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math7
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Suppose that limit x> a f(x)= infinity and limit x> a g(x) = c, where c is a real number. Prove each statement.
(a) lim x> a [f(x) + g(x)] = infinity
(b) lim x> a [f(x)g(x)] = infinity if c > 0
(c) lim x> a [f(x)g(x)] = negative infinity if c < 0
I need to prove it using the precise definition of a limit (i.e. no limit laws).
Thanks so much!!!!!!
I actually only need the proofs for a) and c)... if it helps, here's the link to the proof of a problem to (b): http://imageshack.us/photo/myimages/190/unledmkd.png/
 2 years ago
 2 years ago
math7 Group Title
Suppose that limit x> a f(x)= infinity and limit x> a g(x) = c, where c is a real number. Prove each statement. (a) lim x> a [f(x) + g(x)] = infinity (b) lim x> a [f(x)g(x)] = infinity if c > 0 (c) lim x> a [f(x)g(x)] = negative infinity if c < 0 I need to prove it using the precise definition of a limit (i.e. no limit laws). Thanks so much!!!!!! I actually only need the proofs for a) and c)... if it helps, here's the link to the proof of a problem to (b): http://imageshack.us/photo/myimages/190/unledmkd.png/
 2 years ago
 2 years ago

This Question is Open

Jessica_Moore Group TitleBest ResponseYou've already chosen the best response.0
A) When A is approaching a positive number it will approach Infinity Infinity + C = Infinity because Infinity + anything is infinity B} When the constant C Is greater than 0 [ positive non zero number ] then multiplying it by any number in positive infinity will just make the limit reach POSITIVE infinity C} Same thing as B But this time its less than 0 thus reaching negative infinity because C [ negative any number ] * Any number > 0 = Negative large number[ infinity ] I hope this helps.
 2 years ago
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