anonymous
  • anonymous
A block with mass m1 = 8.6 kg is on an incline with an angle θ = 35.0° with respect to the horizontal. The coefficients of friction are: μk = 0.32 and μs = 0.352. Now a new block with mass m2 = 16.9 kg is attached to the first block. The new block is made of a different material and has a greater coefficient of static friction. What minimum value for the coefficient of static friction is needed between the new block and the plane to keep the system from accelerating?
Physics
  • Stacey Warren - Expert brainly.com
Hey! We 've verified this expert answer for you, click below to unlock the details :)
SOLVED
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.
chestercat
  • chestercat
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
anonymous
  • anonymous
anonymous
  • anonymous
Something is just wrong with my free-body diagram. I keep getting the wrong answer. I'm suck somewhere, I just don't know which step at this point. :-(
anonymous
  • anonymous
*stuck... lol

Looking for something else?

Not the answer you are looking for? Search for more explanations.

More answers

anonymous
  • anonymous
|dw:1351678973651:dw|
anonymous
  • anonymous
where N1 = m1 g cos theta, and N2 = m2 g cos theta
anonymous
  • anonymous
@brinethery
anonymous
  • anonymous
Thank you very much. I just woke up and am trying to resurrect with coffee. I will go over the problem later on and see if I come up with the right answer :-). I appreciate your help.

Looking for something else?

Not the answer you are looking for? Search for more explanations.