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monroe17
Find an equation of the tangent line to the curve at the point. x^2+xy+y^2=7 (2,1) please show steps! I need to learn how to do it
Have you been taught derivatives
yes, but tomorrow I have an exam on a bunch of stuf and im sooooooo lost!!! I'm just trying to learn it all because I don't understand my professor at all.
okay lets start with this problem. Every time you take the derivative of a y we need to add y'. Ex) the derivative of 2y^2=6 is 4yy'=0, then you solve for y' We will do the same above. Let's work one term at a time. What is the derivative of x^2?
Do implicit differentiation in this one i suppose. do it for both y and x
thats the prob idk how
\[-{\frac {x+2\,y}{2\,x+y}}\]
http://www.khanacademy.org/math/calculus/differential-calculus/v/implicit-differentiation this could help
http://www.khanacademy.org/math/calculus/differential-calculus/v/implicit-differentiation--part-2 part 2 is nice too
well when y is dependant variable -(2*x+y)/(x+2*y)
at 2,1 the slope is -5 -- 4
I figure it out. But, now I'm stuck on the next problem
use y=mx+b 1=-5/4*2+b sfb
b=7/2 so y=-5/4*x+ 7/2 :)
BTW I graphed it and it works fine both the tangent line and the function yyou gave me do you wanna see it?
yeah i already figured it out