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hunterhoff
Group Title
Create your own twostep equation with All Real Numbers as the solution. Show the steps to solving the equation to prove the solution All Real Numbers.
My answer is:
2(x + 3) = 2(x + 1)  4
2x6 =2x24
2x6=2x6
2x=2x
x=2x/2
Is this right?
 2 years ago
 2 years ago
hunterhoff Group Title
Create your own twostep equation with All Real Numbers as the solution. Show the steps to solving the equation to prove the solution All Real Numbers. My answer is: 2(x + 3) = 2(x + 1)  4 2x6 =2x24 2x6=2x6 2x=2x x=2x/2 Is this right?
 2 years ago
 2 years ago

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UmmmHELP Group TitleBest ResponseYou've already chosen the best response.0
I think...
 2 years ago

UmmmHELP Group TitleBest ResponseYou've already chosen the best response.0
are there other options or just that one?
 2 years ago

hunterhoff Group TitleBest ResponseYou've already chosen the best response.0
There were no options, I had to come up with one
 2 years ago

Study23 Group TitleBest ResponseYou've already chosen the best response.0
Well, this problem is a case in which \(\ \Huge x=All Real Numbers \).
 2 years ago

hunterhoff Group TitleBest ResponseYou've already chosen the best response.0
Lol so is it correct?
 2 years ago

UmmmHELP Group TitleBest ResponseYou've already chosen the best response.0
Yeah im not sure...sorry!
 2 years ago

Study23 Group TitleBest ResponseYou've already chosen the best response.0
One moment...
 2 years ago

Study23 Group TitleBest ResponseYou've already chosen the best response.0
So, what you have is mostly correct. dw:1351659038210:dw Because we have the same expressions on both sides of the equation sign, x could be any real number, and the equation would render true. Does that make sense?
 2 years ago

hunterhoff Group TitleBest ResponseYou've already chosen the best response.0
Umm I think so
 2 years ago

hunterhoff Group TitleBest ResponseYou've already chosen the best response.0
Would it meet my teachers approval?
 2 years ago

Study23 Group TitleBest ResponseYou've already chosen the best response.0
The correct answer then, for this problem, would be "All Real Numbers". Additionally, your question states prove that the solution to the eqn is all real numbers.
 2 years ago

hunterhoff Group TitleBest ResponseYou've already chosen the best response.0
Oh ok, thanks! :)
 2 years ago
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