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bmelyk Group Title

just wondering how to proceed with this problem.

  • 2 years ago
  • 2 years ago

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  1. bmelyk Group Title
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    Use the appropriate rule or combination of rules to find the derivative of the function defined below. y=\[(16x-4)\sqrt{8x-2}\]

    • 2 years ago
  2. bmelyk Group Title
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    i know i have to use my product rule, when i do that i get: (16x-4)(1/2)(8x-2)^-1/2 + (8x-2)^1/2 *16

    • 2 years ago
  3. hartnn Group Title
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    u forgot chain rule for (8x-2)

    • 2 years ago
  4. bmelyk Group Title
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    oh times 8 in there lol. i had that wrote down, lol just forgot to type it.

    • 2 years ago
  5. hartnn Group Title
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    then u are correct

    • 2 years ago
  6. bmelyk Group Title
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    okay so that i got: \[\frac{ 4(16x-4) }{ \sqrt{8x-2} }+16\sqrt{8x-2}\]

    • 2 years ago
  7. hartnn Group Title
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    absolutely correct!

    • 2 years ago
  8. bmelyk Group Title
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    would i take my 4 out of the numerator so i got 16(4x-1) ?

    • 2 years ago
  9. hartnn Group Title
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    thats not much of a simplification, but u can !

    • 2 years ago
  10. bmelyk Group Title
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    is tehre a way to further simplify this> my answer isn't matching any of the answers on my assingment (this one is a multiple choice)

    • 2 years ago
  11. hartnn Group Title
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    what are the options ? u can factor out 16 from both the terms..

    • 2 years ago
  12. bmelyk Group Title
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    a) 16- 4/squrt8x-2 B)16(squrt8x-2)+32 times 16x-4/squrt8x-2 c)16-16/squrt8x-2 d)64/squrt8x-2 e)32*2^1/2*x^1/2 -16*2^1/2+(16-4x)/squrt8x-2 f)8*csgn(4x-1)*2^1/2 g)16*squrt8x-2+4(16x-4/squrt8x-2) h)8(16x-4)(squrt8x-2)

    • 2 years ago
  13. hartnn Group Title
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    ohh, u can cross-multiply to get the common denominator as \(\sqrt{}8x-2\)

    • 2 years ago
  14. bmelyk Group Title
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    so then i have\[4(16x-4)+16\sqrt{8x-2}(\sqrt{8x-2})\]

    • 2 years ago
  15. bmelyk Group Title
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    ??

    • 2 years ago
  16. hartnn Group Title
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    which is? \(\sqrt{8x-2}\sqrt{8x-2}=8x-2\)

    • 2 years ago
  17. bmelyk Group Title
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    i had 320x-16 as my numerator but that's not there as an answer either.

    • 2 years ago
  18. bmelyk Group Title
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    is the answer c?

    • 2 years ago
  19. hartnn Group Title
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    checking, wait..your c option is weird...16-16=0

    • 2 years ago
  20. bmelyk Group Title
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    \[16-\frac{ 16 }{ \sqrt{8x-2} }\]

    • 2 years ago
  21. bmelyk Group Title
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    that's what it actually is, it's a little weird when i wrote it the other way lol..

    • 2 years ago
  22. bmelyk Group Title
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    so is that right tho?

    • 2 years ago
  23. Chlorophyll Group Title
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    My answer's the denom. cancel out! However the way your post the option too complicated to read !!!

    • 2 years ago
  24. bmelyk Group Title
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    how did your answer look? i can re-write them out.

    • 2 years ago
  25. bmelyk Group Title
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    \[a) 16-\frac{ 4 }{ \sqrt{8x-2} }\]

    • 2 years ago
  26. Chlorophyll Group Title
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    = 24 √ ( 8x -1)

    • 2 years ago
  27. bmelyk Group Title
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    \[b) 16\sqrt{8x-2}+32*\frac{ 16x-4 }{ \sqrt{8x-2} }\]

    • 2 years ago
  28. bmelyk Group Title
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    \[c)16-\frac{ 16 }{ 8x-2 }\]

    • 2 years ago
  29. bmelyk Group Title
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    \[d)\frac{ 64 }{ \sqrt{8x-2} }\]

    • 2 years ago
  30. bmelyk Group Title
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    \[e) 32*2^{\frac{ 1 }{ 2 }}*x^\frac{ 1 }{ 2 }-16*2^\frac{ 1 }{ 2 }+(16x-4)*\frac{ 2^\frac{ 1 }{ 2 } }{ x \frac{ 1 }{ 2 } }\]

    • 2 years ago
  31. bmelyk Group Title
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    \[f)8*csgn(4x-1)*2^\frac{ 1 }{ 2 }\]

    • 2 years ago
  32. bmelyk Group Title
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    are you sure?

    • 2 years ago
  33. bmelyk Group Title
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    \[g)16\sqrt{8x-2}+4\frac{ 16-4x }{ \sqrt{8x-2}}\]

    • 2 years ago
  34. bmelyk Group Title
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    no idea hah.

    • 2 years ago
  35. bmelyk Group Title
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    \[h)8(16-4x)(\sqrt{8x-2}\]

    • 2 years ago
  36. hartnn Group Title
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    isn't g) option the same thing what we got ?

    • 2 years ago
  37. bmelyk Group Title
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    omg.. look at that.

    • 2 years ago
  38. bmelyk Group Title
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    hhaha so it is!!!

    • 2 years ago
  39. bmelyk Group Title
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    if you wanna check out my lastest/last question that would be great!

    • 2 years ago
  40. Chlorophyll Group Title
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    So it turns out that there's no need to simplified =)

    • 2 years ago
  41. bmelyk Group Title
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    i had the right answer all along haha.

    • 2 years ago
  42. bmelyk Group Title
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    http://openstudy.com/study#/updates/50902c28e4b043900ad9134d please : )

    • 2 years ago
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