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heathernelly
 3 years ago
kkkkk
heathernelly
 3 years ago
kkkkk

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dpaInc
 3 years ago
Best ResponseYou've already chosen the best response.1can you give me the derivative of f ??

heathernelly
 3 years ago
Best ResponseYou've already chosen the best response.0that's all it says :// :(

dpaInc
 3 years ago
Best ResponseYou've already chosen the best response.1yes... but you need to calculate the derivative of f to find the relative max/min of the function.

dpaInc
 3 years ago
Best ResponseYou've already chosen the best response.1isn't this for a calculus class?

heathernelly
 3 years ago
Best ResponseYou've already chosen the best response.0its okay :) so you don't know how to do it? :(

heathernelly
 3 years ago
Best ResponseYou've already chosen the best response.0i know how to do it on a calculater ..but i left it at a friends house ://

dpaInc
 3 years ago
Best ResponseYou've already chosen the best response.1oh... so you're allowed to use the max/min functions of a graphing calculator?

dpaInc
 3 years ago
Best ResponseYou've already chosen the best response.1since you don't have your graphing calculator with you, use this online one.... https://www.desmos.com/calculator i've also included the graph of your function here:

dpaInc
 3 years ago
Best ResponseYou've already chosen the best response.1it looks like you have a relative max at x=4 and a relative min at x=0

heathernelly
 3 years ago
Best ResponseYou've already chosen the best response.0yeah, but that's not one of my options :(

dpaInc
 3 years ago
Best ResponseYou've already chosen the best response.1the function you gave at the start does not coincide with those choices...

heathernelly
 3 years ago
Best ResponseYou've already chosen the best response.0thats what it says in my homework

dpaInc
 3 years ago
Best ResponseYou've already chosen the best response.1i double checked with this function you gave at the start: \(\large f(x)=x^3+6x^236 \) f has a relative max at x=4 and a relative min at x=0.

dpaInc
 3 years ago
Best ResponseYou've already chosen the best response.1f(4) = 4 so (4, 4) is a relmax f(0) = 36 so (0, 36) is a relmin

heathernelly
 3 years ago
Best ResponseYou've already chosen the best response.0but that's none of the options ://

dpaInc
 3 years ago
Best ResponseYou've already chosen the best response.1i'm sorry.... i'm absolutely sure of my answer here.. even the calculator verifies my answer.... is this the function we started with correct?

heathernelly
 3 years ago
Best ResponseYou've already chosen the best response.0yes it is ..hmm :// :(

heathernelly
 3 years ago
Best ResponseYou've already chosen the best response.0im just going to pick a or b:///.. lol ..thank you for the help though :)

heathernelly
 3 years ago
Best ResponseYou've already chosen the best response.0do you think you could help me with another one?

dpaInc
 3 years ago
Best ResponseYou've already chosen the best response.1there has to be an error in those choices... yw... :)

heathernelly
 3 years ago
Best ResponseYou've already chosen the best response.0What is a cubic polynomial function in standard form with zeros 1, –2, and 2?

dpaInc
 3 years ago
Best ResponseYou've already chosen the best response.1do you know how to multiply out binomials?

heathernelly
 3 years ago
Best ResponseYou've already chosen the best response.0i know i have to write like (x+1)(x2)(x+2)

dpaInc
 3 years ago
Best ResponseYou've already chosen the best response.1standard form for a cubic polynomial is: \(\large y=ax^3+bx^2+cx+d \) where a, b, c, d are real numbers.

dpaInc
 3 years ago
Best ResponseYou've already chosen the best response.1not quite... since the zeros are 1, 2, and 2, then the factors are (x1)(x+2)(x2)

dpaInc
 3 years ago
Best ResponseYou've already chosen the best response.1so all you do is multiply out the 3 binomials....

heathernelly
 3 years ago
Best ResponseYou've already chosen the best response.0how is it 1 when it says 1 ?

dpaInc
 3 years ago
Best ResponseYou've already chosen the best response.1a zero refers to where the graph crosses the xaxis (when y=0) so the equation is 0 = (x1)(x+2)(x2) if x=1, you'll have 0 = (11)(1+2)(12) which is a true statement but if you have what you wrote down, 0 = (1+1)(1+2)(12) is not a true statement

dpaInc
 3 years ago
Best ResponseYou've already chosen the best response.1multiply out the binomials: (x1)(x+2)(x2) = \(\large x^3x^24x+4 \)
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