A community for students.
Here's the question you clicked on:
 0 viewing
anonymous
 4 years ago
Solve the following formula for the specified variable.
C=1/4h(s+k) solve for s???
anonymous
 4 years ago
Solve the following formula for the specified variable. C=1/4h(s+k) solve for s???

This Question is Closed

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0if this was a normal equation, and all those variables were numbers, how would you solve for s? hint: try to get s by itself

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0It's been so long since i actually did this type of problem

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0i also have a question about the original question is it C=(1/4)h(s+k) or C=1/(4h(s+k))

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0it's the first one that you put on there

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0the first and easiest thing to get rid of is the 1/4 if we want to rewrite the equation, we could like this: c=(h(s+k))/4 since we are dividing by 4 on the right, we can multiply both sides by 4 to get closer to having s by itself (by moving the 4 over) we get: 4c=h(s+k) now, to get rid of that h notice its being multiplied by the quantity inside the parenthesis to move it to the other side, we need to divide both sides by h (4c)/h=s+k finally, subtract k from both sides to get your answer

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0dw:1351648217904:dw

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0dw:1351648246343:dw

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0ok so when i solved that i got 4c/hk

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0you should get 4c=h(s+k)

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0That's what you got as the answer??

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0now, divide both sides by h

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0so the h on the one side would cancel and just leave me with s+k but i don't know what i would get on the other side

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0so my answr is going to be 4c/h=s +k??

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0you have to get s by itself subtract k from both sides

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0I thought that I just subracted something

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0it says solve for s that means you have to get s by itself

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0think of it this way if you have s+k and you want to get s by itself, wouldnt it be necessary to subtract k s+kk=s

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0since you subtracted k from one side, you MUST subtract it from the other

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0ok im just confused on what im going to get i thought what i typed a minute ago was my answr

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0your answer is going to have s by itself on one side and a whole bunch of stuff on the other after you subtract k from both sides, the final answer is s=((4c)/h)k

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0I thought that is what i put a minute ago

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0it was not. you hadnt subtracted k yet

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Ok well i got that one wrong because the C was not capital

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0I've got this stuff due tommorrow and im still not doen after this

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0its ok. r u working it or something

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0for this one, you can follow the exact same steps as the first one. Multiply both sides by 2 to get rid of the 1/2 divide both sides by f subtract k from both sides what do you get?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0i even wrote the wrong problem

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0And I'm solving for r

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0i got 2c/fk but that's not right

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0where did you get a c theres no c in b=1/2f(r+k)

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0i got that one may i ask another onee

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0dw:1351649553338:dw

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0ok start by simplifying sqrt((xy)^2)=xy yes?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0I guess i don't know lol

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0it is. trust me anyway, on the top, you can simplify sqrt(x^5y^9) to sqrt(x^4y^8)*sqrt(xy) sqrt(x^4y^8)=x^2*y^4 so 7x^2y^4*sqrt(xy)  3xy one x and 1 y on the top and bottom cancel answer: (7xy^3*sqrt(xy))/3

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0dw:1351649829505:dw

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0can u draw that for me because it's hard for me to read and understand it

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0is that 3 suppose to be with the root?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0were the original numbers with the root or were they outside?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0because i put it with the y and it said it was wrong.

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0they were on the outside of the root but they were part of the root

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0were the original numbers (the 3 and 7) with the root or in front of it?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0dw:1351650274050:dw

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0that changes the answer then i assumed they were not part of the root; i assumed they were multiplied by it my mistake

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0\[\sqrt[7]{x ^{5}y ^{9}} or 7\sqrt{x ^{5}y ^{9}}\]

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0yea. when i solved it the first time i did it like the 2nd choice the new answer isdw:1351650440270:dw

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0so my y is on the outside??

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0you cant simplify the bottom at all, and the top can be just a little bit

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0im just saying the answer is the one i drew the reason is given in the post after that

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0is the 3 part of the root like the 7 is?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0another answer is dw:1351651467504:dw

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0i apologize for any incorrect answers
Ask your own question
Sign UpFind more explanations on OpenStudy
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.