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dpaIncBest ResponseYou've already chosen the best response.1
can you give me the derivative of f ??
 one year ago

heathernellyBest ResponseYou've already chosen the best response.0
that's all it says :// :(
 one year ago

dpaIncBest ResponseYou've already chosen the best response.1
yes... but you need to calculate the derivative of f to find the relative max/min of the function.
 one year ago

dpaIncBest ResponseYou've already chosen the best response.1
isn't this for a calculus class?
 one year ago

heathernellyBest ResponseYou've already chosen the best response.0
its okay :) so you don't know how to do it? :(
 one year ago

heathernellyBest ResponseYou've already chosen the best response.0
i know how to do it on a calculater ..but i left it at a friends house ://
 one year ago

dpaIncBest ResponseYou've already chosen the best response.1
oh... so you're allowed to use the max/min functions of a graphing calculator?
 one year ago

dpaIncBest ResponseYou've already chosen the best response.1
since you don't have your graphing calculator with you, use this online one.... https://www.desmos.com/calculator i've also included the graph of your function here:
 one year ago

dpaIncBest ResponseYou've already chosen the best response.1
it looks like you have a relative max at x=4 and a relative min at x=0
 one year ago

heathernellyBest ResponseYou've already chosen the best response.0
yeah, but that's not one of my options :(
 one year ago

dpaIncBest ResponseYou've already chosen the best response.1
the function you gave at the start does not coincide with those choices...
 one year ago

heathernellyBest ResponseYou've already chosen the best response.0
thats what it says in my homework
 one year ago

dpaIncBest ResponseYou've already chosen the best response.1
i double checked with this function you gave at the start: \(\large f(x)=x^3+6x^236 \) f has a relative max at x=4 and a relative min at x=0.
 one year ago

dpaIncBest ResponseYou've already chosen the best response.1
f(4) = 4 so (4, 4) is a relmax f(0) = 36 so (0, 36) is a relmin
 one year ago

heathernellyBest ResponseYou've already chosen the best response.0
but that's none of the options ://
 one year ago

dpaIncBest ResponseYou've already chosen the best response.1
i'm sorry.... i'm absolutely sure of my answer here.. even the calculator verifies my answer.... is this the function we started with correct?
 one year ago

heathernellyBest ResponseYou've already chosen the best response.0
yes it is ..hmm :// :(
 one year ago

heathernellyBest ResponseYou've already chosen the best response.0
im just going to pick a or b:///.. lol ..thank you for the help though :)
 one year ago

heathernellyBest ResponseYou've already chosen the best response.0
do you think you could help me with another one?
 one year ago

dpaIncBest ResponseYou've already chosen the best response.1
there has to be an error in those choices... yw... :)
 one year ago

heathernellyBest ResponseYou've already chosen the best response.0
What is a cubic polynomial function in standard form with zeros 1, –2, and 2?
 one year ago

dpaIncBest ResponseYou've already chosen the best response.1
do you know how to multiply out binomials?
 one year ago

heathernellyBest ResponseYou've already chosen the best response.0
i know i have to write like (x+1)(x2)(x+2)
 one year ago

dpaIncBest ResponseYou've already chosen the best response.1
standard form for a cubic polynomial is: \(\large y=ax^3+bx^2+cx+d \) where a, b, c, d are real numbers.
 one year ago

dpaIncBest ResponseYou've already chosen the best response.1
not quite... since the zeros are 1, 2, and 2, then the factors are (x1)(x+2)(x2)
 one year ago

dpaIncBest ResponseYou've already chosen the best response.1
so all you do is multiply out the 3 binomials....
 one year ago

heathernellyBest ResponseYou've already chosen the best response.0
how is it 1 when it says 1 ?
 one year ago

dpaIncBest ResponseYou've already chosen the best response.1
a zero refers to where the graph crosses the xaxis (when y=0) so the equation is 0 = (x1)(x+2)(x2) if x=1, you'll have 0 = (11)(1+2)(12) which is a true statement but if you have what you wrote down, 0 = (1+1)(1+2)(12) is not a true statement
 one year ago

dpaIncBest ResponseYou've already chosen the best response.1
multiply out the binomials: (x1)(x+2)(x2) = \(\large x^3x^24x+4 \)
 one year ago
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