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The equation of motion is \(\ s=2costy+3sint, t\le0 \). Find velocity/acceleration at time t. I took the derivative to find the velocity, but got 0...?

Calculus1
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is that 2cos(ty) ?
Good catch! That's supposed to be a t only.
so \[s=2\cos(y) + 3\sin(t) , t \le0\] ?

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Other answers:

Oops cos(t)
Well the velocity at time t is just the derivative. Can you differentiate that?
@Dido525 I tried, but I got 0, which doesn't seem correct.
Lets see:|dw:1351660147750:dw|
Oh that was a 2? :P sorry..
so Plug in your value for t and you have your answer :P .
Would I add the derivates of each here? What happens to the constants?
I just did the derivative for you O_o .
I suppose I was confused by the constants...
Ohh. If you have constants out in from you take out the constant, take the derivative of the function and multiply the constant back in.
Ohh.Okay. I was getting the product rule confused with the addition one. So for the acceleration, I take the derivative of the derivative?
Yep!
Okay!! Thanks so much!!!
Welcome :) .

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