Got Homework?
Connect with other students for help. It's a free community.
Here's the question you clicked on:
 0 viewing
The equation of motion is \(\ s=2costy+3sint, t\le0 \). Find velocity/acceleration at time t. I took the derivative to find the velocity, but got 0...?
 one year ago
 one year ago
The equation of motion is \(\ s=2costy+3sint, t\le0 \). Find velocity/acceleration at time t. I took the derivative to find the velocity, but got 0...?
 one year ago
 one year ago

This Question is Closed

Study23Best ResponseYou've already chosen the best response.0
Good catch! That's supposed to be a t only.
 one year ago

Dido525Best ResponseYou've already chosen the best response.3
so \[s=2\cos(y) + 3\sin(t) , t \le0\] ?
 one year ago

Dido525Best ResponseYou've already chosen the best response.3
Well the velocity at time t is just the derivative. Can you differentiate that?
 one year ago

Study23Best ResponseYou've already chosen the best response.0
@Dido525 I tried, but I got 0, which doesn't seem correct.
 one year ago

Dido525Best ResponseYou've already chosen the best response.3
Lets see:dw:1351660147750:dw
 one year ago

zepdrixBest ResponseYou've already chosen the best response.0
Oh that was a 2? :P sorry..
 one year ago

Dido525Best ResponseYou've already chosen the best response.3
so Plug in your value for t and you have your answer :P .
 one year ago

Study23Best ResponseYou've already chosen the best response.0
Would I add the derivates of each here? What happens to the constants?
 one year ago

Dido525Best ResponseYou've already chosen the best response.3
I just did the derivative for you O_o .
 one year ago

Study23Best ResponseYou've already chosen the best response.0
I suppose I was confused by the constants...
 one year ago

Dido525Best ResponseYou've already chosen the best response.3
Ohh. If you have constants out in from you take out the constant, take the derivative of the function and multiply the constant back in.
 one year ago

Study23Best ResponseYou've already chosen the best response.0
Ohh.Okay. I was getting the product rule confused with the addition one. So for the acceleration, I take the derivative of the derivative?
 one year ago

Study23Best ResponseYou've already chosen the best response.0
Okay!! Thanks so much!!!
 one year ago
See more questions >>>
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.