Got Homework?
Connect with other students for help. It's a free community.
Here's the question you clicked on:
 0 viewing

This Question is Closed

tcarroll010 Group TitleBest ResponseYou've already chosen the best response.1
Start with the realization that this is the difference between 2 perfect squares. And when you have a^3  b^3, this can be factored into (a  b)(a^2 + ab + b^2)
 2 years ago

tcarroll010 Group TitleBest ResponseYou've already chosen the best response.1
Sorry, just saw the plus sign.
 2 years ago

tcarroll010 Group TitleBest ResponseYou've already chosen the best response.1
It is the SUM of 2 perfect squares, which can be factored. a^3 + b^3 = (a + b)(a^2  ab + b^2).
 2 years ago

Thailynn Group TitleBest ResponseYou've already chosen the best response.0
Google it or yahoo it . http://answers.yahoo.com/question/index?qid=20110601120209AAC6qWn
 2 years ago

tcarroll010 Group TitleBest ResponseYou've already chosen the best response.1
So, 27x^3 + 125 = 0 > (3x)^3 + 5^3 = 0 and you can use my formula (second post) and you can find the first zero.
 2 years ago

heathernelly Group TitleBest ResponseYou've already chosen the best response.0
oh okaay, thank you very muchh :)
 2 years ago

tcarroll010 Group TitleBest ResponseYou've already chosen the best response.1
(3x)^3 + 5^3 = 0 = (3x + 5)(9x^2  15x + 25)
 2 years ago

tcarroll010 Group TitleBest ResponseYou've already chosen the best response.1
You will have one real zero at x = 5/3 and 2 imaginary zeros that come from the second factor. Just use the quadratic formula.
 2 years ago

heathernelly Group TitleBest ResponseYou've already chosen the best response.0
ty :))
 2 years ago

tcarroll010 Group TitleBest ResponseYou've already chosen the best response.1
You are very welcome!
 2 years ago
See more questions >>>
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.