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bmelyk
 2 years ago
Best ResponseYou've already chosen the best response.1Use the appropriate rule or combination of rules to find the derivative of the function defined below. y=\[(16x4)\sqrt{8x2}\]

bmelyk
 2 years ago
Best ResponseYou've already chosen the best response.1i know i have to use my product rule, when i do that i get: (16x4)(1/2)(8x2)^1/2 + (8x2)^1/2 *16

hartnn
 2 years ago
Best ResponseYou've already chosen the best response.0u forgot chain rule for (8x2)

bmelyk
 2 years ago
Best ResponseYou've already chosen the best response.1oh times 8 in there lol. i had that wrote down, lol just forgot to type it.

bmelyk
 2 years ago
Best ResponseYou've already chosen the best response.1okay so that i got: \[\frac{ 4(16x4) }{ \sqrt{8x2} }+16\sqrt{8x2}\]

bmelyk
 2 years ago
Best ResponseYou've already chosen the best response.1would i take my 4 out of the numerator so i got 16(4x1) ?

hartnn
 2 years ago
Best ResponseYou've already chosen the best response.0thats not much of a simplification, but u can !

bmelyk
 2 years ago
Best ResponseYou've already chosen the best response.1is tehre a way to further simplify this> my answer isn't matching any of the answers on my assingment (this one is a multiple choice)

hartnn
 2 years ago
Best ResponseYou've already chosen the best response.0what are the options ? u can factor out 16 from both the terms..

bmelyk
 2 years ago
Best ResponseYou've already chosen the best response.1a) 16 4/squrt8x2 B)16(squrt8x2)+32 times 16x4/squrt8x2 c)1616/squrt8x2 d)64/squrt8x2 e)32*2^1/2*x^1/2 16*2^1/2+(164x)/squrt8x2 f)8*csgn(4x1)*2^1/2 g)16*squrt8x2+4(16x4/squrt8x2) h)8(16x4)(squrt8x2)

hartnn
 2 years ago
Best ResponseYou've already chosen the best response.0ohh, u can crossmultiply to get the common denominator as \(\sqrt{}8x2\)

bmelyk
 2 years ago
Best ResponseYou've already chosen the best response.1so then i have\[4(16x4)+16\sqrt{8x2}(\sqrt{8x2})\]

hartnn
 2 years ago
Best ResponseYou've already chosen the best response.0which is? \(\sqrt{8x2}\sqrt{8x2}=8x2\)

bmelyk
 2 years ago
Best ResponseYou've already chosen the best response.1i had 320x16 as my numerator but that's not there as an answer either.

hartnn
 2 years ago
Best ResponseYou've already chosen the best response.0checking, wait..your c option is weird...1616=0

bmelyk
 2 years ago
Best ResponseYou've already chosen the best response.1\[16\frac{ 16 }{ \sqrt{8x2} }\]

bmelyk
 2 years ago
Best ResponseYou've already chosen the best response.1that's what it actually is, it's a little weird when i wrote it the other way lol..

Chlorophyll
 2 years ago
Best ResponseYou've already chosen the best response.0My answer's the denom. cancel out! However the way your post the option too complicated to read !!!

bmelyk
 2 years ago
Best ResponseYou've already chosen the best response.1how did your answer look? i can rewrite them out.

bmelyk
 2 years ago
Best ResponseYou've already chosen the best response.1\[a) 16\frac{ 4 }{ \sqrt{8x2} }\]

bmelyk
 2 years ago
Best ResponseYou've already chosen the best response.1\[b) 16\sqrt{8x2}+32*\frac{ 16x4 }{ \sqrt{8x2} }\]

bmelyk
 2 years ago
Best ResponseYou've already chosen the best response.1\[c)16\frac{ 16 }{ 8x2 }\]

bmelyk
 2 years ago
Best ResponseYou've already chosen the best response.1\[d)\frac{ 64 }{ \sqrt{8x2} }\]

bmelyk
 2 years ago
Best ResponseYou've already chosen the best response.1\[e) 32*2^{\frac{ 1 }{ 2 }}*x^\frac{ 1 }{ 2 }16*2^\frac{ 1 }{ 2 }+(16x4)*\frac{ 2^\frac{ 1 }{ 2 } }{ x \frac{ 1 }{ 2 } }\]

bmelyk
 2 years ago
Best ResponseYou've already chosen the best response.1\[f)8*csgn(4x1)*2^\frac{ 1 }{ 2 }\]

bmelyk
 2 years ago
Best ResponseYou've already chosen the best response.1\[g)16\sqrt{8x2}+4\frac{ 164x }{ \sqrt{8x2}}\]

bmelyk
 2 years ago
Best ResponseYou've already chosen the best response.1\[h)8(164x)(\sqrt{8x2}\]

hartnn
 2 years ago
Best ResponseYou've already chosen the best response.0isn't g) option the same thing what we got ?

bmelyk
 2 years ago
Best ResponseYou've already chosen the best response.1if you wanna check out my lastest/last question that would be great!

Chlorophyll
 2 years ago
Best ResponseYou've already chosen the best response.0So it turns out that there's no need to simplified =)

bmelyk
 2 years ago
Best ResponseYou've already chosen the best response.1i had the right answer all along haha.

bmelyk
 2 years ago
Best ResponseYou've already chosen the best response.1http://openstudy.com/study#/updates/50902c28e4b043900ad9134d please : )
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