bmelyk
just wondering how to proceed with this problem.



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bmelyk
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Use the appropriate rule or combination of rules to find the derivative of the function defined below.
y=\[(16x4)\sqrt{8x2}\]

bmelyk
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i know i have to use my product rule,
when i do that i get: (16x4)(1/2)(8x2)^1/2 + (8x2)^1/2 *16

hartnn
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u forgot chain rule for (8x2)

bmelyk
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oh times 8 in there lol. i had that wrote down, lol just forgot to type it.

hartnn
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then u are correct

bmelyk
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okay so that i got:
\[\frac{ 4(16x4) }{ \sqrt{8x2} }+16\sqrt{8x2}\]

hartnn
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absolutely correct!

bmelyk
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would i take my 4 out of the numerator so i got 16(4x1) ?

hartnn
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thats not much of a simplification, but u can !

bmelyk
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is tehre a way to further simplify this> my answer isn't matching any of the answers on my assingment (this one is a multiple choice)

hartnn
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what are the options ?
u can factor out 16 from both the terms..

bmelyk
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a) 16 4/squrt8x2
B)16(squrt8x2)+32 times 16x4/squrt8x2
c)1616/squrt8x2
d)64/squrt8x2
e)32*2^1/2*x^1/2 16*2^1/2+(164x)/squrt8x2
f)8*csgn(4x1)*2^1/2
g)16*squrt8x2+4(16x4/squrt8x2)
h)8(16x4)(squrt8x2)

hartnn
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ohh, u can crossmultiply to get the common denominator as \(\sqrt{}8x2\)

bmelyk
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so then i have\[4(16x4)+16\sqrt{8x2}(\sqrt{8x2})\]

bmelyk
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??

hartnn
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which is?
\(\sqrt{8x2}\sqrt{8x2}=8x2\)

bmelyk
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i had 320x16 as my numerator but that's not there as an answer either.

bmelyk
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is the answer c?

hartnn
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checking, wait..your c option is weird...1616=0

bmelyk
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\[16\frac{ 16 }{ \sqrt{8x2} }\]

bmelyk
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that's what it actually is, it's a little weird when i wrote it the other way lol..

bmelyk
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so is that right tho?

Chlorophyll
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My answer's the denom. cancel out!
However the way your post the option too complicated to read !!!

bmelyk
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how did your answer look? i can rewrite them out.

bmelyk
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\[a) 16\frac{ 4 }{ \sqrt{8x2} }\]

Chlorophyll
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= 24 √ ( 8x 1)

bmelyk
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\[b) 16\sqrt{8x2}+32*\frac{ 16x4 }{ \sqrt{8x2} }\]

bmelyk
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\[c)16\frac{ 16 }{ 8x2 }\]

bmelyk
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\[d)\frac{ 64 }{ \sqrt{8x2} }\]

bmelyk
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\[e) 32*2^{\frac{ 1 }{ 2 }}*x^\frac{ 1 }{ 2 }16*2^\frac{ 1 }{ 2 }+(16x4)*\frac{ 2^\frac{ 1 }{ 2 } }{ x \frac{ 1 }{ 2 } }\]

bmelyk
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\[f)8*csgn(4x1)*2^\frac{ 1 }{ 2 }\]

bmelyk
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are you sure?

bmelyk
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\[g)16\sqrt{8x2}+4\frac{ 164x }{ \sqrt{8x2}}\]

bmelyk
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no idea hah.

bmelyk
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\[h)8(164x)(\sqrt{8x2}\]

hartnn
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isn't g) option the same thing what we got ?

bmelyk
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omg.. look at that.

bmelyk
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hhaha so it is!!!

bmelyk
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if you wanna check out my lastest/last question that would be great!

Chlorophyll
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So it turns out that there's no need to simplified =)

bmelyk
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i had the right answer all along haha.
