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Schrodinger
 3 years ago
I'm having trouble finding out how I can move from 4/(sqrt(2)sqrt(6)) to sqrt(2)  sqrt(6). I really can't figure this out for the life of me, and I have no idea why.
Schrodinger
 3 years ago
I'm having trouble finding out how I can move from 4/(sqrt(2)sqrt(6)) to sqrt(2)  sqrt(6). I really can't figure this out for the life of me, and I have no idea why.

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hartnn
 3 years ago
Best ResponseYou've already chosen the best response.1hint :multiply and divide by (sqrt(2)+sqrt(6)

Schrodinger
 3 years ago
Best ResponseYou've already chosen the best response.0I tried that, but i'm getting just a batsh*t crazy mess when I try to do that. I'm assuming you're talking about multiplying the numerator and denominator by the numerator? I must be doing something wrong there.

hartnn
 3 years ago
Best ResponseYou've already chosen the best response.1not with numerator, with denominator, but with middle sign reversed , (sqrt(2)+sqrt(6)

Schrodinger
 3 years ago
Best ResponseYou've already chosen the best response.0Okay, that's cool, but how do you just know to do that?

hartnn
 3 years ago
Best ResponseYou've already chosen the best response.1its called rationalizing the denominator, if there is \(\large a+\sqrt b\) in the denominator, u multiply and divide by \(\large a\sqrt b\)

hartnn
 3 years ago
Best ResponseYou've already chosen the best response.1similar case when u want to rationalize the numerator.....

Schrodinger
 3 years ago
Best ResponseYou've already chosen the best response.0Okay, cool. I've actually never seen that done before, at least formally, before. Thanks!

hartnn
 3 years ago
Best ResponseYou've already chosen the best response.1try it out here, and tell me if u don't get it....

Schrodinger
 3 years ago
Best ResponseYou've already chosen the best response.0\[\frac{4}{\sqrt{2}\sqrt{6}}\]... \[\frac{ 4 }{\sqrt{2}\sqrt{6}} * \frac{ \sqrt{2}+\sqrt{6} }{ \sqrt{2}+\sqrt{6} }\]... \[\frac{ 4\sqrt{2}+4\sqrt{6} }{ 2+\sqrt{12}\sqrt{12}6 }\]... \[\frac{ 4\sqrt{2}+4\sqrt{6} }{ 2  6 }\]... \[\frac{ 4\sqrt{2}+4\sqrt{6} }{ 4 }\]... \[\sqrt{2}\sqrt{6}\] Correct?

hartnn
 3 years ago
Best ResponseYou've already chosen the best response.1absolutely ! good work :)

Schrodinger
 3 years ago
Best ResponseYou've already chosen the best response.0Thanks. I'm pretty worried/bothered at the fact that I was never formally taught that concept in middle or high school. My teachers were the type to kind of go, "Oh well you just put this here and do that and then hooray!" without giving a concrete or logically consistent approach to how to simplify or solve certain things. It's like it was assumed that I understood. Man, public school isn't exactly wonderful.

hartnn
 3 years ago
Best ResponseYou've already chosen the best response.1don't worry, whatever u can't understand, ask here, we'll try our best to make u understand :)
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