Study23
The equation of motion is \(\ s=2costy+3sint, t\le0 \). Find velocity/acceleration at time t. I took the derivative to find the velocity, but got 0...?
Delete
Share
This Question is Closed
Dido525
Best Response
You've already chosen the best response.
3
is that 2cos(ty) ?
Study23
Best Response
You've already chosen the best response.
0
Good catch! That's supposed to be a t only.
Dido525
Best Response
You've already chosen the best response.
3
so \[s=2\cos(y) + 3\sin(t) , t \le0\] ?
Dido525
Best Response
You've already chosen the best response.
3
Oops cos(t)
Dido525
Best Response
You've already chosen the best response.
3
Well the velocity at time t is just the derivative. Can you differentiate that?
Study23
Best Response
You've already chosen the best response.
0
@Dido525 I tried, but I got 0, which doesn't seem correct.
Dido525
Best Response
You've already chosen the best response.
3
Lets see:|dw:1351660147750:dw|
zepdrix
Best Response
You've already chosen the best response.
0
Oh that was a 2? :P sorry..
Study23
Best Response
You've already chosen the best response.
0
@zepdrix yup
Dido525
Best Response
You've already chosen the best response.
3
so Plug in your value for t and you have your answer :P .
Study23
Best Response
You've already chosen the best response.
0
Would I add the derivates of each here? What happens to the constants?
Dido525
Best Response
You've already chosen the best response.
3
I just did the derivative for you O_o .
Study23
Best Response
You've already chosen the best response.
0
I suppose I was confused by the constants...
Dido525
Best Response
You've already chosen the best response.
3
Ohh. If you have constants out in from you take out the constant, take the derivative of the function and multiply the constant back in.
Study23
Best Response
You've already chosen the best response.
0
Ohh.Okay. I was getting the product rule confused with the addition one. So for the acceleration, I take the derivative of the derivative?
Dido525
Best Response
You've already chosen the best response.
3
Yep!
Study23
Best Response
You've already chosen the best response.
0
Okay!! Thanks so much!!!
Dido525
Best Response
You've already chosen the best response.
3
Welcome :) .