anonymous
  • anonymous
Please, solve this differential equation 9*y*(y')^2 + 4*(x^3)*y' - 4*(x^2)*y = 0 PS I'm a foreigner, so I might you ask more questions during the problrm solving! Thanx a lot!
Differential Equations
  • Stacey Warren - Expert brainly.com
Hey! We 've verified this expert answer for you, click below to unlock the details :)
SOLVED
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.
katieb
  • katieb
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
anonymous
  • anonymous
Dang that's a long one...
anonymous
  • anonymous
I know. And I could not solve it. I suppose, that there must be a parameter. But which one? Should I put y' = p or y' = px ??? I've already done both but I hadn'd any result.
anonymous
  • anonymous
I think you either wrote it incorrectly or you're not being asked to solve it...?

Looking for something else?

Not the answer you are looking for? Search for more explanations.

More answers

anonymous
  • anonymous
@Algebraic! I DID wrote this equation correctly (I checked it 3 times). And I didn't understand, do you have doubts about my homework? You may trust me, I really have to solve this for my Math classes.
anonymous
  • anonymous
cool. no analytic solutions as far as I can tell, so ...
anonymous
  • anonymous
@Algebraic! Why do you think that?
sirm3d
  • sirm3d
is this not a quadratic equation in \[y \prime \]? that you should solve the quadratic equation first, then the resulting differential equations?
anonymous
  • anonymous
that y next to the 9 on the first term looks weird
anonymous
  • anonymous
This is special differential Equation. What I know is that (y') should replace with p(x) or p(x)*x and then dy = pdx or dy=pdx+xdp 1) accordingly. And I solved this equation with both replacements and as a result a had really huge equations. I thought, I had done something wrong that is why I asked you for help. But I have just understood that you had not even seen such equations.
anonymous
  • anonymous
Should I put here an example of solving similar equation?
across
  • across
Observe how\[y(x)=\frac13ix^2\]is a solution of this ODE:\[\begin{align} 9y(y')^2&=-\frac43ix^4,\tag{1}\\ 4x^3y'&=\frac83ix^4,\tag{2}\\ 4x^2y&=\frac43ix^4,\tag{3} \end{align}\]\((1)+(2)-(3)=0\). This is also true for its conjugate.
anonymous
  • anonymous
|dw:1351986536371:dw|
anonymous
  • anonymous
|dw:1351986790555:dw|
anonymous
  • anonymous
|dw:1351987002927:dw|
anonymous
  • anonymous
|dw:1351987163211:dw|
anonymous
  • anonymous
|dw:1351987461053:dw|
anonymous
  • anonymous
@Algebraic! take a look.
anonymous
  • anonymous
@mahmit2012!!! That is amazing!!! I'm going to figure it out! Thanx a lot!!!

Looking for something else?

Not the answer you are looking for? Search for more explanations.