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Study23 Group Title

The equation of motion is \(\ s=2costy+3sint, t\le0 \). Find velocity/acceleration at time t. I took the derivative to find the velocity, but got 0...?

  • one year ago
  • one year ago

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  1. Dido525 Group Title
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    is that 2cos(ty) ?

    • one year ago
  2. Study23 Group Title
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    Good catch! That's supposed to be a t only.

    • one year ago
  3. Dido525 Group Title
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    so \[s=2\cos(y) + 3\sin(t) , t \le0\] ?

    • one year ago
  4. Dido525 Group Title
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    Oops cos(t)

    • one year ago
  5. Dido525 Group Title
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    Well the velocity at time t is just the derivative. Can you differentiate that?

    • one year ago
  6. Study23 Group Title
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    @Dido525 I tried, but I got 0, which doesn't seem correct.

    • one year ago
  7. Dido525 Group Title
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    Lets see:|dw:1351660147750:dw|

    • one year ago
  8. zepdrix Group Title
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    Oh that was a 2? :P sorry..

    • one year ago
  9. Study23 Group Title
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    @zepdrix yup

    • one year ago
  10. Dido525 Group Title
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    so Plug in your value for t and you have your answer :P .

    • one year ago
  11. Study23 Group Title
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    Would I add the derivates of each here? What happens to the constants?

    • one year ago
  12. Dido525 Group Title
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    I just did the derivative for you O_o .

    • one year ago
  13. Study23 Group Title
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    I suppose I was confused by the constants...

    • one year ago
  14. Dido525 Group Title
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    Ohh. If you have constants out in from you take out the constant, take the derivative of the function and multiply the constant back in.

    • one year ago
  15. Study23 Group Title
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    Ohh.Okay. I was getting the product rule confused with the addition one. So for the acceleration, I take the derivative of the derivative?

    • one year ago
  16. Dido525 Group Title
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    Yep!

    • one year ago
  17. Study23 Group Title
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    Okay!! Thanks so much!!!

    • one year ago
  18. Dido525 Group Title
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    Welcome :) .

    • one year ago
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