • anonymous
\[16-\frac{ 16 }{ \sqrt{8x-2} }\]
anonymous
  • anonymous
that's what it actually is, it's a little weird when i wrote it the other way lol..
anonymous
  • anonymous
so is that right tho?
anonymous
  • anonymous
My answer's the denom. cancel out! However the way your post the option too complicated to read !!!
anonymous
  • anonymous
how did your answer look? i can re-write them out.
anonymous
  • anonymous
\[a) 16-\frac{ 4 }{ \sqrt{8x-2} }\]
anonymous
  • anonymous
= 24 √ ( 8x -1)
anonymous
  • anonymous
\[b) 16\sqrt{8x-2}+32*\frac{ 16x-4 }{ \sqrt{8x-2} }\]
anonymous
  • anonymous
\[c)16-\frac{ 16 }{ 8x-2 }\]
anonymous
  • anonymous
\[d)\frac{ 64 }{ \sqrt{8x-2} }\]
anonymous
  • anonymous
\[e) 32*2^{\frac{ 1 }{ 2 }}*x^\frac{ 1 }{ 2 }-16*2^\frac{ 1 }{ 2 }+(16x-4)*\frac{ 2^\frac{ 1 }{ 2 } }{ x \frac{ 1 }{ 2 } }\]
anonymous
  • anonymous
\[f)8*csgn(4x-1)*2^\frac{ 1 }{ 2 }\]
anonymous
  • anonymous
are you sure?
anonymous
  • anonymous
\[g)16\sqrt{8x-2}+4\frac{ 16-4x }{ \sqrt{8x-2}}\]
anonymous
  • anonymous
no idea hah.
anonymous
  • anonymous
\[h)8(16-4x)(\sqrt{8x-2}\]
hartnn
  • hartnn
isn't g) option the same thing what we got ?
anonymous
  • anonymous
omg.. look at that.
anonymous
  • anonymous
hhaha so it is!!!
anonymous
  • anonymous
if you wanna check out my lastest/last question that would be great!
anonymous
  • anonymous
So it turns out that there's no need to simplified =)
anonymous
  • anonymous
i had the right answer all along haha.

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