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heathernelly
 3 years ago
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heathernelly
 3 years ago
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tcarroll010
 3 years ago
Best ResponseYou've already chosen the best response.1Start with the realization that this is the difference between 2 perfect squares. And when you have a^3  b^3, this can be factored into (a  b)(a^2 + ab + b^2)

tcarroll010
 3 years ago
Best ResponseYou've already chosen the best response.1Sorry, just saw the plus sign.

tcarroll010
 3 years ago
Best ResponseYou've already chosen the best response.1It is the SUM of 2 perfect squares, which can be factored. a^3 + b^3 = (a + b)(a^2  ab + b^2).

Thailynn
 3 years ago
Best ResponseYou've already chosen the best response.0Google it or yahoo it . http://answers.yahoo.com/question/index?qid=20110601120209AAC6qWn

tcarroll010
 3 years ago
Best ResponseYou've already chosen the best response.1So, 27x^3 + 125 = 0 > (3x)^3 + 5^3 = 0 and you can use my formula (second post) and you can find the first zero.

heathernelly
 3 years ago
Best ResponseYou've already chosen the best response.0oh okaay, thank you very muchh :)

tcarroll010
 3 years ago
Best ResponseYou've already chosen the best response.1(3x)^3 + 5^3 = 0 = (3x + 5)(9x^2  15x + 25)

tcarroll010
 3 years ago
Best ResponseYou've already chosen the best response.1You will have one real zero at x = 5/3 and 2 imaginary zeros that come from the second factor. Just use the quadratic formula.

tcarroll010
 3 years ago
Best ResponseYou've already chosen the best response.1You are very welcome!
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