## anonymous 3 years ago Solve the following formula for the specified variable. C=1/4h(s+k) solve for s???

1. anonymous

if this was a normal equation, and all those variables were numbers, how would you solve for s? hint: try to get s by itself

2. anonymous

It's been so long since i actually did this type of problem

3. anonymous

i also have a question about the original question is it C=(1/4)h(s+k) or C=1/(4h(s+k))

4. anonymous

it's the first one that you put on there

5. anonymous

c=1/4h(s+k)

6. anonymous

the first and easiest thing to get rid of is the 1/4 if we want to re-write the equation, we could like this: c=(h(s+k))/4 since we are dividing by 4 on the right, we can multiply both sides by 4 to get closer to having s by itself (by moving the 4 over) we get: 4c=h(s+k) now, to get rid of that h notice its being multiplied by the quantity inside the parenthesis to move it to the other side, we need to divide both sides by h (4c)/h=s+k finally, subtract k from both sides to get your answer

7. anonymous

ok im confused

8. anonymous

|dw:1351648217904:dw|

9. anonymous

|dw:1351648246343:dw|

10. anonymous

ok so when i solved that i got 4c/h-k

11. anonymous

is that right ?

12. anonymous

you should get 4c=h(s+k)

13. anonymous

ok

14. anonymous

That's what you got as the answer??

15. anonymous

now, divide both sides by h

16. anonymous

so the h on the one side would cancel and just leave me with s+k but i don't know what i would get on the other side

17. anonymous

(4c)/h

18. anonymous

so my answr is going to be 4c/h=s +k??

19. anonymous

you have to get s by itself subtract k from both sides

20. anonymous

OMG!! I'm sooo lost

21. anonymous

I thought that I just subracted something

22. anonymous

it says solve for s that means you have to get s by itself

23. anonymous

think of it this way if you have s+k and you want to get s by itself, wouldnt it be necessary to subtract k s+k-k=s

24. anonymous

yes

25. anonymous

since you subtracted k from one side, you MUST subtract it from the other

26. anonymous

ok im just confused on what im going to get i thought what i typed a minute ago was my answr

27. anonymous

your answer is going to have s by itself on one side and a whole bunch of stuff on the other after you subtract k from both sides, the final answer is s=((4c)/h)-k

28. anonymous

4c/h-k?

29. anonymous

I thought that is what i put a minute ago

30. anonymous

it was not. you hadnt subtracted k yet

31. anonymous

Ok well i got that one wrong because the C was not capital

32. anonymous

b=1/2f(r+k)

33. anonymous

for r

34. anonymous

I've got this stuff due tommorrow and im still not doen after this

35. anonymous

r u there?

36. anonymous

yes. sorry

37. anonymous

its ok. r u working it or something

38. anonymous

i got distracted

39. anonymous

for this one, you can follow the exact same steps as the first one. Multiply both sides by 2 to get rid of the 1/2 divide both sides by f subtract k from both sides what do you get?

40. anonymous

one sec

41. anonymous

i even wrote the wrong problem

42. anonymous

its ok, it happens

43. anonymous

b=1/2f(r+k)

44. anonymous

And I'm solving for r

45. anonymous

thats the exact same

46. anonymous

i got 2c/f-k but that's not right

47. anonymous

where did you get a c theres no c in b=1/2f(r+k)

48. anonymous

i have no idea

49. anonymous

i got that one may i ask another onee

50. anonymous

?

51. anonymous

yes

52. anonymous

|dw:1351649553338:dw|

53. anonymous

that is my next one

54. anonymous

hmmm give me a sec

55. anonymous

k

56. anonymous

ok start by simplifying sqrt((xy)^2)=xy yes?

57. anonymous

I guess i don't know lol

58. anonymous

it is. trust me anyway, on the top, you can simplify sqrt(x^5y^9) to sqrt(x^4y^8)*sqrt(xy) sqrt(x^4y^8)=x^2*y^4 so 7x^2y^4*sqrt(xy) ---------------- 3xy one x and 1 y on the top and bottom cancel answer: (7xy^3*sqrt(xy))/3

59. anonymous

|dw:1351649829505:dw|

60. anonymous

can u draw that for me because it's hard for me to read and understand it

61. anonymous

is that 3 suppose to be with the root?

62. anonymous

or is it with the Y?

63. anonymous

@etemplin

64. anonymous

its with the y

65. anonymous

were the original numbers with the root or were they outside?

66. anonymous

because i put it with the y and it said it was wrong.

67. anonymous

they were on the outside of the root but they were part of the root

68. anonymous

were the original numbers (the 3 and 7) with the root or in front of it?

69. anonymous

they were in front

70. anonymous

|dw:1351650274050:dw|

71. anonymous

that changes the answer then i assumed they were not part of the root; i assumed they were multiplied by it my mistake

72. anonymous

like that

73. anonymous

it's fine

74. anonymous

$\sqrt[7]{x ^{5}y ^{9}} or 7\sqrt{x ^{5}y ^{9}}$

75. anonymous

ok what is that

76. anonymous

which is it?

77. anonymous

78. anonymous

the first one

79. anonymous

yea. when i solved it the first time i did it like the 2nd choice the new answer is|dw:1351650440270:dw|

80. anonymous

so my y is on the outside??

81. anonymous

yes

82. anonymous

you cant simplify the bottom at all, and the top can be just a little bit

83. anonymous

what u mean

84. anonymous

im just saying the answer is the one i drew the reason is given in the post after that

85. anonymous

ok

86. anonymous

that wasn't correct

87. anonymous

is the 3 part of the root like the 7 is?

88. anonymous