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Solve the following formula for the specified variable.
C=1/4h(s+k) solve for s???
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etemplin
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if this was a normal equation, and all those variables were numbers, how would you solve for s?
hint: try to get s by itself
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It's been so long since i actually did this type of problem
etemplin
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i also have a question about the original question
is it C=(1/4)h(s+k)
or
C=1/(4h(s+k))
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it's the first one that you put on there
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c=1/4h(s+k)
etemplin
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the first and easiest thing to get rid of is the 1/4
if we want to re-write the equation, we could like this:
c=(h(s+k))/4
since we are dividing by 4 on the right, we can multiply both sides by 4 to get closer to having s by itself (by moving the 4 over)
we get:
4c=h(s+k)
now, to get rid of that h
notice its being multiplied by the quantity inside the parenthesis
to move it to the other side, we need to divide both sides by h
(4c)/h=s+k
finally, subtract k from both sides to get your answer
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ok im confused
etemplin
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|dw:1351648217904:dw|
etemplin
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|dw:1351648246343:dw|
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ok so when i solved that i got 4c/h-k
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is that right ?
etemplin
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you should get 4c=h(s+k)
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ok
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That's what you got as the answer??
etemplin
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now, divide both sides by h
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so the h on the one side would cancel and just leave me with s+k but i don't know what i would get on the other side
etemplin
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(4c)/h
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so my answr is going to be 4c/h=s +k??
etemplin
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you have to get s by itself
subtract k from both sides
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OMG!! I'm sooo lost
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I thought that I just subracted something
etemplin
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it says solve for s
that means you have to get s by itself
etemplin
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think of it this way
if you have s+k and you want to get s by itself, wouldnt it be necessary to subtract k
s+k-k=s
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yes
etemplin
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since you subtracted k from one side, you MUST subtract it from the other
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ok im just confused on what im going to get i thought what i typed a minute ago was my answr
etemplin
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your answer is going to have s by itself on one side and a whole bunch of stuff on the other
after you subtract k from both sides, the final answer is s=((4c)/h)-k
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4c/h-k?
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I thought that is what i put a minute ago
etemplin
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it was not. you hadnt subtracted k yet
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Ok well i got that one wrong because the C was not capital
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b=1/2f(r+k)
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for r
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I've got this stuff due tommorrow and im still not doen after this
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r u there?
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yes. sorry
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its ok. r u working it or something
etemplin
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i got distracted
etemplin
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for this one, you can follow the exact same steps as the first one. Multiply both sides by 2 to get rid of the 1/2
divide both sides by f
subtract k from both sides
what do you get?
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one sec
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i even wrote the wrong problem
etemplin
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its ok, it happens
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b=1/2f(r+k)
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And I'm solving for r
etemplin
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thats the exact same
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i got 2c/f-k but that's not right
etemplin
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where did you get a c
theres no c in b=1/2f(r+k)
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i have no idea
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i got that one may i ask another onee
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?
etemplin
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yes
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|dw:1351649553338:dw|
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that is my next one
etemplin
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hmmm
give me a sec
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k
etemplin
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ok
start by simplifying sqrt((xy)^2)=xy
yes?
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I guess i don't know lol
etemplin
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it is. trust me
anyway, on the top, you can simplify sqrt(x^5y^9) to sqrt(x^4y^8)*sqrt(xy)
sqrt(x^4y^8)=x^2*y^4
so
7x^2y^4*sqrt(xy)
----------------
3xy
one x and 1 y on the top and bottom cancel
answer:
(7xy^3*sqrt(xy))/3
etemplin
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|dw:1351649829505:dw|
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can u draw that for me because it's hard for me to read and understand it
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is that 3 suppose to be with the root?
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or is it with the Y?
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@etemplin
etemplin
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its with the y
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were the original numbers with the root or were they outside?
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because i put it with the y and it said it was wrong.
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they were on the outside of the root but they were part of the root
etemplin
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were the original numbers (the 3 and 7) with the root or in front of it?
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they were in front
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|dw:1351650274050:dw|
etemplin
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that changes the answer then
i assumed they were not part of the root; i assumed they were multiplied by it
my mistake
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like that
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it's fine
etemplin
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\[\sqrt[7]{x ^{5}y ^{9}} or 7\sqrt{x ^{5}y ^{9}}\]
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ok what is that
etemplin
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which is it?
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is that the answer?
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the first one
etemplin
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yea. when i solved it the first time i did it like the 2nd choice
the new answer is|dw:1351650440270:dw|
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so my y is on the outside??
etemplin
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yes
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you cant simplify the bottom at all, and the top can be just a little bit
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what u mean
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im just saying
the answer is the one i drew
the reason is given in the post after that
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ok
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that wasn't correct
etemplin
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is the 3 part of the root like the 7 is?
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another answer is |dw:1351651467504:dw|
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i apologize for any incorrect answers