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KE8717504
 2 years ago
Solve the following formula for the specified variable.
C=1/4h(s+k) solve for s???
KE8717504
 2 years ago
Solve the following formula for the specified variable. C=1/4h(s+k) solve for s???

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etemplin
 2 years ago
Best ResponseYou've already chosen the best response.0if this was a normal equation, and all those variables were numbers, how would you solve for s? hint: try to get s by itself

KE8717504
 2 years ago
Best ResponseYou've already chosen the best response.0It's been so long since i actually did this type of problem

etemplin
 2 years ago
Best ResponseYou've already chosen the best response.0i also have a question about the original question is it C=(1/4)h(s+k) or C=1/(4h(s+k))

KE8717504
 2 years ago
Best ResponseYou've already chosen the best response.0it's the first one that you put on there

etemplin
 2 years ago
Best ResponseYou've already chosen the best response.0the first and easiest thing to get rid of is the 1/4 if we want to rewrite the equation, we could like this: c=(h(s+k))/4 since we are dividing by 4 on the right, we can multiply both sides by 4 to get closer to having s by itself (by moving the 4 over) we get: 4c=h(s+k) now, to get rid of that h notice its being multiplied by the quantity inside the parenthesis to move it to the other side, we need to divide both sides by h (4c)/h=s+k finally, subtract k from both sides to get your answer

KE8717504
 2 years ago
Best ResponseYou've already chosen the best response.0ok so when i solved that i got 4c/hk

etemplin
 2 years ago
Best ResponseYou've already chosen the best response.0you should get 4c=h(s+k)

KE8717504
 2 years ago
Best ResponseYou've already chosen the best response.0That's what you got as the answer??

etemplin
 2 years ago
Best ResponseYou've already chosen the best response.0now, divide both sides by h

KE8717504
 2 years ago
Best ResponseYou've already chosen the best response.0so the h on the one side would cancel and just leave me with s+k but i don't know what i would get on the other side

KE8717504
 2 years ago
Best ResponseYou've already chosen the best response.0so my answr is going to be 4c/h=s +k??

etemplin
 2 years ago
Best ResponseYou've already chosen the best response.0you have to get s by itself subtract k from both sides

KE8717504
 2 years ago
Best ResponseYou've already chosen the best response.0I thought that I just subracted something

etemplin
 2 years ago
Best ResponseYou've already chosen the best response.0it says solve for s that means you have to get s by itself

etemplin
 2 years ago
Best ResponseYou've already chosen the best response.0think of it this way if you have s+k and you want to get s by itself, wouldnt it be necessary to subtract k s+kk=s

etemplin
 2 years ago
Best ResponseYou've already chosen the best response.0since you subtracted k from one side, you MUST subtract it from the other

KE8717504
 2 years ago
Best ResponseYou've already chosen the best response.0ok im just confused on what im going to get i thought what i typed a minute ago was my answr

etemplin
 2 years ago
Best ResponseYou've already chosen the best response.0your answer is going to have s by itself on one side and a whole bunch of stuff on the other after you subtract k from both sides, the final answer is s=((4c)/h)k

KE8717504
 2 years ago
Best ResponseYou've already chosen the best response.0I thought that is what i put a minute ago

etemplin
 2 years ago
Best ResponseYou've already chosen the best response.0it was not. you hadnt subtracted k yet

KE8717504
 2 years ago
Best ResponseYou've already chosen the best response.0Ok well i got that one wrong because the C was not capital

KE8717504
 2 years ago
Best ResponseYou've already chosen the best response.0I've got this stuff due tommorrow and im still not doen after this

KE8717504
 2 years ago
Best ResponseYou've already chosen the best response.0its ok. r u working it or something

etemplin
 2 years ago
Best ResponseYou've already chosen the best response.0for this one, you can follow the exact same steps as the first one. Multiply both sides by 2 to get rid of the 1/2 divide both sides by f subtract k from both sides what do you get?

KE8717504
 2 years ago
Best ResponseYou've already chosen the best response.0i even wrote the wrong problem

KE8717504
 2 years ago
Best ResponseYou've already chosen the best response.0And I'm solving for r

KE8717504
 2 years ago
Best ResponseYou've already chosen the best response.0i got 2c/fk but that's not right

etemplin
 2 years ago
Best ResponseYou've already chosen the best response.0where did you get a c theres no c in b=1/2f(r+k)

KE8717504
 2 years ago
Best ResponseYou've already chosen the best response.0i got that one may i ask another onee

KE8717504
 2 years ago
Best ResponseYou've already chosen the best response.0dw:1351649553338:dw

etemplin
 2 years ago
Best ResponseYou've already chosen the best response.0ok start by simplifying sqrt((xy)^2)=xy yes?

KE8717504
 2 years ago
Best ResponseYou've already chosen the best response.0I guess i don't know lol

etemplin
 2 years ago
Best ResponseYou've already chosen the best response.0it is. trust me anyway, on the top, you can simplify sqrt(x^5y^9) to sqrt(x^4y^8)*sqrt(xy) sqrt(x^4y^8)=x^2*y^4 so 7x^2y^4*sqrt(xy)  3xy one x and 1 y on the top and bottom cancel answer: (7xy^3*sqrt(xy))/3

KE8717504
 2 years ago
Best ResponseYou've already chosen the best response.0can u draw that for me because it's hard for me to read and understand it

KE8717504
 2 years ago
Best ResponseYou've already chosen the best response.0is that 3 suppose to be with the root?

etemplin
 2 years ago
Best ResponseYou've already chosen the best response.0were the original numbers with the root or were they outside?

KE8717504
 2 years ago
Best ResponseYou've already chosen the best response.0because i put it with the y and it said it was wrong.

KE8717504
 2 years ago
Best ResponseYou've already chosen the best response.0they were on the outside of the root but they were part of the root

etemplin
 2 years ago
Best ResponseYou've already chosen the best response.0were the original numbers (the 3 and 7) with the root or in front of it?

KE8717504
 2 years ago
Best ResponseYou've already chosen the best response.0dw:1351650274050:dw

etemplin
 2 years ago
Best ResponseYou've already chosen the best response.0that changes the answer then i assumed they were not part of the root; i assumed they were multiplied by it my mistake

etemplin
 2 years ago
Best ResponseYou've already chosen the best response.0\[\sqrt[7]{x ^{5}y ^{9}} or 7\sqrt{x ^{5}y ^{9}}\]

etemplin
 2 years ago
Best ResponseYou've already chosen the best response.0yea. when i solved it the first time i did it like the 2nd choice the new answer isdw:1351650440270:dw

KE8717504
 2 years ago
Best ResponseYou've already chosen the best response.0so my y is on the outside??

etemplin
 2 years ago
Best ResponseYou've already chosen the best response.0you cant simplify the bottom at all, and the top can be just a little bit

etemplin
 2 years ago
Best ResponseYou've already chosen the best response.0im just saying the answer is the one i drew the reason is given in the post after that

etemplin
 2 years ago
Best ResponseYou've already chosen the best response.0is the 3 part of the root like the 7 is?

etemplin
 2 years ago
Best ResponseYou've already chosen the best response.0another answer is dw:1351651467504:dw

etemplin
 2 years ago
Best ResponseYou've already chosen the best response.0i apologize for any incorrect answers
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