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I'm having trouble finding out how I can move from 4/(sqrt(2)sqrt(6)) to sqrt(2)  sqrt(6). I really can't figure this out for the life of me, and I have no idea why.
 one year ago
 one year ago
I'm having trouble finding out how I can move from 4/(sqrt(2)sqrt(6)) to sqrt(2)  sqrt(6). I really can't figure this out for the life of me, and I have no idea why.
 one year ago
 one year ago

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hartnnBest ResponseYou've already chosen the best response.1
hint :multiply and divide by (sqrt(2)+sqrt(6)
 one year ago

SchrodingerBest ResponseYou've already chosen the best response.0
I tried that, but i'm getting just a batsh*t crazy mess when I try to do that. I'm assuming you're talking about multiplying the numerator and denominator by the numerator? I must be doing something wrong there.
 one year ago

hartnnBest ResponseYou've already chosen the best response.1
not with numerator, with denominator, but with middle sign reversed , (sqrt(2)+sqrt(6)
 one year ago

SchrodingerBest ResponseYou've already chosen the best response.0
Okay, that's cool, but how do you just know to do that?
 one year ago

hartnnBest ResponseYou've already chosen the best response.1
its called rationalizing the denominator, if there is \(\large a+\sqrt b\) in the denominator, u multiply and divide by \(\large a\sqrt b\)
 one year ago

hartnnBest ResponseYou've already chosen the best response.1
similar case when u want to rationalize the numerator.....
 one year ago

SchrodingerBest ResponseYou've already chosen the best response.0
Okay, cool. I've actually never seen that done before, at least formally, before. Thanks!
 one year ago

hartnnBest ResponseYou've already chosen the best response.1
try it out here, and tell me if u don't get it....
 one year ago

SchrodingerBest ResponseYou've already chosen the best response.0
\[\frac{4}{\sqrt{2}\sqrt{6}}\]... \[\frac{ 4 }{\sqrt{2}\sqrt{6}} * \frac{ \sqrt{2}+\sqrt{6} }{ \sqrt{2}+\sqrt{6} }\]... \[\frac{ 4\sqrt{2}+4\sqrt{6} }{ 2+\sqrt{12}\sqrt{12}6 }\]... \[\frac{ 4\sqrt{2}+4\sqrt{6} }{ 2  6 }\]... \[\frac{ 4\sqrt{2}+4\sqrt{6} }{ 4 }\]... \[\sqrt{2}\sqrt{6}\] Correct?
 one year ago

hartnnBest ResponseYou've already chosen the best response.1
absolutely ! good work :)
 one year ago

SchrodingerBest ResponseYou've already chosen the best response.0
Thanks. I'm pretty worried/bothered at the fact that I was never formally taught that concept in middle or high school. My teachers were the type to kind of go, "Oh well you just put this here and do that and then hooray!" without giving a concrete or logically consistent approach to how to simplify or solve certain things. It's like it was assumed that I understood. Man, public school isn't exactly wonderful.
 one year ago

hartnnBest ResponseYou've already chosen the best response.1
don't worry, whatever u can't understand, ask here, we'll try our best to make u understand :)
 one year ago
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