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monroe17
Group Title
Find an equation of the tangent line to the curve at the point.
x^2+xy+y^2=7
(2,1)
please show steps! I need to learn how to do it
 one year ago
 one year ago
monroe17 Group Title
Find an equation of the tangent line to the curve at the point. x^2+xy+y^2=7 (2,1) please show steps! I need to learn how to do it
 one year ago
 one year ago

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ChmE Group TitleBest ResponseYou've already chosen the best response.0
Have you been taught derivatives
 one year ago

monroe17 Group TitleBest ResponseYou've already chosen the best response.0
yes, but tomorrow I have an exam on a bunch of stuf and im sooooooo lost!!! I'm just trying to learn it all because I don't understand my professor at all.
 one year ago

ChmE Group TitleBest ResponseYou've already chosen the best response.0
okay lets start with this problem. Every time you take the derivative of a y we need to add y'. Ex) the derivative of 2y^2=6 is 4yy'=0, then you solve for y' We will do the same above. Let's work one term at a time. What is the derivative of x^2?
 one year ago

timo86m Group TitleBest ResponseYou've already chosen the best response.1
Do implicit differentiation in this one i suppose. do it for both y and x
 one year ago

monroe17 Group TitleBest ResponseYou've already chosen the best response.0
thats the prob idk how
 one year ago

timo86m Group TitleBest ResponseYou've already chosen the best response.1
\[{\frac {x+2\,y}{2\,x+y}}\]
 one year ago

timo86m Group TitleBest ResponseYou've already chosen the best response.1
http://www.khanacademy.org/math/calculus/differentialcalculus/v/implicitdifferentiation this could help
 one year ago

timo86m Group TitleBest ResponseYou've already chosen the best response.1
http://www.khanacademy.org/math/calculus/differentialcalculus/v/implicitdifferentiationpart2 part 2 is nice too
 one year ago

timo86m Group TitleBest ResponseYou've already chosen the best response.1
well when y is dependant variable (2*x+y)/(x+2*y)
 one year ago

timo86m Group TitleBest ResponseYou've already chosen the best response.1
at 2,1 the slope is 5  4
 one year ago

monroe17 Group TitleBest ResponseYou've already chosen the best response.0
I figure it out. But, now I'm stuck on the next problem
 one year ago

timo86m Group TitleBest ResponseYou've already chosen the best response.1
use y=mx+b 1=5/4*2+b sfb
 one year ago

timo86m Group TitleBest ResponseYou've already chosen the best response.1
b=7/2 so y=5/4*x+ 7/2 :)
 one year ago

timo86m Group TitleBest ResponseYou've already chosen the best response.1
BTW I graphed it and it works fine both the tangent line and the function yyou gave me do you wanna see it?
 one year ago

monroe17 Group TitleBest ResponseYou've already chosen the best response.0
yeah i already figured it out
 one year ago
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