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find maximum and minimum values for the function g(x)=x^3-3x

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what u got as first derivative ?
3x^2-3=0 x^2=1 x=1,-1

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Other answers:

should i take second derivative?
correct. here u can just put the values in g(x) and by inspection u can tell which is max
mathematically, u should take 2nd derivative...
max at x=-1 and minimum at x=1
bt then why we took second derivative in last qn?
because we can't find the max or min just by putting the points and inspection, can we ?
i see is my final answers ryt?
u dr??
sorry, got disconnected...yes, its correct
one last qn and i am done ,,well for this qn i think i gt crct anser bt i want t o knw if i need to take second derivative "find maximum and minimum value of 3x^4-8x^3+12x^2-48x+25
yes, u need to..
are answers 0 and 2?
mim at x=2
max at x=0 min at x=2 ryt?
yes, both are correct..i had doubt with max at x=0
thanx a lot!!!! it really helped cant tell u hw thankful i am !!
seeya gn8 sweeet drms

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