## KE8717504 Group Title Solve the following formula for the specified variable. C=1/4h(s+k) solve for s??? one year ago one year ago

1. etemplin Group Title

if this was a normal equation, and all those variables were numbers, how would you solve for s? hint: try to get s by itself

2. KE8717504 Group Title

It's been so long since i actually did this type of problem

3. etemplin Group Title

i also have a question about the original question is it C=(1/4)h(s+k) or C=1/(4h(s+k))

4. KE8717504 Group Title

it's the first one that you put on there

5. KE8717504 Group Title

c=1/4h(s+k)

6. etemplin Group Title

the first and easiest thing to get rid of is the 1/4 if we want to re-write the equation, we could like this: c=(h(s+k))/4 since we are dividing by 4 on the right, we can multiply both sides by 4 to get closer to having s by itself (by moving the 4 over) we get: 4c=h(s+k) now, to get rid of that h notice its being multiplied by the quantity inside the parenthesis to move it to the other side, we need to divide both sides by h (4c)/h=s+k finally, subtract k from both sides to get your answer

7. KE8717504 Group Title

ok im confused

8. etemplin Group Title

|dw:1351648217904:dw|

9. etemplin Group Title

|dw:1351648246343:dw|

10. KE8717504 Group Title

ok so when i solved that i got 4c/h-k

11. KE8717504 Group Title

is that right ?

12. etemplin Group Title

you should get 4c=h(s+k)

13. KE8717504 Group Title

ok

14. KE8717504 Group Title

That's what you got as the answer??

15. etemplin Group Title

now, divide both sides by h

16. KE8717504 Group Title

so the h on the one side would cancel and just leave me with s+k but i don't know what i would get on the other side

17. etemplin Group Title

(4c)/h

18. KE8717504 Group Title

so my answr is going to be 4c/h=s +k??

19. etemplin Group Title

you have to get s by itself subtract k from both sides

20. KE8717504 Group Title

OMG!! I'm sooo lost

21. KE8717504 Group Title

I thought that I just subracted something

22. etemplin Group Title

it says solve for s that means you have to get s by itself

23. etemplin Group Title

think of it this way if you have s+k and you want to get s by itself, wouldnt it be necessary to subtract k s+k-k=s

24. KE8717504 Group Title

yes

25. etemplin Group Title

since you subtracted k from one side, you MUST subtract it from the other

26. KE8717504 Group Title

ok im just confused on what im going to get i thought what i typed a minute ago was my answr

27. etemplin Group Title

your answer is going to have s by itself on one side and a whole bunch of stuff on the other after you subtract k from both sides, the final answer is s=((4c)/h)-k

28. KE8717504 Group Title

4c/h-k?

29. KE8717504 Group Title

I thought that is what i put a minute ago

30. etemplin Group Title

it was not. you hadnt subtracted k yet

31. KE8717504 Group Title

Ok well i got that one wrong because the C was not capital

32. KE8717504 Group Title

b=1/2f(r+k)

33. KE8717504 Group Title

for r

34. KE8717504 Group Title

I've got this stuff due tommorrow and im still not doen after this

35. KE8717504 Group Title

r u there?

36. etemplin Group Title

yes. sorry

37. KE8717504 Group Title

its ok. r u working it or something

38. etemplin Group Title

i got distracted

39. etemplin Group Title

for this one, you can follow the exact same steps as the first one. Multiply both sides by 2 to get rid of the 1/2 divide both sides by f subtract k from both sides what do you get?

40. KE8717504 Group Title

one sec

41. KE8717504 Group Title

i even wrote the wrong problem

42. etemplin Group Title

its ok, it happens

43. KE8717504 Group Title

b=1/2f(r+k)

44. KE8717504 Group Title

And I'm solving for r

45. etemplin Group Title

thats the exact same

46. KE8717504 Group Title

i got 2c/f-k but that's not right

47. etemplin Group Title

where did you get a c theres no c in b=1/2f(r+k)

48. KE8717504 Group Title

i have no idea

49. KE8717504 Group Title

i got that one may i ask another onee

50. KE8717504 Group Title

?

51. etemplin Group Title

yes

52. KE8717504 Group Title

|dw:1351649553338:dw|

53. KE8717504 Group Title

that is my next one

54. etemplin Group Title

hmmm give me a sec

55. KE8717504 Group Title

k

56. etemplin Group Title

ok start by simplifying sqrt((xy)^2)=xy yes?

57. KE8717504 Group Title

I guess i don't know lol

58. etemplin Group Title

it is. trust me anyway, on the top, you can simplify sqrt(x^5y^9) to sqrt(x^4y^8)*sqrt(xy) sqrt(x^4y^8)=x^2*y^4 so 7x^2y^4*sqrt(xy) ---------------- 3xy one x and 1 y on the top and bottom cancel answer: (7xy^3*sqrt(xy))/3

59. etemplin Group Title

|dw:1351649829505:dw|

60. KE8717504 Group Title

can u draw that for me because it's hard for me to read and understand it

61. KE8717504 Group Title

is that 3 suppose to be with the root?

62. KE8717504 Group Title

or is it with the Y?

63. KE8717504 Group Title

@etemplin

64. etemplin Group Title

its with the y

65. etemplin Group Title

were the original numbers with the root or were they outside?

66. KE8717504 Group Title

because i put it with the y and it said it was wrong.

67. KE8717504 Group Title

they were on the outside of the root but they were part of the root

68. etemplin Group Title

were the original numbers (the 3 and 7) with the root or in front of it?

69. KE8717504 Group Title

they were in front

70. KE8717504 Group Title

|dw:1351650274050:dw|

71. etemplin Group Title

that changes the answer then i assumed they were not part of the root; i assumed they were multiplied by it my mistake

72. KE8717504 Group Title

like that

73. KE8717504 Group Title

it's fine

74. etemplin Group Title

$\sqrt[7]{x ^{5}y ^{9}} or 7\sqrt{x ^{5}y ^{9}}$

75. KE8717504 Group Title

ok what is that

76. etemplin Group Title

which is it?

77. KE8717504 Group Title

78. KE8717504 Group Title

the first one

79. etemplin Group Title

yea. when i solved it the first time i did it like the 2nd choice the new answer is|dw:1351650440270:dw|

80. KE8717504 Group Title

so my y is on the outside??

81. etemplin Group Title

yes

82. etemplin Group Title

you cant simplify the bottom at all, and the top can be just a little bit

83. KE8717504 Group Title

what u mean

84. etemplin Group Title

im just saying the answer is the one i drew the reason is given in the post after that

85. KE8717504 Group Title

ok

86. KE8717504 Group Title

that wasn't correct

87. etemplin Group Title

is the 3 part of the root like the 7 is?

88. etemplin Group Title