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## anonymous 3 years ago a construction worker drops a wrench from the top of an 80 m high tower. what is the velocity of the wrench when it strikes the ground

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1. klimenkov

$$S=\frac{gt^2}2$$ $$v=gt$$ $$t=\sqrt{\frac{2S}{g}}$$ $$v=g\cdot\sqrt{\frac{2S}{g}}=\sqrt{2gS}$$

2. anonymous

Do you know how to solve it

3. klimenkov

It is a solution, S - is a distance, v - velocity, g - acceleration = 9.8 m/s^2

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