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Solve the following formula for the specified variable.
C=1/4h(s+k) solve for s???
 one year ago
 one year ago
Solve the following formula for the specified variable. C=1/4h(s+k) solve for s???
 one year ago
 one year ago

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etemplinBest ResponseYou've already chosen the best response.0
if this was a normal equation, and all those variables were numbers, how would you solve for s? hint: try to get s by itself
 one year ago

KE8717504Best ResponseYou've already chosen the best response.0
It's been so long since i actually did this type of problem
 one year ago

etemplinBest ResponseYou've already chosen the best response.0
i also have a question about the original question is it C=(1/4)h(s+k) or C=1/(4h(s+k))
 one year ago

KE8717504Best ResponseYou've already chosen the best response.0
it's the first one that you put on there
 one year ago

etemplinBest ResponseYou've already chosen the best response.0
the first and easiest thing to get rid of is the 1/4 if we want to rewrite the equation, we could like this: c=(h(s+k))/4 since we are dividing by 4 on the right, we can multiply both sides by 4 to get closer to having s by itself (by moving the 4 over) we get: 4c=h(s+k) now, to get rid of that h notice its being multiplied by the quantity inside the parenthesis to move it to the other side, we need to divide both sides by h (4c)/h=s+k finally, subtract k from both sides to get your answer
 one year ago

etemplinBest ResponseYou've already chosen the best response.0
dw:1351648217904:dw
 one year ago

etemplinBest ResponseYou've already chosen the best response.0
dw:1351648246343:dw
 one year ago

KE8717504Best ResponseYou've already chosen the best response.0
ok so when i solved that i got 4c/hk
 one year ago

etemplinBest ResponseYou've already chosen the best response.0
you should get 4c=h(s+k)
 one year ago

KE8717504Best ResponseYou've already chosen the best response.0
That's what you got as the answer??
 one year ago

etemplinBest ResponseYou've already chosen the best response.0
now, divide both sides by h
 one year ago

KE8717504Best ResponseYou've already chosen the best response.0
so the h on the one side would cancel and just leave me with s+k but i don't know what i would get on the other side
 one year ago

KE8717504Best ResponseYou've already chosen the best response.0
so my answr is going to be 4c/h=s +k??
 one year ago

etemplinBest ResponseYou've already chosen the best response.0
you have to get s by itself subtract k from both sides
 one year ago

KE8717504Best ResponseYou've already chosen the best response.0
I thought that I just subracted something
 one year ago

etemplinBest ResponseYou've already chosen the best response.0
it says solve for s that means you have to get s by itself
 one year ago

etemplinBest ResponseYou've already chosen the best response.0
think of it this way if you have s+k and you want to get s by itself, wouldnt it be necessary to subtract k s+kk=s
 one year ago

etemplinBest ResponseYou've already chosen the best response.0
since you subtracted k from one side, you MUST subtract it from the other
 one year ago

KE8717504Best ResponseYou've already chosen the best response.0
ok im just confused on what im going to get i thought what i typed a minute ago was my answr
 one year ago

etemplinBest ResponseYou've already chosen the best response.0
your answer is going to have s by itself on one side and a whole bunch of stuff on the other after you subtract k from both sides, the final answer is s=((4c)/h)k
 one year ago

KE8717504Best ResponseYou've already chosen the best response.0
I thought that is what i put a minute ago
 one year ago

etemplinBest ResponseYou've already chosen the best response.0
it was not. you hadnt subtracted k yet
 one year ago

KE8717504Best ResponseYou've already chosen the best response.0
Ok well i got that one wrong because the C was not capital
 one year ago

KE8717504Best ResponseYou've already chosen the best response.0
I've got this stuff due tommorrow and im still not doen after this
 one year ago

KE8717504Best ResponseYou've already chosen the best response.0
its ok. r u working it or something
 one year ago

etemplinBest ResponseYou've already chosen the best response.0
for this one, you can follow the exact same steps as the first one. Multiply both sides by 2 to get rid of the 1/2 divide both sides by f subtract k from both sides what do you get?
 one year ago

KE8717504Best ResponseYou've already chosen the best response.0
i even wrote the wrong problem
 one year ago

KE8717504Best ResponseYou've already chosen the best response.0
And I'm solving for r
 one year ago

KE8717504Best ResponseYou've already chosen the best response.0
i got 2c/fk but that's not right
 one year ago

etemplinBest ResponseYou've already chosen the best response.0
where did you get a c theres no c in b=1/2f(r+k)
 one year ago

KE8717504Best ResponseYou've already chosen the best response.0
i got that one may i ask another onee
 one year ago

KE8717504Best ResponseYou've already chosen the best response.0
dw:1351649553338:dw
 one year ago

etemplinBest ResponseYou've already chosen the best response.0
ok start by simplifying sqrt((xy)^2)=xy yes?
 one year ago

KE8717504Best ResponseYou've already chosen the best response.0
I guess i don't know lol
 one year ago

etemplinBest ResponseYou've already chosen the best response.0
it is. trust me anyway, on the top, you can simplify sqrt(x^5y^9) to sqrt(x^4y^8)*sqrt(xy) sqrt(x^4y^8)=x^2*y^4 so 7x^2y^4*sqrt(xy)  3xy one x and 1 y on the top and bottom cancel answer: (7xy^3*sqrt(xy))/3
 one year ago

etemplinBest ResponseYou've already chosen the best response.0
dw:1351649829505:dw
 one year ago

KE8717504Best ResponseYou've already chosen the best response.0
can u draw that for me because it's hard for me to read and understand it
 one year ago

KE8717504Best ResponseYou've already chosen the best response.0
is that 3 suppose to be with the root?
 one year ago

KE8717504Best ResponseYou've already chosen the best response.0
or is it with the Y?
 one year ago

etemplinBest ResponseYou've already chosen the best response.0
were the original numbers with the root or were they outside?
 one year ago

KE8717504Best ResponseYou've already chosen the best response.0
because i put it with the y and it said it was wrong.
 one year ago

KE8717504Best ResponseYou've already chosen the best response.0
they were on the outside of the root but they were part of the root
 one year ago

etemplinBest ResponseYou've already chosen the best response.0
were the original numbers (the 3 and 7) with the root or in front of it?
 one year ago

KE8717504Best ResponseYou've already chosen the best response.0
dw:1351650274050:dw
 one year ago

etemplinBest ResponseYou've already chosen the best response.0
that changes the answer then i assumed they were not part of the root; i assumed they were multiplied by it my mistake
 one year ago

etemplinBest ResponseYou've already chosen the best response.0
\[\sqrt[7]{x ^{5}y ^{9}} or 7\sqrt{x ^{5}y ^{9}}\]
 one year ago

etemplinBest ResponseYou've already chosen the best response.0
yea. when i solved it the first time i did it like the 2nd choice the new answer isdw:1351650440270:dw
 one year ago

KE8717504Best ResponseYou've already chosen the best response.0
so my y is on the outside??
 one year ago

etemplinBest ResponseYou've already chosen the best response.0
you cant simplify the bottom at all, and the top can be just a little bit
 one year ago

etemplinBest ResponseYou've already chosen the best response.0
im just saying the answer is the one i drew the reason is given in the post after that
 one year ago

etemplinBest ResponseYou've already chosen the best response.0
is the 3 part of the root like the 7 is?
 one year ago

etemplinBest ResponseYou've already chosen the best response.0
another answer is dw:1351651467504:dw
 one year ago

etemplinBest ResponseYou've already chosen the best response.0
i apologize for any incorrect answers
 one year ago
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