A community for students.
Here's the question you clicked on:
 0 viewing

This Question is Closed

bmelyk
 2 years ago
Best ResponseYou've already chosen the best response.1Use the appropriate rule or combination of rules to find the derivative of the function defined below. \[y=2(\sin(6x)+\cos(x^3))^\frac{ 1 }{ 2 }\]

bmelyk
 2 years ago
Best ResponseYou've already chosen the best response.1not even sure how to start this one. ;( looks like it would the the chain rule of course.

hartnn
 2 years ago
Best ResponseYou've already chosen the best response.1first what is derivative of x^{1/2} = ?

hartnn
 2 years ago
Best ResponseYou've already chosen the best response.1we always go from outer function to inner function

hartnn
 2 years ago
Best ResponseYou've already chosen the best response.1\(y'=2(1/2)(\sin(6x)+\cos(x^3))^\frac{ 1 }{ 2 }d/dx(\sin(6x)+\cos(x^3))\)

bmelyk
 2 years ago
Best ResponseYou've already chosen the best response.1options for the right answer are: \[a)2*\frac{ \cos(6x)\sin(x^3) }{ (\sin(6x)+cox(x^3))^1/2 }\] \[b)\frac{ \cos(6x) +\sin(x^3)}{ (\sin(6x)+\cos(x^3))^\frac{ 1 }{ 2 } }\] \[c)\frac{ 12 }{ 6x^\frac{ 1 }{ 2 } }*\cos(6x)\frac{ 6 }{ \cos(x^3)^\frac{ 1 }{ 2 } }*\sin(x^3)*x^2\] \[d)\frac{ 1 }{ (\sin(6x)^\frac{ 1 }{ 2 }+\cos(x^3))^\frac{ 1 }{ 2 } }\] \[e)\frac{ 6*\cos(6x)3x^2*\sin(x^3) }{ (\sin(6x)+\cos(x^3))^\frac{ 1 }{ 2 } }\] f) same as e only 2 outside of the fraction. \[g) \frac{ 2 }{ \sin(6x)+\cos(x^3))^1/2 }\] \[h) \frac{ 6 }{ \sin(6x)^\frac{ 1 }{ 2 } }*\cos6x\frac{ 3 }{ \cos(x^3)^\frac{ 1 }{ 2 } }*\sin(x^3)*x^2\]

hartnn
 2 years ago
Best ResponseYou've already chosen the best response.1u got my last comment ? how i got that ?

hartnn
 2 years ago
Best ResponseYou've already chosen the best response.1so what is d/dx(sin(6x)+cos(x^3)) ?

bmelyk
 2 years ago
Best ResponseYou've already chosen the best response.1do i use the product rule for sin*6x and cos*x^3?

hartnn
 2 years ago
Best ResponseYou've already chosen the best response.1there is no product, so NO u can treat them individually also what is d/dx (sin 6x) = ?

hartnn
 2 years ago
Best ResponseYou've already chosen the best response.1u need chain rule here too, right ?

hartnn
 2 years ago
Best ResponseYou've already chosen the best response.1yes! times 6, because u'll have d/dx(6x)

hartnn
 2 years ago
Best ResponseYou've already chosen the best response.1yup, what about 2nd term ? d/dx (cos (x^3)) = ?

hartnn
 2 years ago
Best ResponseYou've already chosen the best response.1absolutely correct! u got it :)

hartnn
 2 years ago
Best ResponseYou've already chosen the best response.1put everything together, and u'll get it.

hartnn
 2 years ago
Best ResponseYou've already chosen the best response.1i hope chain rule is clearer to u now.....
Ask your own question
Sign UpFind more explanations on OpenStudy
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.