anonymous
  • anonymous
The equation of motion is \(\ s=2costy+3sint, t\le0 \). Find velocity/acceleration at time t. I took the derivative to find the velocity, but got 0...?
Calculus1
  • Stacey Warren - Expert brainly.com
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SOLVED
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katieb
  • katieb
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anonymous
  • anonymous
is that 2cos(ty) ?
anonymous
  • anonymous
Good catch! That's supposed to be a t only.
anonymous
  • anonymous
so \[s=2\cos(y) + 3\sin(t) , t \le0\] ?

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anonymous
  • anonymous
Oops cos(t)
anonymous
  • anonymous
Well the velocity at time t is just the derivative. Can you differentiate that?
anonymous
  • anonymous
@Dido525 I tried, but I got 0, which doesn't seem correct.
anonymous
  • anonymous
Lets see:|dw:1351660147750:dw|
zepdrix
  • zepdrix
Oh that was a 2? :P sorry..
anonymous
  • anonymous
@zepdrix yup
anonymous
  • anonymous
so Plug in your value for t and you have your answer :P .
anonymous
  • anonymous
Would I add the derivates of each here? What happens to the constants?
anonymous
  • anonymous
I just did the derivative for you O_o .
anonymous
  • anonymous
I suppose I was confused by the constants...
anonymous
  • anonymous
Ohh. If you have constants out in from you take out the constant, take the derivative of the function and multiply the constant back in.
anonymous
  • anonymous
Ohh.Okay. I was getting the product rule confused with the addition one. So for the acceleration, I take the derivative of the derivative?
anonymous
  • anonymous
Yep!
anonymous
  • anonymous
Okay!! Thanks so much!!!
anonymous
  • anonymous
Welcome :) .

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