A community for students.
Here's the question you clicked on:
 0 viewing
anonymous
 3 years ago
Suppose that limit x> a f(x)= infinity and limit x> a g(x) = c, where c is a real number. Prove each statement.
(a) lim x> a [f(x) + g(x)] = infinity
(b) lim x> a [f(x)g(x)] = infinity if c > 0
(c) lim x> a [f(x)g(x)] = negative infinity if c < 0
I need to prove it using the precise definition of a limit (i.e. no limit laws).
Thanks so much!!!!!!
I actually only need the proofs for a) and c)... if it helps, here's the link to the proof of a problem to (b):
http://imageshack.us/photo/myimages/190/unledmkd.png/
anonymous
 3 years ago
Suppose that limit x> a f(x)= infinity and limit x> a g(x) = c, where c is a real number. Prove each statement. (a) lim x> a [f(x) + g(x)] = infinity (b) lim x> a [f(x)g(x)] = infinity if c > 0 (c) lim x> a [f(x)g(x)] = negative infinity if c < 0 I need to prove it using the precise definition of a limit (i.e. no limit laws). Thanks so much!!!!!! I actually only need the proofs for a) and c)... if it helps, here's the link to the proof of a problem to (b): http://imageshack.us/photo/myimages/190/unledmkd.png/

This Question is Open

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0A) When A is approaching a positive number it will approach Infinity Infinity + C = Infinity because Infinity + anything is infinity B} When the constant C Is greater than 0 [ positive non zero number ] then multiplying it by any number in positive infinity will just make the limit reach POSITIVE infinity C} Same thing as B But this time its less than 0 thus reaching negative infinity because C [ negative any number ] * Any number > 0 = Negative large number[ infinity ] I hope this helps.
Ask your own question
Sign UpFind more explanations on OpenStudy
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.