## nasticia Group Title a construction worker drops a wrench from the top of an 80 m high tower. what is the velocity of the wrench when it strikes the ground one year ago one year ago

• This Question is Open
1. klimenkov Group Title

$$S=\frac{gt^2}2$$ $$v=gt$$ $$t=\sqrt{\frac{2S}{g}}$$ $$v=g\cdot\sqrt{\frac{2S}{g}}=\sqrt{2gS}$$

2. nasticia Group Title

Do you know how to solve it

3. klimenkov Group Title

It is a solution, S - is a distance, v - velocity, g - acceleration = 9.8 m/s^2