kkkkk

- anonymous

kkkkk

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- anonymous

can you give me the derivative of f ??

- anonymous

that's all it says :// :(

- anonymous

yes... but you need to calculate the derivative of f to find the relative max/min of the function.

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## More answers

- anonymous

isn't this for a calculus class?

- anonymous

algebra 2

- anonymous

oh... sorry....

- anonymous

its okay :) so you don't know how to do it? :(

- anonymous

i know how to do it on a calculater ..but i left it at a friends house ://

- anonymous

oh... so you're allowed to use the max/min functions of a graphing calculator?

- anonymous

yes

- anonymous

ok... hang on...

- anonymous

okaay :)

- anonymous

since you don't have your graphing calculator with you, use this online one....
https://www.desmos.com/calculator
i've also included the graph of your function here:

##### 1 Attachment

- anonymous

it looks like you have a relative max at x=-4 and a relative min at x=0

- anonymous

yeah, but that's not one of my options :(

- anonymous

the function you gave at the start does not coincide with those choices...

- anonymous

thats what it says in my homework

- anonymous

i double checked with this function you gave at the start: \(\large f(x)=x^3+6x^2-36 \)
f has a relative max at x=-4 and a relative min at x=0.

- anonymous

f(-4) = -4 so (-4, -4) is a relmax
f(0) = -36 so (0, -36) is a relmin

- anonymous

but that's none of the options ://

- anonymous

i'm sorry.... i'm absolutely sure of my answer here..
even the calculator verifies my answer....
is this the function we started with correct?

- anonymous

yes it is ..hmm :// :(

- anonymous

im just going to pick a or b:///.. lol ..thank you for the help though :)

- anonymous

idk what to say... :(

- anonymous

do you think you could help me with another one?

- anonymous

there has to be an error in those choices...
yw... :)

- anonymous

yes...

- anonymous

What is a cubic polynomial function in standard form with zeros 1, –2, and 2?

- anonymous

do you know how to multiply out binomials?

- anonymous

i know i have to write like (x+1)(x-2)(x+2)

- anonymous

standard form for a cubic polynomial is: \(\large y=ax^3+bx^2+cx+d \)
where a, b, c, d are real numbers.

- anonymous

not quite... since the zeros are 1, -2, and 2,
then the factors are (x-1)(x+2)(x-2)

- anonymous

so all you do is multiply out the 3 binomials....

- anonymous

how is it -1 when it says 1 ?

- anonymous

a zero refers to where the graph crosses the x-axis (when y=0)
so the equation is 0 = (x-1)(x+2)(x-2)
if x=1, you'll have 0 = (1-1)(1+2)(1-2) which is a true statement
but if you have what you wrote down, 0 = (1+1)(1+2)(1-2) is not a true statement

- anonymous

multiply out the binomials: (x-1)(x+2)(x-2) = \(\large x^3-x^2-4x+4 \)

- anonymous

thanks :)

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